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  4. problem creating textbox on the fly

problem creating textbox on the fly

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  • N Nirandas

    Cann't you use Repeater or DataGrid for this? That will be more simpler. Any way, you will have to create as many Literal Controls as there are textboxs and put it between textboxs to insert some text/html markup between them. You can take out the code inside the button's click and put it in a method and call it from both the page_load and the button_click.

    Nirandas, a developer from India. http://www.nirandas.com

    E Offline
    E Offline
    eyeseetee
    wrote on last edited by
    #8

    ive tried putting
    after the tb.Text = row["fieldname"].ToString() + "
    "; but this doesnt work.

    modified on Tuesday, July 8, 2008 9:04 AM

    N 1 Reply Last reply
    0
    • E eyeseetee

      ive tried putting
      after the tb.Text = row["fieldname"].ToString() + "
      "; but this doesnt work.

      modified on Tuesday, July 8, 2008 9:04 AM

      N Offline
      N Offline
      Nirandas
      wrote on last edited by
      #9

      That would not work as your appending text to the textbox, and browser will not parse it while rendering. As I said, creating literal controls and adding them between textboxs is the way to go if you don't want to use repeater/Datagrid. Can you paste the code which you are using to add these textboxs to the page? Then I may be able to suggest the code to you.

      Nirandas, a developer from India. http://www.nirandas.com

      E 1 Reply Last reply
      0
      • N Nirandas

        That would not work as your appending text to the textbox, and browser will not parse it while rendering. As I said, creating literal controls and adding them between textboxs is the way to go if you don't want to use repeater/Datagrid. Can you paste the code which you are using to add these textboxs to the page? Then I may be able to suggest the code to you.

        Nirandas, a developer from India. http://www.nirandas.com

        E Offline
        E Offline
        eyeseetee
        wrote on last edited by
        #10

        foreach (DataRow row in dataSetselect.Tables[0].Rows) { lb = new Label(); tb = new TextBox(); lb.Text = row["field"].ToString(); tb.Text = row["field"].ToString(); TextBoxesHere.Controls.Add(lb); TextBoxesHere.Controls.Add(tb); } thanks it would need to go somewhere in there

        N 1 Reply Last reply
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        • E eyeseetee

          foreach (DataRow row in dataSetselect.Tables[0].Rows) { lb = new Label(); tb = new TextBox(); lb.Text = row["field"].ToString(); tb.Text = row["field"].ToString(); TextBoxesHere.Controls.Add(lb); TextBoxesHere.Controls.Add(tb); } thanks it would need to go somewhere in there

          N Offline
          N Offline
          Nirandas
          wrote on last edited by
          #11

          Change the line

          lb.Text = row["field"].ToString();

          to

          lb.Text = "
          " + row["field"].ToString();

          This will add a line break before every label. HTH

          Nirandas, a developer from India. http://www.nirandas.com

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          • N Nirandas

            Change the line

            lb.Text = row["field"].ToString();

            to

            lb.Text = "
            " + row["field"].ToString();

            This will add a line break before every label. HTH

            Nirandas, a developer from India. http://www.nirandas.com

            E Offline
            E Offline
            eyeseetee
            wrote on last edited by
            #12

            it throws up an error: should it be like: lb.Text = " " + row["field"].ToString(); or lb.Text = "" + row["field"].ToString();

            N 1 Reply Last reply
            0
            • E eyeseetee

              it throws up an error: should it be like: lb.Text = " " + row["field"].ToString(); or lb.Text = "" + row["field"].ToString();

              N Offline
              N Offline
              Nirandas
              wrote on last edited by
              #13

              The complete statement should be in a single line. And the quotes should not be empty, it should contain <br /> The line will be:

              lb.Text = "<br />" + row["field"].ToString();

              I didn't formatted the code correctly last time, sorry. You can insert any html markup there, since you want a line break, use <br /> Goodluck.

              Nirandas, a developer from India. http://www.nirandas.com

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              • N Nirandas

                The complete statement should be in a single line. And the quotes should not be empty, it should contain <br /> The line will be:

                lb.Text = "<br />" + row["field"].ToString();

                I didn't formatted the code correctly last time, sorry. You can insert any html markup there, since you want a line break, use <br /> Goodluck.

                Nirandas, a developer from India. http://www.nirandas.com

                E Offline
                E Offline
                eyeseetee
                wrote on last edited by
                #14

                No that doesn work either, all that does is put the
                in the actual textbox as text. I need to add it afterwards but not sure of the syntax Thanks anyway

                S 1 Reply Last reply
                0
                • E eyeseetee

                  I am trying to create a function which creates a certain amount of textboxes depending on how many are in the datatable. I have the following code so far: foreach (DataRow row in dataSetselectactivities.Tables[0].Rows) { TextBox tb = new TextBox(); tb.Visible = true; } but how would I add a new value to the textbox for each row, would it be something like tb.text += dttablevalue any help would be great thanks

                  N Offline
                  N Offline
                  Nirandas
                  wrote on last edited by
                  #15

                  I am pasting the complete code:

                  foreach (DataRow row in dataSetselect.Tables[0].Rows)
                  {
                  lb = new Label();
                  tb = new TextBox();
                  lb.Text = "<br />" + row["field"].ToString();
                  tb.Text = row["field"].ToString();
                  TextBoxesHere.Controls.Add(lb);
                  TextBoxesHere.Controls.Add(tb);
                  }

                  Is it the same code as what you are using?

                  Nirandas, a developer from India. http://www.nirandas.com

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                  • E eyeseetee

                    No that doesn work either, all that does is put the
                    in the actual textbox as text. I need to add it afterwards but not sure of the syntax Thanks anyway

                    S Offline
                    S Offline
                    Sherin Iranimose
                    wrote on last edited by
                    #16

                    Instead of label you can use a LiteralControl LiteralControl lit=new LiteralControl(); lit.Text="<br />" Textboxhere.controls.add(lit);

                    EVEN THE WORD IMPOSSIBLE SAYS I M POSSIBLE.

                    modified on Tuesday, July 8, 2008 11:04 AM

                    1 Reply Last reply
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                    • N Nirandas

                      I am pasting the complete code:

                      foreach (DataRow row in dataSetselect.Tables[0].Rows)
                      {
                      lb = new Label();
                      tb = new TextBox();
                      lb.Text = "<br />" + row["field"].ToString();
                      tb.Text = row["field"].ToString();
                      TextBoxesHere.Controls.Add(lb);
                      TextBoxesHere.Controls.Add(tb);
                      }

                      Is it the same code as what you are using?

                      Nirandas, a developer from India. http://www.nirandas.com

                      E Offline
                      E Offline
                      eyeseetee
                      wrote on last edited by
                      #17

                      OK I got it now, I was putting the break in the textbox not the label!! :doh: Thanks for your help in this

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