Help with random numbers
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When I run the following code I get the same number 36 times, but when I step through it in debug I get 'random' numbers?!?! Any idea why?
for (int a = 0; a < 36; a++) { Random generator = new Random(); int randomValue; randomValue = generator.Next(1, 20); list3.Add(a, randomValue); }David Wilkes
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When I run the following code I get the same number 36 times, but when I step through it in debug I get 'random' numbers?!?! Any idea why?
for (int a = 0; a < 36; a++) { Random generator = new Random(); int randomValue; randomValue = generator.Next(1, 20); list3.Add(a, randomValue); }David Wilkes
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Sorry, "list3" is a custom data type similar to a listbox.
David Wilkes
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Sorry, "list3" is a custom data type similar to a listbox.
David Wilkes
Hi, you create a new random generator every time; they each start with a dfeault seed value, which depends on the current time. As a result, while single stepping it seems all right; when running it finishes in less than 1 second, so all seeds are the same. You should create and use only one generator outside the loop and keep using it. :)
Luc Pattyn [My Articles] [Forum Guidelines]
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Hi, you create a new random generator every time; they each start with a dfeault seed value, which depends on the current time. As a result, while single stepping it seems all right; when running it finishes in less than 1 second, so all seeds are the same. You should create and use only one generator outside the loop and keep using it. :)
Luc Pattyn [My Articles] [Forum Guidelines]
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Hi, you create a new random generator every time; they each start with a dfeault seed value, which depends on the current time. As a result, while single stepping it seems all right; when running it finishes in less than 1 second, so all seeds are the same. You should create and use only one generator outside the loop and keep using it. :)
Luc Pattyn [My Articles] [Forum Guidelines]
That makes total sense. Figured it was something simple. Thanks!!!
David Wilkes
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When I run the following code I get the same number 36 times, but when I step through it in debug I get 'random' numbers?!?! Any idea why?
for (int a = 0; a < 36; a++) { Random generator = new Random(); int randomValue; randomValue = generator.Next(1, 20); list3.Add(a, randomValue); }David Wilkes
Random generator = new Random(); for (int a = 0; a < 36; a++) { int randomValue; randomValue = generator.Next(1, 20); list3.Add(a, randomValue); }
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