Accessing a parent class' methods

[Anthony Mushrow]

Say I have three classes, each a child of the previous. Can I explicitly call each of a classes methods that have been overridden?

class A
{
public A() { }
protected virtual void MakeLunch()
{
//Make cheese sandwich
}
}
.
class B : A
{
public B() { }
protected override void MakeLunch()
{
base.MakeLunch();
//Grab a banana
}
}
.
class C : B
{
public C() { }
protected override void MakeLunch()
{
A.MakeLunch();
//Get a drink
}
}

From class C, can I skip the banana and just get a cheese sandwich and a drink? Or do I need one of my five-a-day?

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[Ennis Ray Lynch Jr]

I wouldn't imagine you could since B overrides A C should not "know" about A. However, if B used new on MakeLunch instead then it would be possible by casting C as A.

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[Anthony Mushrow]

I don't want to do that, it would cause more complications than it would solve. Thanks anyway.

My current favourite word is: Nipple!

-SK Genius

Game Programming articles start -here[^]-

[Ennis Ray Lynch Jr]

I figured which is why I initially hesitated in responding. However, I think the reasoning is why such an action is prevented by the compiler.

Need software developed? Offering C# development all over the United States, ERL GLOBAL, Inc is the only call you will have to make.
Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway
Most of this sig is for Google, not ego.

[N a v a n e e t h]

Ennis Ray Lynch, Jr. wrote:

However, if B used new on MakeLunch instead then it would be possible by casting C as A.

But that won't work too since the MakeLunch is marked as protected. Please correct me if I am wrong.

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[Roger Alsing 0]

It does not work in C# , but it is possible at IL level. So I guess its simply a rule that prevents you to skip layers of abstraction in C#.

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[Ennis Ray Lynch Jr]

I haven't tried it but it might, since C would still be in the inheritance chain for A

Need software developed? Offering C# development all over the United States, ERL GLOBAL, Inc is the only call you will have to make.
Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway
Most of this sig is for Google, not ego.