Truncate decimal place

[polishprogrammer]

I need to do some math that involves truncating the number after the tenths place. So, I need to take some calculation and remove all digits after the first decimal place without rounding. For example 3765/3700 * 100=101.75675675675675675675675675676 But, I need to produce from that calculation 101.7. Not 101.8 (the rounded form). Is there a built in method that performs this sort of calculation, or some other way that you might suggest? Thanks.

[gauthee]

try math.ceiling or math.floor methods

Gautham

[Martin 0]

Hello, If you want to show it as a string, you could use the String.Format method.

int numberofdecpoints= 10;
double d = 3765/3700 * 100;
string roundednumber = String.Format("{0:F"+ numberofdecpoints.ToString() +"}",d);

All the best, Martin

[Not Active]

May not be the prettiest double d = 101.75675675675675675675675675676; string s = string.Format("{0:f2}", d); d = Convert.ToDouble(s.Remove(s.Length-1)); Using the specifier {0:f1} still rounds the number to 101.8, so use 0:f2 and truncate it.

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only two letters away from being an asset

[althamda]

Can't you just do this? double d = 128.158676; Convert.ToDouble(Convert.ToInt32(d * 10)) / 10;

[mabo42]

double d = 101.75675675675675675675675675676;
d = Math.Floor(10 * d) / 10;

Now d has a value of 101.7 Hope this helps