Help here...allow the files display randomly

[Missy Glory]

Hi everyone:), I have a problem here, my program can automatic display 12 files when the button is click.I use timer to let the 12 files to display orderly. But my question is " How to allow the 12 files to display randomly everytime when i click the button" :confused: :laugh:Thank for helpin

[Tamimi Code]

could you explain more ??

When you get mad...THINK twice that the only advice Tamimi - Code

[Missy Glory]

Yes... The 12 files is the 12 waveform to be display one by one automatically when i click the button.My program can only allow the 12 waveform to display in order when i run the program( everytime when i run the program, the 12 waveform will display from 1 to 12). Therefore my problem is " how to allow the 12 waveform to display randomly." for example when i run the program, the third waveform will run first. And when i run the program the second time, the tenth waveform will run first. Hope u understand..;) thank..

[joon vh]

this is what I think you need:

        static void Main(string[] args)
        {
            RunRandomly(12);
        }

        static void RunRandomly(int amount)
        {
            ArrayList alreadyused = new ArrayList();
            Random rnd = new Random();
            while (amount > 0)
            {
                int rndint = Convert.ToInt32(rnd.Next(12));
                if (!alreadyused.Contains(rndint))
                {
                    Run(rndint);
                    amount--;
                    alreadyused.Add(rndint);
                }               
            }
        }
        static void Run(int number)
        {
            // do whatever you need to do, number will be a random number between 0 and 11
            Console.WriteLine(number);
        }

if it doesn't make sense, then neither did your question I'm afraid ;)

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Visual Studio can't evaluate this, can you? public object moo { __get { return moo; } __set { moo = value; } }

[Stefan Troschuetz]

joon vh. wrote:

int rndint = Convert.ToInt32(rnd.Next(12));

No need to call Convert.ToInt32 here since Random.Next returns an integer.

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"Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning." - Rick Cook

www.troschuetz.de

[joon vh]

wow... dunno why I assumed it didn't :p good call

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Visual Studio can't evaluate this, can you? public object moo { __get { return moo; } __set { moo = value; } }