Why?

[_8086]

int j; j=4; //100 printf("\n\nj value:%d",(~j));//100-->(NOT)-->011-->So shouldn't this be 2?? It prints -5??? Why?:confused:

---------------------------- 286? WOWW!:-O

[jeron1]

(4) is hex 0x00000004 ~(4) is hex 0xfffffffb which is a signed integer which is (-5) Jeron

[Mark Salsbery]

_8086 wrote:

011-->So shouldn't this be 2

Actually that's 3 :) The ~ operator effects ALL the bits of the integer

int j; // j is a signed integer - I'll assume 32-bits in length
j=4; // 00000000000000000000000000000100 (4)
j=~j; // 11111111111111111111111111111011 (-5)

"If you can dodge a wrench, you can dodge a ball."

[led mike]

:->

led mike

[_8086]

Mark Salsbery wrote:

Actually that's 3

:doh: Thanks :)

---------------------------- 286? WOWW!:-O