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  4. convert color image to grayscale image ?

convert color image to grayscale image ?

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  • G gentleguy

    dear all howt to convert color image to grayscale image in c++? anyone has such code? thanks a lot

    Li Zhiyuan

    I Offline
    I Offline
    Iain Clarke Warrior Programmer
    wrote on last edited by
    #2

    There are several articles on codeproject about turning RGB colours into HSL (hue, saturation, luminence) colours - and to get grey scale, you can just extract the luminence component for your needs. Or search for rgb and grayscale on codeproject for some other mentions of your problem; http://www.google.com/search?hl=en&q=rgb+grayscale+%2Bsite%3Acodeproject.com&btnG=Search[^] (Some people may spell it greyscale too. Good luck, Iain.

    Iain Clarke appearing in spite of being begged not to by CPallini.

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    • G gentleguy

      dear all howt to convert color image to grayscale image in c++? anyone has such code? thanks a lot

      Li Zhiyuan

      CPalliniC Offline
      CPalliniC Offline
      CPallini
      wrote on last edited by
      #3

      Can't you simply average the color components, i.e.

      COLORREF color, gray;
      //...
      BYTE avg = (GetRValue(color) + GetGValue(color) + GetBValue(color))/3;
      gray = RGB(avg, avg, avg);

      ?

      If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
      This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke

      In testa che avete, signor di Ceprano?

      R 1 Reply Last reply
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      • CPalliniC CPallini

        Can't you simply average the color components, i.e.

        COLORREF color, gray;
        //...
        BYTE avg = (GetRValue(color) + GetGValue(color) + GetBValue(color))/3;
        gray = RGB(avg, avg, avg);

        ?

        If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
        This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke

        R Offline
        R Offline
        Rajkumar R
        wrote on last edited by
        #4

        then (R = 100, G = 0, B = 0) and (R= 0, G =100, B = 0) and (R=0, g= 0, b= 100) all gives the same value, that is if the image has 3 region each filled with Red, Green, Blue respectively, then the whole image has same gray value (can't identify the regions)

        modified on Thursday, February 21, 2008 5:06 AM

        CPalliniC 1 Reply Last reply
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        • R Rajkumar R

          then (R = 100, G = 0, B = 0) and (R= 0, G =100, B = 0) and (R=0, g= 0, b= 100) all gives the same value, that is if the image has 3 region each filled with Red, Green, Blue respectively, then the whole image has same gray value (can't identify the regions)

          modified on Thursday, February 21, 2008 5:06 AM

          CPalliniC Offline
          CPalliniC Offline
          CPallini
          wrote on last edited by
          #5

          Color to Gray space conversion is lossy by definition: RGB Color space allows 2^24 different values for color image pixels, while the constraint RGB(x,x,x) implies 2^8 different values for gray pixels. Thus we have a mapping of a 2^24 set to 2^8 set, i.e. a lossy mapping. Average is a very simple method to obtain a grayscale image, maybe also a naive (though working) one, but the lossy nature of the conversion is unavoidable. :)

          If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
          This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke

          In testa che avete, signor di Ceprano?

          R 1 Reply Last reply
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          • CPalliniC CPallini

            Color to Gray space conversion is lossy by definition: RGB Color space allows 2^24 different values for color image pixels, while the constraint RGB(x,x,x) implies 2^8 different values for gray pixels. Thus we have a mapping of a 2^24 set to 2^8 set, i.e. a lossy mapping. Average is a very simple method to obtain a grayscale image, maybe also a naive (though working) one, but the lossy nature of the conversion is unavoidable. :)

            If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
            This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke

            R Offline
            R Offline
            Rajkumar R
            wrote on last edited by
            #6

            I know that. but averaging u meantion cannot differentiate even very distinct colours RED, GREEN, BLUE. I personally don't believe that averaging is a solution. eventhough the actual solution is some sort of weighted average :)

            modified on Thursday, February 21, 2008 5:52 AM

            CPalliniC 1 Reply Last reply
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            • R Rajkumar R

              I know that. but averaging u meantion cannot differentiate even very distinct colours RED, GREEN, BLUE. I personally don't believe that averaging is a solution. eventhough the actual solution is some sort of weighted average :)

              modified on Thursday, February 21, 2008 5:52 AM

              CPalliniC Offline
              CPalliniC Offline
              CPallini
              wrote on last edited by
              #7

              Rajkumar R wrote:

              but averaging u meantion cannot differentiate even very distinct colours RED, GREEN, BLUE.

              The above is obviously true.

              Rajkumar R wrote:

              I personally don't believe averaging is a solution.

              You're wrong. It is a quite acceptable solution, because (as I've already written) is a function mapping the color space set to the the grayspace one. It is also a reasonable mapping. Of course there are many possible solutions and the better one maybe application-dependent. Now a simple question: are you able to distinguish a full red from a full green in a B/W movie? Does it matter to the Director? :)

              If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
              This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke

              In testa che avete, signor di Ceprano?

              R 1 Reply Last reply
              0
              • CPalliniC CPallini

                Rajkumar R wrote:

                but averaging u meantion cannot differentiate even very distinct colours RED, GREEN, BLUE.

                The above is obviously true.

                Rajkumar R wrote:

                I personally don't believe averaging is a solution.

                You're wrong. It is a quite acceptable solution, because (as I've already written) is a function mapping the color space set to the the grayspace one. It is also a reasonable mapping. Of course there are many possible solutions and the better one maybe application-dependent. Now a simple question: are you able to distinguish a full red from a full green in a B/W movie? Does it matter to the Director? :)

                If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke

                R Offline
                R Offline
                Rajkumar R
                wrote on last edited by
                #8

                CPallini wrote:

                distinguish a full red from a full green in a B/W movie? Does it matter to the Director?

                lol !!! :laugh: , instead he can put black screen, save light energy. :)

                G 1 Reply Last reply
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                • R Rajkumar R

                  CPallini wrote:

                  distinguish a full red from a full green in a B/W movie? Does it matter to the Director?

                  lol !!! :laugh: , instead he can put black screen, save light energy. :)

                  G Offline
                  G Offline
                  gentleguy
                  wrote on last edited by
                  #9

                  thanks all friends how to blur or mask a color image, actually i load a jpeg image to computer, now i would like to smooth via Gaussion function, but one of friend said i have to convert color image to grayscale image and then i can blur, so now i don't how to do? anyone has such code or suggestion? thanks a lot

                  Li Zhiyuan

                  R 1 Reply Last reply
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                  • G gentleguy

                    dear all howt to convert color image to grayscale image in c++? anyone has such code? thanks a lot

                    Li Zhiyuan

                    S Offline
                    S Offline
                    swarup
                    wrote on last edited by
                    #10

                    search for "MakeInactiveDemo" in codeproject he has a function to convert image to grayscale

                    G 1 Reply Last reply
                    0
                    • G gentleguy

                      thanks all friends how to blur or mask a color image, actually i load a jpeg image to computer, now i would like to smooth via Gaussion function, but one of friend said i have to convert color image to grayscale image and then i can blur, so now i don't how to do? anyone has such code or suggestion? thanks a lot

                      Li Zhiyuan

                      R Offline
                      R Offline
                      Rajkumar R
                      wrote on last edited by
                      #11

                      Image Processing for Dummies with C# and GDI+ Part 2 - Convolution Filters [^] although written in C#, it is easy to understand the gaussian blur implementation, i think it is not converting to greyscale before blur.

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                      • S swarup

                        search for "MakeInactiveDemo" in codeproject he has a function to convert image to grayscale

                        G Offline
                        G Offline
                        gentleguy
                        wrote on last edited by
                        #12

                        thanks friend anyone know how to convolution of image? i have a little problem of concept, how to multiply two arrays? and how to put new value in new array, thanks a lot, urgent

                        Li Zhiyuan

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