Can anybody tell me the way of getting this answer
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Can anybody tell me the way os getting this answer #define f(g,g2) g##g2 main() { int var12=100; printf("%d",f(var,12))); } Ans:100 Thanks in advance
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Can anybody tell me the way os getting this answer #define f(g,g2) g##g2 main() { int var12=100; printf("%d",f(var,12))); } Ans:100 Thanks in advance
Upon Preprocessing completion (but before compilation), the statement
printf("%d",f(var,12))); gets expanded toprintf("%d",var12)). So the answer, 100. In macrof(g, g2), u r passing var and 12. The statementg##g2joins the original parameter to the macro i.e,var##12 = var12. Hence the resulting variable, var12Come online at:- jubinc@skype
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Can anybody tell me the way os getting this answer #define f(g,g2) g##g2 main() { int var12=100; printf("%d",f(var,12))); } Ans:100 Thanks in advance
Have you considered compiling with the /P switch to see just what the preprocessor resolves the macro to?
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