Program Files Nightmare

[Dreamer2007]

Kindly assist me rectify VB 6.0 code below: Shell("xcopy c:\Software\Zimbabwe c:\Program Files\Zimbabwe.* /-Y") I want to copy the folder called Zimbabwe to Program Files but nothing seems to be happening.

[nlarson11]

i believe the problem is that shell assumes you know the location of xcopy. so by not specifying a path for xcopy it's looking at the local directory instead of c:\windows\system32, so put the path in for xcopy

'Never argue with an idiot; they'll drag you down to their level and beat you with experience.' ~ anonymous

[Dave Kreskowiak]

The XCOPY command should be:

XCOPY C:\\Software\\Zimbabwe\\\*.\* C:\\Program Files\\Zimbabwe\\\*.\* /Y

A guide to posting questions on CodeProject[^]
Dave Kreskowiak Microsoft MVP Visual Developer - Visual Basic
     2006, 2007

[Dreamer2007]

Dave Kreskowiak wrote:

XCOPY C:\Software\Zimbabwe\*.* C:\Program Files\Zimbabwe\*.* /Y

I tried this but still the results are negative. When I try this same command from the DOS prompt I get an error message that says: Invalid number of parameters. I think the problem could be on the spacing of the folder name Program Files but then how can this be rectified? Pease assist.

[Dave Kreskowiak]

Whoops. Any path names with spaces in them should have quote marks around them.

XCOPY C:\Software\Zimbabwe\*.* "C:\Program Files\Zimbabwe\*.*" /Y

A guide to posting questions on CodeProject[^]
Dave Kreskowiak Microsoft MVP Visual Developer - Visual Basic
     2006, 2007