how to calculate all columns amount? [modified]

[gentleguy]

thanks for your reply,actually i load one image which is binary image, actually the data is 2_D array. this is about my work...not homework, i am doing projection histogram, so i need to collect each column 255 amound. i am not good in c++..learning...so if possible, pls help me. thanks a lot

gentleguy

[gentleguy]

thanks for reply, for me maybe i have 400 or 700 hundrads columns,i load binary image, maybe 300x600 or evern big than this one... i am a newbie, can give me examlpe.thanks

gentleguy

[Saurabh Garg]

Can you tell us how do you declare this 2D array? I will give you a hint for static 2D array in C++.

int array[100][100];
int count[100];       // There are 100 columns.

for(int i=0 ; i<100 ; ++i)
{
    count[i] = 0;
}

for(int i=0 ; i<100 ; ++i)
{
    for(int j=0 ; j<100 ; ++j)
    {
        if(array[i][j] == 255)
        {
            count[j]++;
        }
    }
}

Hope this helps. -Saurabh

[Iain Clarke Warrior Programmer]

So, you have a block of bytes, and you know it is W wide, and H high. First - images often have the width padded by 4. Check whether this is the case or not.

void Count255s (BYTE *blob, UINT W, UINT H)
{
UINT nColumnCounts [W]; // W columns...
UINT x,y;

// clear counts.

= 0;

for (y = 0; y < H; y++)
{
for (x = 0; x < W; x++)
{
if (blob [x + y*W] == 255)

+= 1;

}
}

// now we have counts!
DoSomethingwithCounts (W, nColumnCounts);

}

There's no error checking, and there are more efficient ways of doing this, but this should be fairly clear for you, I hope. You could replace the check with:

    if (\*blob++ == 255)

to remove the expensive multiplication, but I'd avoid that unless you are very happy with pointers. Did that help at all? Iain.

Plz sir... CPallini CPallini abuz drugz, plz plz help urgent.

[gentleguy]

thanks a lot. very helpful, how can i save each column amount? thanks, sorry ask many by the way, why you use the third for loop? don't understnad.could you give me any explanation. thanks a lot

gentleguy

modified on Thursday, June 26, 2008 7:50 AM

[Iain Clarke Warrior Programmer]

1st for loop is to zero out all the counts. I put the action bit on the same line as the loops, which might have been a bad idea... 2nd and 3rd loops are going through the x,y coords of your data. If you were just looking for the grand total of 255s, you could have done it in one. But as you need to keep track of which column you're on, you need a 2D loop pair. As for saving the column amount - however you like. If you just take my code and use it, you're in trouble. It's there to help you write your own. The answer to your question depends on your application, and how you put data into your histogram. You could create a CArray, and pass a pointer or reference to it to the count function, then the results would be available outside the function. Or you could have a CHistogram::InitialiseFromBitmapData function, and keep the results internally. Or... lots more choices. Iain.

Plz sir... CPallini CPallini abuz drugz, plz plz help urgent.

[gentleguy]

thanks a lot. here i will explain to you something, when i calculate 255 for each column, i just can start to scan my data(2-D) from left bottom, and then up row by row,do you understand me? thanks a lot, and disturb you a lot.

gentleguy

[Iain Clarke Warrior Programmer]

gentleguy wrote:

do you understand me?

Not really... The code I showed assumed that the data was row after row - I didn't assume whether I was starting with top left or bottom left - I've seen bitmap formats of both kind. If your data is stored differently, you can change the maths inside the [ and ] to look it up differently. Good luck, Iain.

Plz sir... CPallini CPallini abuz drugz, plz plz help urgent.

[Hamid Taebi]

Can you use of Listctrl?

[gentleguy]

thanks for your help, my data is from binary image, different binary image has different dimension, when i load one 2-D binary image, depend on image size, but i can obtain width and height of image via access image definition. do you understand me? i can declare a 2-D dinamic array.thanks

unsigned char *ucImgdata1 =m_vicImg.ibuff;
int iWidth1 = m_vicImg.endx-m_vicImg.stx+1;
int iHeight1 = m_vicImg.endy-m_vicImg.sty+1;
int iWidthbyte1=m_vicImg.buffwidth;
int *nColumnCounts=new int[iWidth1];

for (int i=0;i<iwidth1;iwidth1;i++)
{
	nColumnCounts\[i\]=0;
}
for(int iY=0;iY<iheight;iheight1;iy++)
{
	for(int iX=0;iX<iwidth1;iwidth1;ix++)
	{
		
		if (imgArray \[iX+iY\*iwidth1\] == 255)          
		{
			
			nColumnCounts\[iX\]++;  
			
			FILE\* stream;
			stream=fopen("C:\\\\TestArray.txt","w");
			fprintf(stream," Array=%d\\n",nColumnCounts\[iX\]);
			fclose(stream);
		}
	}

but i couldn't get the correct result. i would like to get one array including how many amount of 255 for each column.help me,thanks.

gentleguy

modified on Sunday, June 29, 2008 4:53 AM

[gentleguy]

i am not sure for this. i tried many times, still couldn't finish it. do you have any other idea, thanks

gentleguy

[gentleguy]

thanks a lot, i still get the correct result. but my data format is a little different. the detail is following:

unsigned char *ucImgdata1 =m_vicImg.ibuff;
int iWidth1 = m_vicImg.endx-m_vicImg.stx+1;
int iHeight1 = m_vicImg.endy-m_vicImg.sty+1;
int iWidthbyte1=m_vicImg.buffwidth;
int *nColumnCounts=new int[iWidth1];
for (int i=0;i<iwidth1;i++)
{ nColumnCounts[i]=0;
}
for(int iY=0;iY<iheight1;iy++)
{
for(int iX=0;iX<iwidth1;ix++)
{
if (imgArray [iX+iY*iWidth1] == 255)
{
nColumnCounts[iX]++;
FILE* stream;
stream=fopen("C:\\TestArray.txt","w");
fprintf(stream," Array=%d\n",nColumnCounts[iX]);
fclose(stream);
}
}
}

could help me? thanks

gentleguy