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  4. Urgent - How to identify given image is too dark or light

Urgent - How to identify given image is too dark or light

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  • S Offline
    S Offline
    sujtha
    wrote on last edited by
    #1

    How to identify given image is too dark or light? Input format of the file is tif and jpg.

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    • S sujtha

      How to identify given image is too dark or light? Input format of the file is tif and jpg.

      W Offline
      W Offline
      Waldermort
      wrote on last edited by
      #2

      By taking a look at it I suppose... Please don't mark your topic with the word Urgent.

      Waldermort

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      • S sujtha

        How to identify given image is too dark or light? Input format of the file is tif and jpg.

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        R Offline
        Russell
        wrote on last edited by
        #3

        images are made of pixel, then every pixel has got a color, the color is a combination of red-green-blue (RGB). white is RGB(255,255,255), black is RGB(0,0,0). Convert your image in a gray scale: take the color of every pixel (r,g,b) then compute c=(r+g+b)/3, so the gray pixel of a new image can be RGB(c,c,c), but you can simply store c somewhere. Then compute the mean value of c on all the image and compare it with a treshold. do something like this: if c_mean is less then 50 the image is too dark if c_mean is greater then 200 the image is too light hope helps :-D


        Russell

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        • W Waldermort

          By taking a look at it I suppose... Please don't mark your topic with the word Urgent.

          Waldermort

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          toxcct
          wrote on last edited by
          #4

          WalderMort wrote:

          Please don't mark your topic with the word Urgent.

          '5' for this :-D


          [VisualCalc][Binary Guide][CommDialogs] | [Forums Guidelines]

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          • S sujtha

            How to identify given image is too dark or light? Input format of the file is tif and jpg.

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            KarstenK
            wrote on last edited by
            #5

            make a bitmap out of and test the pixels. -> CXImage article at CP

            Greetings from Germany

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            • R Russell

              images are made of pixel, then every pixel has got a color, the color is a combination of red-green-blue (RGB). white is RGB(255,255,255), black is RGB(0,0,0). Convert your image in a gray scale: take the color of every pixel (r,g,b) then compute c=(r+g+b)/3, so the gray pixel of a new image can be RGB(c,c,c), but you can simply store c somewhere. Then compute the mean value of c on all the image and compare it with a treshold. do something like this: if c_mean is less then 50 the image is too dark if c_mean is greater then 200 the image is too light hope helps :-D


              Russell

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              Nishad S
              wrote on last edited by
              #6

              Russell` wrote:

              compute c=(r+g+b)/3,

              But the brightness is not simply the average, right? Red has low intensity compared to others. I dont remember the exact ratio.

              - NS -

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              • N Nishad S

                Russell` wrote:

                compute c=(r+g+b)/3,

                But the brightness is not simply the average, right? Red has low intensity compared to others. I dont remember the exact ratio.

                - NS -

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                Russell
                wrote on last edited by
                #7

                I think you are right. If you find the right formula please post it here, I'll be happy to learn it. :-D In this case I think that him doesn't need an accurate extraction of the gray-scale, the simple formula (r+g+b)/3 can be enough.


                Russell

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                • R Russell

                  I think you are right. If you find the right formula please post it here, I'll be happy to learn it. :-D In this case I think that him doesn't need an accurate extraction of the gray-scale, the simple formula (r+g+b)/3 can be enough.


                  Russell

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                  Nishad S
                  wrote on last edited by
                  #8

                  Russell` wrote:

                  If you find the right formula please post it here

                  The one I know is Y = 0.3*R + 0.59*G + 0.11*B

                  Russell` wrote:

                  the simple formula (r+g+b)/3 can be enough

                  If it is not for human recognition... right?

                  - NS -

                  R S 2 Replies Last reply
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                  • N Nishad S

                    Russell` wrote:

                    If you find the right formula please post it here

                    The one I know is Y = 0.3*R + 0.59*G + 0.11*B

                    Russell` wrote:

                    the simple formula (r+g+b)/3 can be enough

                    If it is not for human recognition... right?

                    - NS -

                    R Offline
                    R Offline
                    Russell
                    wrote on last edited by
                    #9

                    NS17 wrote:

                    Y = 0.3*R + 0.59*G + 0.11*B

                    Yes! I was forgetting this!:doh: (r+g+b)/3 it only an approssimation of the right formula... I used this in past to implement a fast algorithm, but of course it isn't exact. :-D


                    Russell

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                    • N Nishad S

                      Russell` wrote:

                      If you find the right formula please post it here

                      The one I know is Y = 0.3*R + 0.59*G + 0.11*B

                      Russell` wrote:

                      the simple formula (r+g+b)/3 can be enough

                      If it is not for human recognition... right?

                      - NS -

                      S Offline
                      S Offline
                      Sreedhar DV
                      wrote on last edited by
                      #10

                      What exactly are those constants 0.3 , 0.59 and 0.11 ?

                      Sreedhar DV [Real success is having courage to meet failure without being defeated.]

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                      • S Sreedhar DV

                        What exactly are those constants 0.3 , 0.59 and 0.11 ?

                        Sreedhar DV [Real success is having courage to meet failure without being defeated.]

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                        Russell
                        wrote on last edited by
                        #11

                        Our eye is more sensitive on the green light and less on red. So, that constants are related to the features of the human eye. hope it helps.


                        Russell

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