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  4. How to read in text from a textbox

How to read in text from a textbox

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  • T Tamimi Code

    hi textBox1.text will give you the text is typed in textBox1:)

    Tamimi - Code

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    Yustme
    wrote on last edited by
    #4

    Hi Tamimi, That worked! Thank you! I declared readIn to read what is typed in the textbox like this: string readIn = this.texBox1.Text; And attaching it to the eventhandler like this: readIn += new KeyEventHandler(texBox1_KeyPress); It gives me the error: No overload for 'texBox1_KeyPress' matches delegate 'System.Windows.Forms.KeyEventHandler' What am i doing wrong?

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    • Y Yustme

      Hi Tamimi, That worked! Thank you! I declared readIn to read what is typed in the textbox like this: string readIn = this.texBox1.Text; And attaching it to the eventhandler like this: readIn += new KeyEventHandler(texBox1_KeyPress); It gives me the error: No overload for 'texBox1_KeyPress' matches delegate 'System.Windows.Forms.KeyEventHandler' What am i doing wrong?

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      Tamimi Code
      wrote on last edited by
      #5

      hi could you give more details about what you are trying to do ?? if simply you want the text in a textbox the .Text property its enough and no need to attaching anything. what exactly you want to do ??

      Tamimi - Code

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      • T Tamimi Code

        hi could you give more details about what you are trying to do ?? if simply you want the text in a textbox the .Text property its enough and no need to attaching anything. what exactly you want to do ??

        Tamimi - Code

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        Yustme
        wrote on last edited by
        #6

        Hi, I want to accept only 0, 1, 2 .... 9 as input. In order to do this, i have to attach texbBox1.Text to the keypressed handler. But i got it fixed now, Thank you!

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        • Y Yustme

          Hi, I want to accept only 0, 1, 2 .... 9 as input. In order to do this, i have to attach texbBox1.Text to the keypressed handler. But i got it fixed now, Thank you!

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          Tamimi Code
          wrote on last edited by
          #7

          hi is there any wrong with this: private void textBox1_KeyPress(object sender, System.Windows.Forms.KeyPressEventArgs e) { int intKeyValue = (int)e.KeyChar; if (((intKeyValue<48 || intKeyValue>57 ) && intKeyValue!=46)) { e.Handled = true; } }

          Tamimi - Code

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          • Y Yustme

            Hi, I want to accept only 0, 1, 2 .... 9 as input. In order to do this, i have to attach texbBox1.Text to the keypressed handler. But i got it fixed now, Thank you!

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            JacquesDP
            wrote on last edited by
            #8

            You could also try using the textchanged event of the textbox.

            He who laughs last is a bit on the slow side

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            • T Tamimi Code

              hi is there any wrong with this: private void textBox1_KeyPress(object sender, System.Windows.Forms.KeyPressEventArgs e) { int intKeyValue = (int)e.KeyChar; if (((intKeyValue<48 || intKeyValue>57 ) && intKeyValue!=46)) { e.Handled = true; } }

              Tamimi - Code

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              Yustme
              wrote on last edited by
              #9

              Hi Tamimi, There is nothing wrong with that method. In fact, thats the eventhandler i was trying to attach 'readIn' to. If a key is pressed 'readIn' will call that eventhandler to check if its a valid one. Sorry for the confusion Tamimi!

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              • Y Yustme

                Hi Tamimi, There is nothing wrong with that method. In fact, thats the eventhandler i was trying to attach 'readIn' to. If a key is pressed 'readIn' will call that eventhandler to check if its a valid one. Sorry for the confusion Tamimi!

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                Tamimi Code
                wrote on last edited by
                #10

                hi are you trying to do this: this.textBox1.KeyPress += new System.Windows.Forms.KeyPressEventHandler(this.textBox1_KeyPress); if not feel free to ask again

                Tamimi - Code

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                • T Tamimi Code

                  hi are you trying to do this: this.textBox1.KeyPress += new System.Windows.Forms.KeyPressEventHandler(this.textBox1_KeyPress); if not feel free to ask again

                  Tamimi - Code

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                  Yustme
                  wrote on last edited by
                  #11

                  Hi Tamimi, Thats exactly what i meant. But i fixed that half an hour ago :) I do have another question... If i want to get everything between 2 chars, how would i do that? Example: [1] [12] [123] How would i get everything between the '[ ]' chars? Substring wont help, coz the characters inside the [] can be sometimes 1, 3 or more. Thanks in advance!

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                  • Y Yustme

                    Hi Tamimi, Thats exactly what i meant. But i fixed that half an hour ago :) I do have another question... If i want to get everything between 2 chars, how would i do that? Example: [1] [12] [123] How would i get everything between the '[ ]' chars? Substring wont help, coz the characters inside the [] can be sometimes 1, 3 or more. Thanks in advance!

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                    Tamimi Code
                    wrote on last edited by
                    #12

                    hi try this: int intStartIndex = textBox1.Text.IndexOf("[") + 1; int intEndIndex = textBox1.Text.IndexOf("]") - 1; string strBetween = textBox1.Text.Substring(intStartIndex,intEndIndex); but you should be sure that the chars "[" and "]" are exists if not you will get an error index or something like this

                    Tamimi - Code

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                    • T Tamimi Code

                      hi try this: int intStartIndex = textBox1.Text.IndexOf("[") + 1; int intEndIndex = textBox1.Text.IndexOf("]") - 1; string strBetween = textBox1.Text.Substring(intStartIndex,intEndIndex); but you should be sure that the chars "[" and "]" are exists if not you will get an error index or something like this

                      Tamimi - Code

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                      Yustme
                      wrote on last edited by
                      #13

                      Hi Tamimi, That worked great! I thank you for all your help and patience! Yustme

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                      • Y Yustme

                        Hi Tamimi, That worked great! I thank you for all your help and patience! Yustme

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                        Tamimi Code
                        wrote on last edited by
                        #14

                        you are welcome:)

                        Tamimi - Code

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