Broken code?
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What led you to the conclusion that your code was wrongly compiled ? Was it not doing what you wanted ? Can we see the C++ code ?
Maximilien Lincourt Your Head A Splode - Strong Bad
What indeed? That it doesn't call the overloaded operator function is quite enough. Showing all the code would be pretty long and boring and irrelevant, so I'll show the important snippets of the declaration/definition of the variables and the class.
template< class T1, class T2> long GetRegValuePtrNew(const char* strKey, const char* strName, CBuffer< T1> Buffer, /*bool bUseTempBuffer, */CBuffer< T2> RetBuf = (T2*)THROW_ERROR, DWORD* pType = NULL) throw(...) { ... Buffer = RetBuf; ... } template< typename T> class CBuffer { ... template< typename T2> void operator = (CBuffer< T2>& rBuffer); ... };There's the basic declaration, so the obvious thing is that the compiler should generate code that calls CBuffer::operator =, but it doesn't, as you can see from the asm snippet I gave you. This is all the relevant parts of the code, but I can post the whole function/class if it's necessary. It's just that it would be so long. I also want to made it clear that I intentionally put spaces after a < since otherwise it's interpreted as HTML code and not shown. In REAL code I would NEVER do that, since I HATE it, it looks POOR. Just wanted to say that ;) EDIT: Actually, I seem to have fixed the problem. The problem was that the compiler was confused, but it still shouldn't have generated faulty code. It should complain, should it not? Consider this: As you saw above, the assignment operator takes a CBuffer of a DIFFERENT type than the type of the actual class (it takes T2 instead of T). In the above template, T1 and T2 = UINT64, the same type. Adding the following:void operator = (CBuffer& rBuffer);...Fixes the problem. It seems the compiler gets confused and cannot interpret T2 as T (so if there's a var of CBuffer< UINT64>, the assignment operator can't take a CBuffer< UINT64> as argument, because it's the same type as the class type T). I got around it by adding an additional operator that takes the class's type T (CBuffer< T>) as argument and now it works. Of course, this shouldn't really be, AFAIK. Here is the new code:void operator = (CBuffer& rBuffer) { Assign(rBuffer); } template void operator = (CBuffer& rBuffer) { Assign(rBuffer); } template void Assign(CBuffer& rBuffer)...As plainly visible, both overloads call Assign, which takes a new template type T2 as argument, and both functions (well, I only tested the first, though) call the Assign fu -
What indeed? That it doesn't call the overloaded operator function is quite enough. Showing all the code would be pretty long and boring and irrelevant, so I'll show the important snippets of the declaration/definition of the variables and the class.
template< class T1, class T2> long GetRegValuePtrNew(const char* strKey, const char* strName, CBuffer< T1> Buffer, /*bool bUseTempBuffer, */CBuffer< T2> RetBuf = (T2*)THROW_ERROR, DWORD* pType = NULL) throw(...) { ... Buffer = RetBuf; ... } template< typename T> class CBuffer { ... template< typename T2> void operator = (CBuffer< T2>& rBuffer); ... };There's the basic declaration, so the obvious thing is that the compiler should generate code that calls CBuffer::operator =, but it doesn't, as you can see from the asm snippet I gave you. This is all the relevant parts of the code, but I can post the whole function/class if it's necessary. It's just that it would be so long. I also want to made it clear that I intentionally put spaces after a < since otherwise it's interpreted as HTML code and not shown. In REAL code I would NEVER do that, since I HATE it, it looks POOR. Just wanted to say that ;) EDIT: Actually, I seem to have fixed the problem. The problem was that the compiler was confused, but it still shouldn't have generated faulty code. It should complain, should it not? Consider this: As you saw above, the assignment operator takes a CBuffer of a DIFFERENT type than the type of the actual class (it takes T2 instead of T). In the above template, T1 and T2 = UINT64, the same type. Adding the following:void operator = (CBuffer& rBuffer);...Fixes the problem. It seems the compiler gets confused and cannot interpret T2 as T (so if there's a var of CBuffer< UINT64>, the assignment operator can't take a CBuffer< UINT64> as argument, because it's the same type as the class type T). I got around it by adding an additional operator that takes the class's type T (CBuffer< T>) as argument and now it works. Of course, this shouldn't really be, AFAIK. Here is the new code:void operator = (CBuffer& rBuffer) { Assign(rBuffer); } template void operator = (CBuffer& rBuffer) { Assign(rBuffer); } template void Assign(CBuffer& rBuffer)...As plainly visible, both overloads call Assign, which takes a new template type T2 as argument, and both functions (well, I only tested the first, though) call the Assign fu -
What indeed? That it doesn't call the overloaded operator function is quite enough. Showing all the code would be pretty long and boring and irrelevant, so I'll show the important snippets of the declaration/definition of the variables and the class.
template< class T1, class T2> long GetRegValuePtrNew(const char* strKey, const char* strName, CBuffer< T1> Buffer, /*bool bUseTempBuffer, */CBuffer< T2> RetBuf = (T2*)THROW_ERROR, DWORD* pType = NULL) throw(...) { ... Buffer = RetBuf; ... } template< typename T> class CBuffer { ... template< typename T2> void operator = (CBuffer< T2>& rBuffer); ... };There's the basic declaration, so the obvious thing is that the compiler should generate code that calls CBuffer::operator =, but it doesn't, as you can see from the asm snippet I gave you. This is all the relevant parts of the code, but I can post the whole function/class if it's necessary. It's just that it would be so long. I also want to made it clear that I intentionally put spaces after a < since otherwise it's interpreted as HTML code and not shown. In REAL code I would NEVER do that, since I HATE it, it looks POOR. Just wanted to say that ;) EDIT: Actually, I seem to have fixed the problem. The problem was that the compiler was confused, but it still shouldn't have generated faulty code. It should complain, should it not? Consider this: As you saw above, the assignment operator takes a CBuffer of a DIFFERENT type than the type of the actual class (it takes T2 instead of T). In the above template, T1 and T2 = UINT64, the same type. Adding the following:void operator = (CBuffer& rBuffer);...Fixes the problem. It seems the compiler gets confused and cannot interpret T2 as T (so if there's a var of CBuffer< UINT64>, the assignment operator can't take a CBuffer< UINT64> as argument, because it's the same type as the class type T). I got around it by adding an additional operator that takes the class's type T (CBuffer< T>) as argument and now it works. Of course, this shouldn't really be, AFAIK. Here is the new code:void operator = (CBuffer& rBuffer) { Assign(rBuffer); } template void operator = (CBuffer& rBuffer) { Assign(rBuffer); } template void Assign(CBuffer& rBuffer)...As plainly visible, both overloads call Assign, which takes a new template type T2 as argument, and both functions (well, I only tested the first, though) call the Assign fuYou do have some other problems you need to address. The argument to your overloaded method should be constant and it should return a reference to the left hand side of the argument so you can do things like: “a1 = a2 = a3”. Keep your eyes open for implicit conversions, which is what you’re originally problem sounded like.
INTP "Program testing can be used to show the presence of bugs, but never to show their absence."Edsger Dijkstra
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Tydia-kun wrote:
CBuffer< T1> Buffer
Tydia-kun wrote:
CBuffer< T2> RetBuf
Tydia-kun wrote:
Buffer = RetBuf;
Buffer and RetBuf are different types
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You do have some other problems you need to address. The argument to your overloaded method should be constant and it should return a reference to the left hand side of the argument so you can do things like: “a1 = a2 = a3”. Keep your eyes open for implicit conversions, which is what you’re originally problem sounded like.
INTP "Program testing can be used to show the presence of bugs, but never to show their absence."Edsger Dijkstra
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Yes, they are and that's the whole point of the overloaded assignment operator (=). It takes a CBuffer of different type (or the same type) and copies the data from that buffer into its own buffer. But somehow the compiler didn't understand that.
Don't you need to implement template specialisatioin for that ?
Maximilien Lincourt Your Head A Splode - Strong Bad
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Don't you need to implement template specialisatioin for that ?
Maximilien Lincourt Your Head A Splode - Strong Bad
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Templates are templates - they can be of any type. That's why the overloaded assignment operator takes a new template type of T2. That's the power of templates.
what if you have
CBuffer<string> bufferOfString;
CBuffer<int> bufferofInt;bufferOfString = bufferOfInt; // ????/
don't you need specialisation to know how to convert a
CBuffer<int>to aCBuffer<string>? It's not just amemcpyor member-member copy. I'm just curious, I'm not very familiar with template constructs.
Maximilien Lincourt Your Head A Splode - Strong Bad
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what if you have
CBuffer<string> bufferOfString;
CBuffer<int> bufferofInt;bufferOfString = bufferOfInt; // ????/
don't you need specialisation to know how to convert a
CBuffer<int>to aCBuffer<string>? It's not just amemcpyor member-member copy. I'm just curious, I'm not very familiar with template constructs.
Maximilien Lincourt Your Head A Splode - Strong Bad
That wouldn't work unless you overlord a operator = (CBuffer<int>) or simply make a template operator = such as template<typename T2> operator = (CBuffer<T2>). That way, the compiler can call the overloaded operator = and pass bufferOfInt to it with T2 = int. Memcpy is a very stupid (and dangerous) way of assigning a class to another class since classes are built around handling its own memory and variables. If you read about templates, then you know that you can specify a type for a template and the compiler will generate a function with that type when the template function is invoked. Take for example template<typename T2> operator = (CBuffer<T2>) When you do bufferOfString = bufferOfInt, it generates an overloaded function operator = (CBuffer<int>) And calls it. That's it.
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Yes, they are and that's the whole point of the overloaded assignment operator (=). It takes a CBuffer of different type (or the same type) and copies the data from that buffer into its own buffer. But somehow the compiler didn't understand that.
Tydia-kun wrote:
Yes, they are and that's the whole point of the overloaded assignment operator (=).
No its not. The point of the assignment operator is to assign the value of one object to the value of another. For that to be possible the objects have to be of the same type. Templates are nothing but code generation. When you declare vector and vector they are completely differnt types and have no common interface. If you want to perforam assignment between the two you have to write a specific operator. You cannt write a generic one
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Tydia-kun wrote:
Yes, they are and that's the whole point of the overloaded assignment operator (=).
No its not. The point of the assignment operator is to assign the value of one object to the value of another. For that to be possible the objects have to be of the same type. Templates are nothing but code generation. When you declare vector and vector they are completely differnt types and have no common interface. If you want to perforam assignment between the two you have to write a specific operator. You cannt write a generic one