The IS operator
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Well here's a case of "Read the Flipping Manual", if ever I saw one! I spent ages trying to compare a control to a TextBox, mostly without success - I went through all manner of
.Equals(),.GetType,== anotherTextBox.GetType(),and all I needed to do was use wasif (control is TextBox)!Gahhh! Still, I'm interested to know what the compiler is doing, and why if (control == TextBox) generates an error - can anyone illuminate me? Thanks, Martin. -
Well here's a case of "Read the Flipping Manual", if ever I saw one! I spent ages trying to compare a control to a TextBox, mostly without success - I went through all manner of
.Equals(),.GetType,== anotherTextBox.GetType(),and all I needed to do was use wasif (control is TextBox)!Gahhh! Still, I'm interested to know what the compiler is doing, and why if (control == TextBox) generates an error - can anyone illuminate me? Thanks, Martin. -
Well here's a case of "Read the Flipping Manual", if ever I saw one! I spent ages trying to compare a control to a TextBox, mostly without success - I went through all manner of
.Equals(),.GetType,== anotherTextBox.GetType(),and all I needed to do was use wasif (control is TextBox)!Gahhh! Still, I'm interested to know what the compiler is doing, and why if (control == TextBox) generates an error - can anyone illuminate me? Thanks, Martin.Utini wrote:
why if (control == TextBox) generates an error - can anyone illuminate me?
Because it's suppose to be:
control.GetType()==typeof(TextBox) -
Well here's a case of "Read the Flipping Manual", if ever I saw one! I spent ages trying to compare a control to a TextBox, mostly without success - I went through all manner of
.Equals(),.GetType,== anotherTextBox.GetType(),and all I needed to do was use wasif (control is TextBox)!Gahhh! Still, I'm interested to know what the compiler is doing, and why if (control == TextBox) generates an error - can anyone illuminate me? Thanks, Martin.Utini wrote:
Well here's a case of "Read the Flipping Manual", if ever I saw one!
Exactly, RTFM. Your code
if( control == TextBox)does not and should not compile for several reasons. 1)TextBoxis meaningless by itself.typeof(TextBox)means something. 2) Assuming you use the code provieded (1), it is meaningless to check for equality between a Control and a Type. What on Earth would that mean? Josh -
Well here's a case of "Read the Flipping Manual", if ever I saw one! I spent ages trying to compare a control to a TextBox, mostly without success - I went through all manner of
.Equals(),.GetType,== anotherTextBox.GetType(),and all I needed to do was use wasif (control is TextBox)!Gahhh! Still, I'm interested to know what the compiler is doing, and why if (control == TextBox) generates an error - can anyone illuminate me? Thanks, Martin. -
Utini wrote:
why if (control == TextBox) generates an error
What error is it generating? Mike Poz
The error would be
'TextBox' is a 'type' but is used like a 'variable'
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Well here's a case of "Read the Flipping Manual", if ever I saw one! I spent ages trying to compare a control to a TextBox, mostly without success - I went through all manner of
.Equals(),.GetType,== anotherTextBox.GetType(),and all I needed to do was use wasif (control is TextBox)!Gahhh! Still, I'm interested to know what the compiler is doing, and why if (control == TextBox) generates an error - can anyone illuminate me? Thanks, Martin.control is an instance, TextBox is a type. Apples and oranges (or more correctly, cookies and cookie cutters).
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