Predifined macro (__FUNCTION__)

[hint_54]

I need to pass the macro __FUNCTION__ to a constructor (it's for error handling) but that macro will not work on any compiler. What I want to know is if there is a way of knowing if the macro is avaiable with pre-processor directives. Something like:

#ifdef SOMETHING
MyConstructor( int );
#else
MyConstructor( void );
#endif

Where SOMETHING is only defined if __FUNCTION__ is avaiable. Is this possible? If not, is there any other way? Thanks in advance hint_54

[David Crow]

hint_54 wrote:

...if __FUNCTION__ is avaiable.

Can't you just use:

#ifdef __FUNCTION__
...
#endif

---

"Let us be thankful for the fools. But for them the rest of us could not succeed." - Mark Twain

"There is no death, only a change of worlds." - Native American Proverb

[hint_54]

I dont know. I dont have the means to test it. My compiler (VS6) does not support the __FUNCTION__ macro. You think it will work? regards hint_54

[Michael Dunn]

__FUNCTION__ was added in VC7, so you can test for the existence of __FUNCTION__ by checking the value of _MSC_VER (the compiler version).

--Mike-- Visual C++ MVP :cool: LINKS~! Ericahist | NEW!! PimpFish | CP SearchBar v3.0 | C++ Forum FAQ

[hint_54]

What about the compilers that are not from microsoft? regards hint_54

[Michael Dunn]

I really have little knowledge of non-MS compilers these days. RTFM ;)

--Mike-- Visual C++ MVP :cool: LINKS~! Ericahist | NEW!! PimpFish | CP SearchBar v3.0 | C++ Forum FAQ

[hint_54]

true ;P hint_54