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extern sample in MSDN

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  • S Stephen Hewitt

    No. The reason for extern is to differentiate between a declaration and a definition: int num; // Is this a definition or a declaration? In this case the compiler assumes it’s a definition. If you want to share num between two compilation units this will not do the trick and will result in a linker error – there will be two variables with the same name. extern int num; // This is a declaration. Now this referrers to a “num” defined elsewhere.

    Steve

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    George_George
    wrote on last edited by
    #5

    Thanks Steve, In the sample, even if you do not use why we need to write statement, extern int i? i is global and we can use it anywhere in the same compile unit (cpp file). regards, George

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    • G George_George

      Thanks Steve, In the sample, even if you do not use why we need to write statement, extern int i? i is global and we can use it anywhere in the same compile unit (cpp file). regards, George

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      Stephen Hewitt
      wrote on last edited by
      #6

      As I said, extern is used to indicate that a construct is a declaration and not a definition. With functions no such mechanism is needed: if the function has a body it’s a definition and if not it’s a declaration:

      int void FooBar(); // This is a declaration (no body).
      int void FooBar() // This is a definition (has body).
      {
      // Do stuff…
      }

      If you want to use the “FooBar” function in another compilation unit (from where it’s defined) you need to make sure to include its declaration. This is usually done by including a header file. It’s an error to define the same function twice in two separate compilation units however and attempting to do so will result in a link error. Since variables don’t have bodies this technique isn’t usable, thus the extern keyword:

      int FooBar; // This is a definition.
      extern int FooBar; // This is a declaration.

      Steve

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      • S Stephen Hewitt

        As I said, extern is used to indicate that a construct is a declaration and not a definition. With functions no such mechanism is needed: if the function has a body it’s a definition and if not it’s a declaration:

        int void FooBar(); // This is a declaration (no body).
        int void FooBar() // This is a definition (has body).
        {
        // Do stuff…
        }

        If you want to use the “FooBar” function in another compilation unit (from where it’s defined) you need to make sure to include its declaration. This is usually done by including a header file. It’s an error to define the same function twice in two separate compilation units however and attempting to do so will result in a link error. Since variables don’t have bodies this technique isn’t usable, thus the extern keyword:

        int FooBar; // This is a definition.
        extern int FooBar; // This is a declaration.

        Steve

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        George_George
        wrote on last edited by
        #7

        Thanks Steve, How about this, extern int i = 100; a definition or declaration, why? regards, George

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        • G George_George

          Thanks Steve, How about this, extern int i = 100; a definition or declaration, why? regards, George

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          Stephen Hewitt
          wrote on last edited by
          #8

          From section 3.1.2 of the C++ standard:  “A declaration is a definition unless it declares a function without specifying the function’s body (8.4), it contains the extern specifier (7.1.1) or a linkage-specification (7.5) and neither an initializer nor a function-body, it declares a static data member in a class declaration (9.4), it is a class name declaration (9.1), or it is a typedef declaration (7.1.3), a using-declaration (7.3.3), or a using-directive (7.3.4).”

          Steve

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          • S Stephen Hewitt

            From section 3.1.2 of the C++ standard:  “A declaration is a definition unless it declares a function without specifying the function’s body (8.4), it contains the extern specifier (7.1.1) or a linkage-specification (7.5) and neither an initializer nor a function-body, it declares a static data member in a class declaration (9.4), it is a class name declaration (9.1), or it is a typedef declaration (7.1.3), a using-declaration (7.3.3), or a using-directive (7.3.4).”

            Steve

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            George_George
            wrote on last edited by
            #9

            Thanks Steve, 1. So, extern int i = 100; should be declaration and matches the rule, " it contains the extern specifier (7.1.1)", right? 2. What is " linkage-specification (7.5)"? regards, George

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            • G George_George

              Hello everyone, I think in practical experience, extern is useful only when we have more than one compile unit (cpp file) and making cross-reference between compile units. In the MSDN extern sample, http://msdn2.microsoft.com/en-us/library/0603949d.aspx It only uses one source file (compile unit) to demonstrate the usage of extern, is it correct and practical? thanks in advance, George

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              Hamid Taebi
              wrote on last edited by
              #10

              I think this[^] article is helpful for you.

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              • H Hamid Taebi

                I think this[^] article is helpful for you.

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                George_George
                wrote on last edited by
                #11

                Thanks Hamid, But it does not cover the case when using extern to qualify a variable which is defined in the same compile unit. :-) regards, George

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                • G George_George

                  Thanks Steve, 1. So, extern int i = 100; should be declaration and matches the rule, " it contains the extern specifier (7.1.1)", right? 2. What is " linkage-specification (7.5)"? regards, George

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                  Stephen Hewitt
                  wrote on last edited by
                  #12

                  George_George wrote:

                  1. So, extern int i = 100; should be declaration and matches the rule, " it contains the extern specifier (7.1.1)", right?

                  No, because of the "and neither an initializer nor a function-body" clause; the example you gave does have an initializer.

                  extern int i; // This is a declaration.
                  extern int i = 100; // This contains an initializer and thus is a definition (and a declaration).

                  George_George wrote:

                  2. What is " linkage-specification (7.5)"?

                  extern "C" is an example.

                  Steve

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                  • G George_George

                    Thanks Hamid, But it does not cover the case when using extern to qualify a variable which is defined in the same compile unit. :-) regards, George

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                    Stephen Hewitt
                    wrote on last edited by
                    #13

                    Doing so is poinless and possibly misleading, but harmless.

                    Steve

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                    • S Stephen Hewitt

                      George_George wrote:

                      1. So, extern int i = 100; should be declaration and matches the rule, " it contains the extern specifier (7.1.1)", right?

                      No, because of the "and neither an initializer nor a function-body" clause; the example you gave does have an initializer.

                      extern int i; // This is a declaration.
                      extern int i = 100; // This contains an initializer and thus is a definition (and a declaration).

                      George_George wrote:

                      2. What is " linkage-specification (7.5)"?

                      extern "C" is an example.

                      Steve

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                      George_George
                      wrote on last edited by
                      #14

                      Thanks Stephen, Any special advantage/restrictions/functions we could have when writing extern int i = 3 other than int i = 3? (I think you mean extern int i = 3 has the same meaning as int i = 3, which is definition with initialization. right?) regards, George

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                      • G George_George

                        Thanks Stephen, Any special advantage/restrictions/functions we could have when writing extern int i = 3 other than int i = 3? (I think you mean extern int i = 3 has the same meaning as int i = 3, which is definition with initialization. right?) regards, George

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                        Stephen Hewitt
                        wrote on last edited by
                        #15

                        There is no reason to do so (use extern) in such cases. Doing so does neither harm nor good; the two constructs are equivalent. I wouldn’t in cases like that however as it could lead to confusion.

                        Steve

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                        • S Stephen Hewitt

                          There is no reason to do so (use extern) in such cases. Doing so does neither harm nor good; the two constructs are equivalent. I wouldn’t in cases like that however as it could lead to confusion.

                          Steve

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                          George_George
                          wrote on last edited by
                          #16

                          Thanks Steve, My question is answered. regards, George

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