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how to make a faster algorithm

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  • R roberto_santinni

    Hey guys, please help? I'm trying to count each character's occurance in a text. This is what I have but if I am working with 20,000 chars it takes forever. How can I make it faster? (Especially the nested for loop) Thanks a lot! private void frequencyItem_Click(object sender, System.EventArgs e) { Form3 form3 = new Form3(); //creating new form that tells the user to please wait... form3.Show(); //displays the form3 cipherTxt.Text = ""; float numTimes = 0; //declaring and initializing numTimes which stores the number of times a char is presented //declaring and initializing my 72 char alphabet String myAlphabet = new String(new char[] {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','0','1','2','3','4','5','6','7','8','9','\u0027','\u002E','\u002C','\u003A','\u003B','\u003F','\u0021','\u0023','\u0028','\u0029'}); //nested for loop comparing every char in the alphabet to every char in the plaintext textbox for(int i=0;i0) //if number of times a char's ocurrence is presented { //print in ciphertext textbox the result of percentages cipherTxt.Text += "Letter " + myAlphabet[i] + " is displayed " + numTimes + " times. It is " + (numTimes/plainTxt.Text.Length)*100 + "% of the whole text." + System.Environment.NewLine; } numTimes = 0; //return the current alphabet's char count to 0 } string frequencyLetters = cipherTxt.Text; //pass results to a string cipherTxt.Text = ""; //clear ciphertext textbox form3.Close(); //closes the waiting form... try //tries following block of code if user selects Cancel on save box { saveFileDialog.ShowDialog(); //show the save dialog String saveFileName = saveFileDialog.FileName; //store output filename as string TextWriter textOut = new StreamWriter(saveFileName); //new streamwriter to filename textOut.WriteLine(frequencyLetters); //writing results to file textOut.Close(); //closing streamwriter } catch(Exception arg) //catches exception { return; //exits void function } } Santinni

    T Offline
    T Offline
    toxcct
    wrote on last edited by
    #3

    roberto_santinni wrote:

    how to make a faster algorithm

    at the beginning of your code, have you tried to write this :

    while (!fastEnough()) {
    accelerate();
    }

    ok ok, i leave :rolleyes:


    You don't know where to start ? ask a good friend

    [VisualCalc 3.0][Flags Beginner's Guide]

    U 1 Reply Last reply
    0
    • R roberto_santinni

      Hey guys, please help? I'm trying to count each character's occurance in a text. This is what I have but if I am working with 20,000 chars it takes forever. How can I make it faster? (Especially the nested for loop) Thanks a lot! private void frequencyItem_Click(object sender, System.EventArgs e) { Form3 form3 = new Form3(); //creating new form that tells the user to please wait... form3.Show(); //displays the form3 cipherTxt.Text = ""; float numTimes = 0; //declaring and initializing numTimes which stores the number of times a char is presented //declaring and initializing my 72 char alphabet String myAlphabet = new String(new char[] {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','0','1','2','3','4','5','6','7','8','9','\u0027','\u002E','\u002C','\u003A','\u003B','\u003F','\u0021','\u0023','\u0028','\u0029'}); //nested for loop comparing every char in the alphabet to every char in the plaintext textbox for(int i=0;i0) //if number of times a char's ocurrence is presented { //print in ciphertext textbox the result of percentages cipherTxt.Text += "Letter " + myAlphabet[i] + " is displayed " + numTimes + " times. It is " + (numTimes/plainTxt.Text.Length)*100 + "% of the whole text." + System.Environment.NewLine; } numTimes = 0; //return the current alphabet's char count to 0 } string frequencyLetters = cipherTxt.Text; //pass results to a string cipherTxt.Text = ""; //clear ciphertext textbox form3.Close(); //closes the waiting form... try //tries following block of code if user selects Cancel on save box { saveFileDialog.ShowDialog(); //show the save dialog String saveFileName = saveFileDialog.FileName; //store output filename as string TextWriter textOut = new StreamWriter(saveFileName); //new streamwriter to filename textOut.WriteLine(frequencyLetters); //writing results to file textOut.Close(); //closing streamwriter } catch(Exception arg) //catches exception { return; //exits void function } } Santinni

      H Offline
      H Offline
      Haoman17
      wrote on last edited by
      #4

      you need to: 1. use loop unroling 2. use openmp if you have dual core processor (write openmp in google) 3. use intell tbb - on intel site 4. use lookup tables

      P U 2 Replies Last reply
      0
      • H Haoman17

        you need to: 1. use loop unroling 2. use openmp if you have dual core processor (write openmp in google) 3. use intell tbb - on intel site 4. use lookup tables

        P Offline
        P Offline
        peterchen
        wrote on last edited by
        #5

        loop unrolling rarely changes anything on todays compilers/architectures. Multithreading will help, but not as much as picking a better algorithm (as said in the first article).


        We are a big screwed up dysfunctional psychotic happy family - some more screwed up, others more happy, but everybody's psychotic joint venture definition of CP
        Linkify! || Fold With Us! || sighist

        H U 2 Replies Last reply
        0
        • R roberto_santinni

          Hey guys, please help? I'm trying to count each character's occurance in a text. This is what I have but if I am working with 20,000 chars it takes forever. How can I make it faster? (Especially the nested for loop) Thanks a lot! private void frequencyItem_Click(object sender, System.EventArgs e) { Form3 form3 = new Form3(); //creating new form that tells the user to please wait... form3.Show(); //displays the form3 cipherTxt.Text = ""; float numTimes = 0; //declaring and initializing numTimes which stores the number of times a char is presented //declaring and initializing my 72 char alphabet String myAlphabet = new String(new char[] {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','0','1','2','3','4','5','6','7','8','9','\u0027','\u002E','\u002C','\u003A','\u003B','\u003F','\u0021','\u0023','\u0028','\u0029'}); //nested for loop comparing every char in the alphabet to every char in the plaintext textbox for(int i=0;i0) //if number of times a char's ocurrence is presented { //print in ciphertext textbox the result of percentages cipherTxt.Text += "Letter " + myAlphabet[i] + " is displayed " + numTimes + " times. It is " + (numTimes/plainTxt.Text.Length)*100 + "% of the whole text." + System.Environment.NewLine; } numTimes = 0; //return the current alphabet's char count to 0 } string frequencyLetters = cipherTxt.Text; //pass results to a string cipherTxt.Text = ""; //clear ciphertext textbox form3.Close(); //closes the waiting form... try //tries following block of code if user selects Cancel on save box { saveFileDialog.ShowDialog(); //show the save dialog String saveFileName = saveFileDialog.FileName; //store output filename as string TextWriter textOut = new StreamWriter(saveFileName); //new streamwriter to filename textOut.WriteLine(frequencyLetters); //writing results to file textOut.Close(); //closing streamwriter } catch(Exception arg) //catches exception { return; //exits void function } } Santinni

          R Offline
          R Offline
          Rob Graham
          wrote on last edited by
          #6

          That algoritm is pretty poor, however, one simple optimization that will roughly double its speed would be

          for(int j=0;j

          U 1 Reply Last reply
          0
          • P peterchen

            loop unrolling rarely changes anything on todays compilers/architectures. Multithreading will help, but not as much as picking a better algorithm (as said in the first article).


            We are a big screwed up dysfunctional psychotic happy family - some more screwed up, others more happy, but everybody's psychotic joint venture definition of CP
            Linkify! || Fold With Us! || sighist

            H Offline
            H Offline
            Haoman17
            wrote on last edited by
            #7

            Im sorry, but you are wrong. in many of my programs, i really saw a different. btw, you can use the optimization switch in VS2005, it also does a great job.

            U 1 Reply Last reply
            0
            • R roberto_santinni

              Hey guys, please help? I'm trying to count each character's occurance in a text. This is what I have but if I am working with 20,000 chars it takes forever. How can I make it faster? (Especially the nested for loop) Thanks a lot! private void frequencyItem_Click(object sender, System.EventArgs e) { Form3 form3 = new Form3(); //creating new form that tells the user to please wait... form3.Show(); //displays the form3 cipherTxt.Text = ""; float numTimes = 0; //declaring and initializing numTimes which stores the number of times a char is presented //declaring and initializing my 72 char alphabet String myAlphabet = new String(new char[] {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','0','1','2','3','4','5','6','7','8','9','\u0027','\u002E','\u002C','\u003A','\u003B','\u003F','\u0021','\u0023','\u0028','\u0029'}); //nested for loop comparing every char in the alphabet to every char in the plaintext textbox for(int i=0;i0) //if number of times a char's ocurrence is presented { //print in ciphertext textbox the result of percentages cipherTxt.Text += "Letter " + myAlphabet[i] + " is displayed " + numTimes + " times. It is " + (numTimes/plainTxt.Text.Length)*100 + "% of the whole text." + System.Environment.NewLine; } numTimes = 0; //return the current alphabet's char count to 0 } string frequencyLetters = cipherTxt.Text; //pass results to a string cipherTxt.Text = ""; //clear ciphertext textbox form3.Close(); //closes the waiting form... try //tries following block of code if user selects Cancel on save box { saveFileDialog.ShowDialog(); //show the save dialog String saveFileName = saveFileDialog.FileName; //store output filename as string TextWriter textOut = new StreamWriter(saveFileName); //new streamwriter to filename textOut.WriteLine(frequencyLetters); //writing results to file textOut.Close(); //closing streamwriter } catch(Exception arg) //catches exception { return; //exits void function } } Santinni

              X Offline
              X Offline
              Xint0
              wrote on last edited by
              #8

              How about using a hash-table for the counters and forget about the nested loops. Assuming you are doing this with .NET 2.0, here's my take on this:

              private string DoCount(string input)
              {
                  string alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ01234567890\u0027\u002E\u002C\u003A\u003B\u003F\u0021\u0023\u0028\u0029";
              // create hash-table for counters, set initial capacity to number of counters (characters in alphabet).
                  Dictionary counters = new Dictionary(alphabet.Length); 
              //initialize just to be safe:
                  foreach(char c in alphabet)
                      counters[c] = 0;
              //count the characters in the input string:
                  foreach(char c in input)
                      if(counters.ContainsKey(c))
                          counters[c]++;
              //now output statistics
                  string output = string.Empty;
                  for (int i = 0; i < alphabet.Length; i++)
                  {
                      flost percent = 0.0F;
                      char c = alphabet[i];
                      int count = counters[c];
                      if(count > 0)
                           percent = (float)count / input.Length;
                      output += string.Format("Letter {0} is displayed {1} times.  It is {2:P2} of the whole text.{3}", c, count, percent, Environment.NewLine);
                  }
                  return output;
              }
              

              Hope it works for you. :-D -- modified at 22:56 Thursday 26th October, 2006

              - Xint0 :cool:

              U 1 Reply Last reply
              0
              • H Haoman17

                Im sorry, but you are wrong. in many of my programs, i really saw a different. btw, you can use the optimization switch in VS2005, it also does a great job.

                U Offline
                U Offline
                User 12346520
                wrote on last edited by
                #9

                thanks: https://movied.org

                1 Reply Last reply
                0
                • X Xint0

                  How about using a hash-table for the counters and forget about the nested loops. Assuming you are doing this with .NET 2.0, here's my take on this:

                  private string DoCount(string input)
                  {
                      string alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ01234567890\u0027\u002E\u002C\u003A\u003B\u003F\u0021\u0023\u0028\u0029";
                  // create hash-table for counters, set initial capacity to number of counters (characters in alphabet).
                      Dictionary counters = new Dictionary(alphabet.Length); 
                  //initialize just to be safe:
                      foreach(char c in alphabet)
                          counters[c] = 0;
                  //count the characters in the input string:
                      foreach(char c in input)
                          if(counters.ContainsKey(c))
                              counters[c]++;
                  //now output statistics
                      string output = string.Empty;
                      for (int i = 0; i < alphabet.Length; i++)
                      {
                          flost percent = 0.0F;
                          char c = alphabet[i];
                          int count = counters[c];
                          if(count > 0)
                               percent = (float)count / input.Length;
                          output += string.Format("Letter {0} is displayed {1} times.  It is {2:P2} of the whole text.{3}", c, count, percent, Environment.NewLine);
                      }
                      return output;
                  }
                  

                  Hope it works for you. :-D -- modified at 22:56 Thursday 26th October, 2006

                  - Xint0 :cool:

                  U Offline
                  U Offline
                  User 12346520
                  wrote on last edited by
                  #10

                  thanks: https://movied.org

                  1 Reply Last reply
                  0
                  • P peterchen

                    loop unrolling rarely changes anything on todays compilers/architectures. Multithreading will help, but not as much as picking a better algorithm (as said in the first article).


                    We are a big screwed up dysfunctional psychotic happy family - some more screwed up, others more happy, but everybody's psychotic joint venture definition of CP
                    Linkify! || Fold With Us! || sighist

                    U Offline
                    U Offline
                    User 12346520
                    wrote on last edited by
                    #11

                    thanks: https://movied.org

                    1 Reply Last reply
                    0
                    • R Rob Graham

                      That algoritm is pretty poor, however, one simple optimization that will roughly double its speed would be

                      for(int j=0;j

                      U Offline
                      U Offline
                      User 12346520
                      wrote on last edited by
                      #12

                      thanks: https://movied.org

                      1 Reply Last reply
                      0
                      • H Haoman17

                        you need to: 1. use loop unroling 2. use openmp if you have dual core processor (write openmp in google) 3. use intell tbb - on intel site 4. use lookup tables

                        U Offline
                        U Offline
                        User 12346520
                        wrote on last edited by
                        #13

                        thanks: https://movied.org

                        1 Reply Last reply
                        0
                        • R roberto_santinni

                          Hey guys, please help? I'm trying to count each character's occurance in a text. This is what I have but if I am working with 20,000 chars it takes forever. How can I make it faster? (Especially the nested for loop) Thanks a lot! private void frequencyItem_Click(object sender, System.EventArgs e) { Form3 form3 = new Form3(); //creating new form that tells the user to please wait... form3.Show(); //displays the form3 cipherTxt.Text = ""; float numTimes = 0; //declaring and initializing numTimes which stores the number of times a char is presented //declaring and initializing my 72 char alphabet String myAlphabet = new String(new char[] {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','0','1','2','3','4','5','6','7','8','9','\u0027','\u002E','\u002C','\u003A','\u003B','\u003F','\u0021','\u0023','\u0028','\u0029'}); //nested for loop comparing every char in the alphabet to every char in the plaintext textbox for(int i=0;i0) //if number of times a char's ocurrence is presented { //print in ciphertext textbox the result of percentages cipherTxt.Text += "Letter " + myAlphabet[i] + " is displayed " + numTimes + " times. It is " + (numTimes/plainTxt.Text.Length)*100 + "% of the whole text." + System.Environment.NewLine; } numTimes = 0; //return the current alphabet's char count to 0 } string frequencyLetters = cipherTxt.Text; //pass results to a string cipherTxt.Text = ""; //clear ciphertext textbox form3.Close(); //closes the waiting form... try //tries following block of code if user selects Cancel on save box { saveFileDialog.ShowDialog(); //show the save dialog String saveFileName = saveFileDialog.FileName; //store output filename as string TextWriter textOut = new StreamWriter(saveFileName); //new streamwriter to filename textOut.WriteLine(frequencyLetters); //writing results to file textOut.Close(); //closing streamwriter } catch(Exception arg) //catches exception { return; //exits void function } } Santinni

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                          U Offline
                          User 12346520
                          wrote on last edited by
                          #14

                          thanks: https://movied.org

                          1 Reply Last reply
                          0
                          • E ejuanpp

                            Why don't you try converting your char values to indexes ? ie: int[] frequence = new int[ushort.MaxValue]; for (int i = 0; i < s.Length; i++) { frequence[(ushort)s[i]]++; } regards

                            U Offline
                            U Offline
                            User 12346520
                            wrote on last edited by
                            #15

                            thanks: https://movied.org

                            1 Reply Last reply
                            0
                            • T toxcct

                              roberto_santinni wrote:

                              how to make a faster algorithm

                              at the beginning of your code, have you tried to write this :

                              while (!fastEnough()) {
                              accelerate();
                              }

                              ok ok, i leave :rolleyes:


                              You don't know where to start ? ask a good friend

                              [VisualCalc 3.0][Flags Beginner's Guide]

                              U Offline
                              U Offline
                              User 12346520
                              wrote on last edited by
                              #16

                              thanks: https://movied.org

                              1 Reply Last reply
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