tree node in datalist
-
i have a treeview , which contains four root nodes , each node contains it's sub nodes , i want to display each root nodes along with it's sub nodes seperately in datalist. I mean datalist will have four template columns .How should i do it?
Yesterday is a canceled check. Tomorrow is a promissory note. Today is the ready cash. USE IT.
-
i have a treeview , which contains four root nodes , each node contains it's sub nodes , i want to display each root nodes along with it's sub nodes seperately in datalist. I mean datalist will have four template columns .How should i do it?
Yesterday is a canceled check. Tomorrow is a promissory note. Today is the ready cash. USE IT.
The obvious way would be to reshape the data from the data source so it represents a table in the format you want, and then bind to it.
Christian Graus Please read this if you don't understand the answer I've given you "also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )