Is there any CInt function - VB in c++?

[Joy Anne]

Dear c++ friends, In VB we have, Dim MyDouble, MyInt MyDouble = 2345.5678 ' MyDouble is a Double. MyInt = CInt(MyDouble) ' MyInt contains 2346. Is there anything in c++ similar to CInt in VB? Thanks, Joy Anne

[Maxwell Chen]

Joy Anne wrote:

Dim MyDouble, MyInt MyDouble = 2345.5678 ' MyDouble is a Double. MyInt = CInt(MyDouble) ' MyInt contains 2346.

double myD = 2345.5678; int myI = (int)myD;

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Maxwell Chen

[Nibu babu thomas]

Faqs[^]

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Nibu thomas Software Developer Faqs by Michael dunn

[kiran janaswamy]

hi, use reinterpret_cast value; snippet of code. int x; double y = 5.66; now x = reinterpret_cast y; // cast double to int data type. this is type conversion in c++. good luck, uday. uday kiran -- modified at 0:57 Wednesday 10th May, 2006

[Hamid Taebi]

see here[^]

[Maxwell Chen]

I think he is trying to convert a double to int.

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Maxwell Chen

[Nibu babu thomas]

But still Faqs are worth a read. :)

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Nibu thomas Software Developer Faqs by Michael dunn

[csc]

Math.round public static int round( float a ) Returns the value of the argument rounded to the nearest int value. -------------------------- just do it like that : #include : double MyDouble = 2345.5678 // MyDouble is a Double. int MyInt = ROUND(MyDouble) // MyInt contains 2346. : double MyDouble = 2345.4678 // MyDouble is a Double. int MyInt = ROUND(MyDouble) // MyInt contains 2345.

[Maxwell Chen]

Nibu thomas wrote:

Faqs are worth a read

:-D

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Maxwell Chen

[Maxwell Chen]

csc wrote:

public static int round( float a )

Is this in C++ ? I mean that public modifier.

csc wrote:

int round( float a )

csc wrote:

ROUND(MyDouble)

Case sensitive?! :wtf: No ';' , it doesn't compile. :~

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Maxwell Chen

[Nibu babu thomas]

I can see that question coming! :-D

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Nibu thomas Software Developer Faqs by Michael dunn

[Maxwell Chen]

Nibu thomas wrote:

I can see that question coming!

The diviner ~~~ :laugh:

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Maxwell Chen

[Hamid Taebi]

yes maybe in next time,isnt possible!?

[Stephen Hewitt]

Basic maths will do the trick. Try this: double d = 2345.5678; int i = d + 0.5 Steve

[Stephen Hewitt]

You don't need to use reinterpret_cast in this case and in fact shouldn’t: casting from double to int is implicit so the following will do the trick: double d = 3.5; int i = d; // Ok, d=3 Is you wanted to make the cast explicit (and there is good reason to do so as it will suppress a warning) static_cast is the right cast for the job. i.e. double d = 3.5; int i = static_cast<int>(d); Part of the point of adding the function style casts was to make your intent specific thus it is important to use the right cast for the job. Steve

[Stephen Hewitt]

This will not round. You need something like this: double myD = 2345.5678; int myI = static_cast<int>(myD+0.5); Also note that I didn't use any C-style casts; they should never be used in C++ code. Steve

[Stephen Hewitt]

Which part did my 1-voter not like: The add 0.5 bit or the static_cast lecture? I stand by both of them but I believe that if you're going to down vote something in the programming forums it's good to reply and explain your objection. Steve

[Maxwell Chen]

I voted 5 to balance it... :-D It used to happen on myself also, when someone doesn't feel like to see the truth. :doh: That's also the reason I posted some reply titled "WTF ?!", remember?! :-D

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Maxwell Chen

[Maxwell Chen]

Stephen Hewitt wrote:

any C-style casts; they should never be used in C++ code.

Personally I guess that the 1-voter doesn't feel comfortable with the sentence above.

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Maxwell Chen

[Maxwell Chen]

So what's happening?! You guys like to vote 1 very much??

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Maxwell Chen