Passing Variable to Parent form
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If you call ShowDialog, it's modal. IF you call Show, so the parent form stays active, it's modeless, and that's why you need a delegate. If your main form code stops when you show the child, your main form code knows when the otehr form ends it's life, so you can examine it's state. If you called Show, you don't know when the child form has something to tell you, a delegate lets the form tell you. If you call Hide, then you're calling Show, I guess. Otherwise, your modal form would freeze your application. A login form has to be modal, or there's no point. A properties form, would be modeless, you change properties and see the results in the main form. Just some examples.
Christian Graus Please read this if you don't understand the answer I've given you "also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
Oh, so inside my FrmMain_Load(), i tried set my childLogin to ShowDialog i get this error "Form that is not a top-level form cannot be displayed as a modal dialog box. Remove the form from any parent form before calling showDialog." private void FrmMain_Load(object sender, EventArgs e) { this.toolStripStaff.Visible = false; this.toolStripCatalogue.Visible = false; this.toolStripProduct.Visible = false; this.toolStripOrder.Visible = false; this.toolStripInventory.Visible = false; FrmLogin childLogin = new FrmLogin(); childLogin.MdiParent = this; childLogin.ShowDialog(); stripLblLoginAs.Text = "Login As :"; }
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Oh, so inside my FrmMain_Load(), i tried set my childLogin to ShowDialog i get this error "Form that is not a top-level form cannot be displayed as a modal dialog box. Remove the form from any parent form before calling showDialog." private void FrmMain_Load(object sender, EventArgs e) { this.toolStripStaff.Visible = false; this.toolStripCatalogue.Visible = false; this.toolStripProduct.Visible = false; this.toolStripOrder.Visible = false; this.toolStripInventory.Visible = false; FrmLogin childLogin = new FrmLogin(); childLogin.MdiParent = this; childLogin.ShowDialog(); stripLblLoginAs.Text = "Login As :"; }
benjamin yap wrote:
childLogin.MdiParent = this;
This is why you can't do it. Get rid of this line, it makes no sense to have it. Set te Owner property instead ( or Parent, I forget which, but I think it's Owner you want ). This stops your modal form from ever being hidden by it's parent.
benjamin yap wrote:
stripLblLoginAs.Text = "Login As :";
This is going to occur *after* your login form has shown. Now the easy easy way to make this work is to set the DIalogResult to DialogResult.OK only if the login succeeds. Then you can do if (childLogin.ShowDialog() == DialogResult.OK) { // logged in } else { // failed, close the program or whatever }
Christian Graus Please read this if you don't understand the answer I've given you "also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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Oh, so inside my FrmMain_Load(), i tried set my childLogin to ShowDialog i get this error "Form that is not a top-level form cannot be displayed as a modal dialog box. Remove the form from any parent form before calling showDialog." private void FrmMain_Load(object sender, EventArgs e) { this.toolStripStaff.Visible = false; this.toolStripCatalogue.Visible = false; this.toolStripProduct.Visible = false; this.toolStripOrder.Visible = false; this.toolStripInventory.Visible = false; FrmLogin childLogin = new FrmLogin(); childLogin.MdiParent = this; childLogin.ShowDialog(); stripLblLoginAs.Text = "Login As :"; }
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Yes, you can pass it on the constructor quite often, instead of setting it first. I know you can for a messagebox, for example.
Christian Graus Please read this if you don't understand the answer I've given you "also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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benjamin yap wrote:
childLogin.MdiParent = this;
This is why you can't do it. Get rid of this line, it makes no sense to have it. Set te Owner property instead ( or Parent, I forget which, but I think it's Owner you want ). This stops your modal form from ever being hidden by it's parent.
benjamin yap wrote:
stripLblLoginAs.Text = "Login As :";
This is going to occur *after* your login form has shown. Now the easy easy way to make this work is to set the DIalogResult to DialogResult.OK only if the login succeeds. Then you can do if (childLogin.ShowDialog() == DialogResult.OK) { // logged in } else { // failed, close the program or whatever }
Christian Graus Please read this if you don't understand the answer I've given you "also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
Christian, i am very sorry for asking so many question, I just started c# few days ago. Please bear with me childLogin.MdiParent = this; --> i though this is to link to the parent form? How do i set to owner property?
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It also breaches one of the tenets of Object Oriented programming.
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Christian, i am very sorry for asking so many question, I just started c# few days ago. Please bear with me childLogin.MdiParent = this; --> i though this is to link to the parent form? How do i set to owner property?
This is a link in an MDI form, I've never used it and it apparently only works to create child forms within an MDI app. childLogin.Owner = this; will do what you want.
Christian Graus Please read this if you don't understand the answer I've given you "also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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Christian, i am very sorry for asking so many question, I just started c# few days ago. Please bear with me childLogin.MdiParent = this; --> i though this is to link to the parent form? How do i set to owner property?
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A dialog is not a MdiChild, so childLogin.MdiParent = this; can be ignored. According to my experience:
childForm child=new childForm(); child.ShowDialog(parent);works. My code and I is not professional. take careful advantage.hmm after i remove that line, and set to owner property, i get this error when i press the login button else if ((txtUsername.Text == username) && (txtPassword.Text == password)) { FrmMain frmMain = (FrmMain)this.MdiParent; frmMain.toolStripStaff.Visible = true; <----ERROR HERE this.Hide(); } Object reference not set to an instance of an object.
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hmm after i remove that line, and set to owner property, i get this error when i press the login button else if ((txtUsername.Text == username) && (txtPassword.Text == password)) { FrmMain frmMain = (FrmMain)this.MdiParent; frmMain.toolStripStaff.Visible = true; <----ERROR HERE this.Hide(); } Object reference not set to an instance of an object.
FrmMain frmMain = (FrmMain)this.MdiParent your login form doesn't have a parent, so the frmMain will be null when running. try this: in main form: LoginForm login=new LoginForm(); login.ShowDialog(this); if (login.DialogResult==DialogResult.OK) { this.toolStripStaff.Visible = true; ........ in login form: else if ((txtUsername.Text == username) && (txtPassword.Text == password)) { this.DialogResult=DialogResult.OK; ........
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Hi, i have a login form as a child form. I want to pass the value txtUsername to the parent form. How do i do it?
You can in your child form's constructor set a field to the opener of it, then at anytime call any method on that form using its reference called. ex:
class Parent
{
public void Anymethod(){}
public Parent()
{
Child c = new Child(this);
}
}
class Child
{
private Form Owner;
public Child(Form f)
{Owner = f;}
public void CallParent()
{
Owner.AnyMEthod();
}
} -
FrmMain frmMain = (FrmMain)this.MdiParent your login form doesn't have a parent, so the frmMain will be null when running. try this: in main form: LoginForm login=new LoginForm(); login.ShowDialog(this); if (login.DialogResult==DialogResult.OK) { this.toolStripStaff.Visible = true; ........ in login form: else if ((txtUsername.Text == username) && (txtPassword.Text == password)) { this.DialogResult=DialogResult.OK; ........
Great! Thanks alot! So how do i pass the value of the txtUsername inside my Login to my statusstrip at my mainform stripLblLoginAs.Text = "Login As :" + login.txtUsername.Text;
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Great! Thanks alot! So how do i pass the value of the txtUsername inside my Login to my statusstrip at my mainform stripLblLoginAs.Text = "Login As :" + login.txtUsername.Text;