TCHAR* and LPTSTR

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kelprinc wrote:

p->shi502_netname ="test";

_tcscpy(p->shi502_netname, _T("test")); I think you should copy _T("test") to "p->shi502_netname". Now it should work.

Jesus Loves:rose:

--Owner Drawn:rose: --Nothing special --Defeat is temporary but surrender is permanent --Never say quits --Jesus is Lord:rose:

kelprinc

It did not work I think i shld rephrase my question. I want to access the string being pointed to by shi502_netname i.e if i just type cout<shi502_netname<

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kelprinc wrote:

TCHAR * shi502_netname = _T("test"); LPTSTR h = shi502_netname ; TCHAR* var = h; cout< Here this is printing fine. What is this p->shi502_netname. Is this a pointer to a char or a single char.

Jesus Loves:rose:

--Owner Drawn:rose: --Nothing special --Defeat is temporary but surrender is permanent --Never say quits --Jesus is Lord:rose:

kelprinc

We are on totally different wave lengths. Forget about the first part. Assume you have a struct p that has shi502_netname as its member. shi502_netname is of type LPTSTR. now i want to print the LPTSTR string in the p struct. I tried doing this p->shi502_netname, but all i get is the first letter of the string Kelvin Chikomo

Owner drawn

I also declared a struct and put a member inside with the same name and it's still working.

struct
{
LPTSTR shi502_netname;
}p;

p.shi502_netname = _T("test");
LPTSTR h = p.shi502_netname ;
TCHAR* var = h;
cout<

Here is the code. It's working.:^)

Jesus Loves:rose:

--Owner Drawn:rose:
--Nothing special
--Defeat is temporary but surrender is permanent
--Never say quits
--Jesus is Lord:rose:

kelprinc

I have edited the struct, its not a normal struct (typedef) typedef struct { LPTSTR shi502_netname; }p; p.shi502_netname = _T("test"); LPTSTR h = p.shi502_netname ; TCHAR* var = h;cout<

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typedef struct
{
LPTSTR shi502_netname;
}p;

Did you declare a variable of type p.

p p1; //don't forget this
p1.shi502_netname = _T("test");
LPTSTR h = p1.shi502_netname ;
TCHAR* var = h;
cout<
It still works fine.

Jesus Loves:rose:

--Owner Drawn:rose:
--Nothing special
--Defeat is temporary but surrender is permanent
--Never say quits
--Jesus is Lord:rose:

kelprinc

Yes i do. you did not declare yours as *p look at my definition of my struct below typedef struct { LPTSTR shi502_netname; }*p; p p1; //don't forget thisp1.shi502_netname = _T("test");LPTSTR h = p1.shi502_netname ;TCHAR* var = h;cout<

Owner drawn

Aha here is the problem...

typedef struct
{
LPTSTR shi502_netname;
} ap,*p;

ap a;
p p1 = &a;
p1->shi502_netname = _T("test");
LPTSTR h = p1->shi502_netname ;
TCHAR* var = h;
cout<

It works with the modifications that I made. You have to make another typedef along with *p i.e ap. If you don't what are you going to assign to a variable of type p. p needs an address of a struct of it's own type.

An advice: Please provide some meaningful names for variables and specially typedefs.

Jesus Loves:rose:

--Owner Drawn:rose:
--Nothing special
--Defeat is temporary but surrender is permanent
--Never say quits
--Jesus is Lord:rose:

kelprinc

I tried it it did not work the struct that iam using is part of the C++ libraries here it is typedef struct _SHARE_INFO_502 { LPTSTR shi502_netname; DWORD shi502_type; LPTSTR shi502_remark; DWORD shi502_permissions; DWORD shi502_max_uses; DWORD shi502_current_uses; LPTSTR shi502_path; LPTSTR shi502_passwd; DWORD shi502_reserved; PSECURITY_DESCRIPTOR shi502_security_descriptor; } SHARE_INFO_502, *PSHARE_INFO_502, *LPSHARE_INFO_502; And i have to use *PSHARE_INFO_502 as the name of the struct Kelvin Chikomo

Owner drawn

Go ahead it will work. PSHARE_INFO_502 should take the address of a valid structure of the same type. Then it has to work. Probably like this: SHARE_INFO_502 shInfo; PSHARE_INFO_502 pShInfo = &shInfo; Now use pShInfo as you should.

Jesus Loves:rose:

--Owner Drawn:rose: --Nothing special --Defeat is temporary but surrender is permanent --Never say quits --Jesus is Lord:rose:

kakan

This maybe is a stupid question but I have to ask: Are your program using UNICODE? In that case, it's perfectly understandable: The console doesn't want UNICODE, so when your 't' is written to the consol, the console sees a 't', followed by a \0. And since \0 is a string terminator, the output is terminated. Could this be the case here?

kelprinc

Yes i am programing in unicode. So what shld i do Kelvin Chikomo

kelprinc

I get wrong out puts if i try this. let me just give you part of my code PSHARE_INFO_502 BufPtr,p; //SHARE_INFO_502 shInfo; //PSHARE_INFO_502 pShInfo = &shInfo; NET_API_STATUS res; LPTSTR lpszServer = NULL; DWORD er=0,tr=0,resume=0, i; //declare server variable lpszServer = lpszArgv[1]; cout<shi502_netname; cout<

kakan

Make sure your console output is in plain ANSI

kelprinc

I am not printing any thing to the console as yet. You can look at the above threads to see my code. Kelvin Chikomo

David Crow

kelprinc wrote:

I am not printing any thing to the console as yet.

Sure you are. What do you think cout is for?

"The words of God are not like the oak leaf which dies and falls to the earth, but like the pine tree which stays green forever." - Native American Proverb

kelprinc

I am now trying to use the W2A conversion but im realy doubting it Kelvin Chikomo

David Crow

You need to use wcout instead of cout.

"The words of God are not like the oak leaf which dies and falls to the earth, but like the pine tree which stays green forever." - Native American Proverb

Prakash Nadar

if you are using unicode build then you should use unicode set of apis to work on them. If you really need to work on multibyte string then you may have to use WideCharToMultiByte api to do the convertion.

-Prakash