How to copy string with NULL
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char szSource[23] = {"Before\0After"}; char szDest[23]; ptr = memcpy(szDest,szSource,22); printf("%s %d",szDest,strlen(szDest));Hi, may i please request you to just try this code and comment on why memcpy is failing? Is it the way it goes or am I wrong somewhere? Can you suggest some workaround? Thanks for your time. :rose:Aljechin wrote:
Hi, may i please request you to just try this code and comment on why memcpy is failing? Is it the way it goes or am I wrong somewhere? Can you suggest some workaround? Thanks for your time.
Sure! Please look up
memcpyin MSDN. There is a working demo there. See you were saying thatszSourcecontainsNULLcharacters right? Sostrlenwon't work because it will return when it finds the first null character. Same withprintfand other functions. They all return when the firstNULLcharacter is found. So if your string is..."Nibu\0is a\0\0\0good\0boy\0".
strlenwill return4.printfwill print onlyNibu
Nibu thomas A Developer Programming tips[^] My site[^]
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char szSource[23] = {"Before\0After"}; char szDest[23]; ptr = memcpy(szDest,szSource,22); printf("%s %d",szDest,strlen(szDest));I went through that page, but not getting it. Can you show me a small code snippet of how do i copy that szSource into szDest? Sorry if a very elementary question. :rose:What are you trying to do exactly ? Is not because memcpy sucessfully copied the source into the destination that the '\0' character will be removed. It will still be present in the new string so as soon as you try to get its length or print the string, you will only have the begining of the string. This is totally logical.
Cédric Moonen Software developer
Charting control -
Aljechin wrote:
Hi, may i please request you to just try this code and comment on why memcpy is failing? Is it the way it goes or am I wrong somewhere? Can you suggest some workaround? Thanks for your time.
Sure! Please look up
memcpyin MSDN. There is a working demo there. See you were saying thatszSourcecontainsNULLcharacters right? Sostrlenwon't work because it will return when it finds the first null character. Same withprintfand other functions. They all return when the firstNULLcharacter is found. So if your string is..."Nibu\0is a\0\0\0good\0boy\0".
strlenwill return4.printfwill print onlyNibu
Nibu thomas A Developer Programming tips[^] My site[^]
Thank you so much. I will surely check that example and get back to you with the problem status. peace homie :rose:
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What are you trying to do exactly ? Is not because memcpy sucessfully copied the source into the destination that the '\0' character will be removed. It will still be present in the new string so as soon as you try to get its length or print the string, you will only have the begining of the string. This is totally logical.
Cédric Moonen Software developer
Charting controlWhat I am doing? PIP (Peripheral Interface Programming). I have generated a sequence of binary data which will be understood by a peripheral device. For example, we issue a print command from notepad. Its not the .txt file that is sent to the printer by the OS. But a series of printer-understood data is sent. My program generates such device-understandable data which could be just dumped into the port of the device and it will print some meaningful text or act accordingly. I have this binary (kinda junk) stored in unsigned char array. So, I am trying to figure out a way to do this. :) :rose:
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What I am doing? PIP (Peripheral Interface Programming). I have generated a sequence of binary data which will be understood by a peripheral device. For example, we issue a print command from notepad. Its not the .txt file that is sent to the printer by the OS. But a series of printer-understood data is sent. My program generates such device-understandable data which could be just dumped into the port of the device and it will print some meaningful text or act accordingly. I have this binary (kinda junk) stored in unsigned char array. So, I am trying to figure out a way to do this. :) :rose:
So, what is the problem ? Your data is there but if you try to display it with a function that waits for a string, you won't be able to see past the zero char. Just send your buffer and it will work. You need to remember the size of your string of course because strlen won't work.
Cédric Moonen Software developer
Charting control -
char szSource[23] = {"Before\0After"}; char szDest[23]; ptr = memcpy(szDest,szSource,22); printf("%s %d",szDest,strlen(szDest));I went through that page, but not getting it. Can you show me a small code snippet of how do i copy that szSource into szDest? Sorry if a very elementary question. :rose:Aljechin wrote:
char szSource[23] = {"Before\0After"}; char szDest[23]; ptr = memcpy(szDest,szSource,22); printf("%s %d",szDest,strlen(szDest));
char szSource[23] = {"Before\0After"}; char szDest[23]; std::copy(szSource, szSource + 23, szDest);However, as Cedric already noted, don't expect that printf and strlen show the whole thing if you have embedded zeroes.
My programming blahblahblah blog. If you ever find anything useful here, please let me know to remove it.
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char szSource[23] = {"Before\0After"}; char szDest[23]; ptr = memcpy(szDest,szSource,22); printf("%s %d",szDest,strlen(szDest));Hi, may i please request you to just try this code and comment on why memcpy is failing? Is it the way it goes or am I wrong somewhere? Can you suggest some workaround? Thanks for your time. :rose:Aljechin wrote:
ptr = memcpy(szDest,szSource,22);
Use 12 instead.
Aljechin wrote:
printf("%s %d",szDest,strlen(szDest));
This is highly dependent on
szDestbeing nul-terminated. Usingmemcpy()implies that you are not treating it as a nul-terminated string.
"The largest fire starts but with the smallest spark." - David Crow
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Aljechin wrote:
ptr = memcpy(szDest,szSource,22);
Use 12 instead.
Aljechin wrote:
printf("%s %d",szDest,strlen(szDest));
This is highly dependent on
szDestbeing nul-terminated. Usingmemcpy()implies that you are not treating it as a nul-terminated string.
"The largest fire starts but with the smallest spark." - David Crow
Thank you so much. :rose:
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Aljechin wrote:
char szSource[23] = {"Before\0After"}; char szDest[23]; ptr = memcpy(szDest,szSource,22); printf("%s %d",szDest,strlen(szDest));
char szSource[23] = {"Before\0After"}; char szDest[23]; std::copy(szSource, szSource + 23, szDest);However, as Cedric already noted, don't expect that printf and strlen show the whole thing if you have embedded zeroes.
My programming blahblahblah blog. If you ever find anything useful here, please let me know to remove it.
Thank you so much. I will try this. :rose:
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So, what is the problem ? Your data is there but if you try to display it with a function that waits for a string, you won't be able to see past the zero char. Just send your buffer and it will work. You need to remember the size of your string of course because strlen won't work.
Cédric Moonen Software developer
Charting controlThank you very much