How to solve this question???
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111100001 1 1100000 111100010 00000000111 00000000111 00000000111 ok, now i change the - to 0, to try to explain this example more clear, this file will be print out in txt format, require the c++ to read from the txt file and also, it is the birnary format, and now can see that the void V is the whole among the group of 1, 1111 1 11 1111 the two exceptional 1 E is locate at: 00001 00000 00010 which consider at not inside the group of 1 and like this 111 111 111 will consider as a group of 1 and so S = (A-E)/(A+V) is this help to explain the problem? thanks sorry to have to post this question again?
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111100001 1 1100000 111100010 00000000111 00000000111 00000000111 ok, now i change the - to 0, to try to explain this example more clear, this file will be print out in txt format, require the c++ to read from the txt file and also, it is the birnary format, and now can see that the void V is the whole among the group of 1, 1111 1 11 1111 the two exceptional 1 E is locate at: 00001 00000 00010 which consider at not inside the group of 1 and like this 111 111 111 will consider as a group of 1 and so S = (A-E)/(A+V) is this help to explain the problem? thanks sorry to have to post this question again?
have you considered ask this in the Mathematic forum ?
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111100001 1 1100000 111100010 00000000111 00000000111 00000000111 ok, now i change the - to 0, to try to explain this example more clear, this file will be print out in txt format, require the c++ to read from the txt file and also, it is the birnary format, and now can see that the void V is the whole among the group of 1, 1111 1 11 1111 the two exceptional 1 E is locate at: 00001 00000 00010 which consider at not inside the group of 1 and like this 111 111 111 will consider as a group of 1 and so S = (A-E)/(A+V) is this help to explain the problem? thanks sorry to have to post this question again?
I have no idea what I just read.... Sorry sinbear, I have no idea.. :confused::wtf::doh:
The only programmers that are better than C programmers are those who code in 1's and 0's..... :) :) Programm3r
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111100001 1 1100000 111100010 00000000111 00000000111 00000000111 ok, now i change the - to 0, to try to explain this example more clear, this file will be print out in txt format, require the c++ to read from the txt file and also, it is the birnary format, and now can see that the void V is the whole among the group of 1, 1111 1 11 1111 the two exceptional 1 E is locate at: 00001 00000 00010 which consider at not inside the group of 1 and like this 111 111 111 will consider as a group of 1 and so S = (A-E)/(A+V) is this help to explain the problem? thanks sorry to have to post this question again?
I think you asked this question yesterday is it homework?
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WhiteSky
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111100001 1 1100000 111100010 00000000111 00000000111 00000000111 ok, now i change the - to 0, to try to explain this example more clear, this file will be print out in txt format, require the c++ to read from the txt file and also, it is the birnary format, and now can see that the void V is the whole among the group of 1, 1111 1 11 1111 the two exceptional 1 E is locate at: 00001 00000 00010 which consider at not inside the group of 1 and like this 111 111 111 will consider as a group of 1 and so S = (A-E)/(A+V) is this help to explain the problem? thanks sorry to have to post this question again?
Are you able to solve this problem on paper? Remember that a computer can't do anything you didn't tell it to do. If a 'space' surrounded by
1s means something, that can easily be searched for. If a series of four (or five)0s is special, that too can be searched for. Work this out on paper and the code will (almost) fall into place.sinbear wrote:
...this file will be print out in txt format...
How is this important (to the problem)?
sinbear wrote:
...it is the birnary format...
Which means what exactly?
sinbear wrote:
the two exceptional 1 E is locate at:
This is all but meaningless. Please clarify.
sinbear wrote:
...the group of 1...
What is a "group of 1?" Plenty of questions have been asked of you but I've yet to see you respond with any clarification. People are willing to help, but only if you can present them with a good understanding of what you want.
"Talent without discipline is like an octopus on roller skates. There's plenty of movement, but you never know if it's going to be forward, backwards, or sideways." - H. Jackson Brown, Jr.
"Judge not by the eye but by the heart." - Native American Proverb
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111100001 1 1100000 111100010 00000000111 00000000111 00000000111 ok, now i change the - to 0, to try to explain this example more clear, this file will be print out in txt format, require the c++ to read from the txt file and also, it is the birnary format, and now can see that the void V is the whole among the group of 1, 1111 1 11 1111 the two exceptional 1 E is locate at: 00001 00000 00010 which consider at not inside the group of 1 and like this 111 111 111 will consider as a group of 1 and so S = (A-E)/(A+V) is this help to explain the problem? thanks sorry to have to post this question again?
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Are you really trying to get some help on this? From the way you present the problem I would guess not... :-P Rilhas