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  4. Unresolved external symbol in a DLL

Unresolved external symbol in a DLL

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  • N Naveen

    Of course classes also :cool:

    nave [OpenedFileFinder] [My Blog]

    G Offline
    G Offline
    George_George
    wrote on last edited by
    #14

    Thanks Naveen! I have proved we could expose both class and global variable by DLL and using your mentioned elegant way. :-) But I am not 100% confident. Here is my code, could you have a code review please? DLL Part:

    // foo.h

    #ifdef _DLLPROJ_
    #define DLLEXP __declspec (dllexport)
    #else
    #define DLLEXP __declspec (dllimport)
    #endif

    DLLEXP class CFoo
    {
    public:

    DLLEXP int foo1();
    
    DLLEXP int foo2();
    

    };

    DLLEXP class CFooImpl : CFoo
    {
    public:

    DLLEXP CFooImpl();
    
    DLLEXP int foo1();
    
    DLLEXP int foo2();
    

    };

    // dllmain.cpp

    #include "foo.h"

    CFooImpl::CFooImpl()
    {
    return;
    }

    int CFooImpl::foo1()
    {
    return 100;
    }

    int CFooImpl::foo2()
    {
    return 200;
    }

    DLLEXP CFooImpl foo;

    Hosting client part

    // main.cpp

    #include "foo.h"

    DLLEXP CFooImpl foo;

    int main()
    {
    CFooImpl foo1;

    int i = foo.foo1();
    i = foo.foo2();
    
    return 0;
    

    }

    regards, George

    N S 2 Replies Last reply
    0
    • S Stuart Dootson

      You've got two issues:

      1. In main.cpp, you want to declare CFoo as __declspec(dllimport). The way I do that is to put something like this in foo.h: #if !defined(FOO_DLL) #define FOO_EXP __declspec(dllimport) #else #define FOO_EXP __declspec(dllexport) #endif class FOO_EXP CFoo { ... }; You would define FOO_DLL when building the DLL using, for example, #define FOO_DLL in every source file in the DLL before #including foo.h. You need do nothing in main.cpp>/code>, as that's what the default case caters for.
      2. As other replies have said, you would need to export CFoo foo; from the DLL.
      G Offline
      G Offline
      George_George
      wrote on last edited by
      #15

      Thanks Stuart, I have correct my code here, could you help to do a code review please? :-) http://www.codeproject.com/script/Forums/View.aspx?fid=1647&msg=2846175[^] regards, George

      1 Reply Last reply
      0
      • G George_George

        Thanks Naveen! I have proved we could expose both class and global variable by DLL and using your mentioned elegant way. :-) But I am not 100% confident. Here is my code, could you have a code review please? DLL Part:

        // foo.h

        #ifdef _DLLPROJ_
        #define DLLEXP __declspec (dllexport)
        #else
        #define DLLEXP __declspec (dllimport)
        #endif

        DLLEXP class CFoo
        {
        public:

        DLLEXP int foo1();
        
        DLLEXP int foo2();
        

        };

        DLLEXP class CFooImpl : CFoo
        {
        public:

        DLLEXP CFooImpl();
        
        DLLEXP int foo1();
        
        DLLEXP int foo2();
        

        };

        // dllmain.cpp

        #include "foo.h"

        CFooImpl::CFooImpl()
        {
        return;
        }

        int CFooImpl::foo1()
        {
        return 100;
        }

        int CFooImpl::foo2()
        {
        return 200;
        }

        DLLEXP CFooImpl foo;

        Hosting client part

        // main.cpp

        #include "foo.h"

        DLLEXP CFooImpl foo;

        int main()
        {
        CFooImpl foo1;

        int i = foo.foo1();
        i = foo.foo2();
        
        return 0;
        

        }

        regards, George

        N Offline
        N Offline
        Naveen
        wrote on last edited by
        #16

        I have noted the below problem

        George_George wrote:

        DLLEXP class CFoo

        This should be modified as class DLLEXP CFoo everthing else seems ok.

        nave [OpenedFileFinder] [My Blog]

        G 1 Reply Last reply
        0
        • G George_George

          Thanks Naveen! I have proved we could expose both class and global variable by DLL and using your mentioned elegant way. :-) But I am not 100% confident. Here is my code, could you have a code review please? DLL Part:

          // foo.h

          #ifdef _DLLPROJ_
          #define DLLEXP __declspec (dllexport)
          #else
          #define DLLEXP __declspec (dllimport)
          #endif

          DLLEXP class CFoo
          {
          public:

          DLLEXP int foo1();
          
          DLLEXP int foo2();
          

          };

          DLLEXP class CFooImpl : CFoo
          {
          public:

          DLLEXP CFooImpl();
          
          DLLEXP int foo1();
          
          DLLEXP int foo2();
          

          };

          // dllmain.cpp

          #include "foo.h"

          CFooImpl::CFooImpl()
          {
          return;
          }

          int CFooImpl::foo1()
          {
          return 100;
          }

          int CFooImpl::foo2()
          {
          return 200;
          }

          DLLEXP CFooImpl foo;

          Hosting client part

          // main.cpp

          #include "foo.h"

          DLLEXP CFooImpl foo;

          int main()
          {
          CFooImpl foo1;

          int i = foo.foo1();
          i = foo.foo2();
          
          return 0;
          

          }

          regards, George

          S Offline
          S Offline
          Stuart Dootson
          wrote on last edited by
          #17

          Aside from the issue Naveen showed you, IIRC you don't need to DLLEXP the class and the classes methods - one or the other, that's all that's needed really. I tend to DLLEXP the methods, as you have better control over what precisely is exported.

          G 1 Reply Last reply
          0
          • N Naveen

            I have noted the below problem

            George_George wrote:

            DLLEXP class CFoo

            This should be modified as class DLLEXP CFoo everthing else seems ok.

            nave [OpenedFileFinder] [My Blog]

            G Offline
            G Offline
            George_George
            wrote on last edited by
            #18

            I think they should be the same? It compiles and runs well in VS. :-) regards, George

            1 Reply Last reply
            0
            • S Stuart Dootson

              Aside from the issue Naveen showed you, IIRC you don't need to DLLEXP the class and the classes methods - one or the other, that's all that's needed really. I tend to DLLEXP the methods, as you have better control over what precisely is exported.

              G Offline
              G Offline
              George_George
              wrote on last edited by
              #19

              Hi Stuart, I have tried that if I only mark dllexport on class and not on methods, the methods could not be found during link process. So, I think we have to mark both. Could you have a try please? regards, George

              S 1 Reply Last reply
              0
              • G George_George

                Hi Stuart, I have tried that if I only mark dllexport on class and not on methods, the methods could not be found during link process. So, I think we have to mark both. Could you have a try please? regards, George

                S Offline
                S Offline
                Stuart Dootson
                wrote on last edited by
                #20

                I have an awful lot of deployed code that uses this mechanism - here's a sample: #if!defined(COMMONLIB_API) #ifdef COMMONLIB_EXPORTS #define COMMONLIB_API __declspec(dllexport) #else #define COMMONLIB_API __declspec(dllimport) #endif #endif namespace MyAppLibrary { class MessageReporter { public: //ctor COMMONLIB_API MessageReporter(); //Add new reporting function COMMONLIB_API static void AddReportFunction(ReportFnPtr func); //Set MessageReporter Level on or off COMMONLIB_API static void SetReporterLevel(Level lev, bool on); //Set all levels to on COMMONLIB_API static void AllLevelsOn() {repLevels=~0;} //Set all levels to off COMMONLIB_API static void AllLevelsOff() {repLevels=0;} }; }; Is it possible you haven't exported necessary constructors?

                G 1 Reply Last reply
                0
                • S Stuart Dootson

                  I have an awful lot of deployed code that uses this mechanism - here's a sample: #if!defined(COMMONLIB_API) #ifdef COMMONLIB_EXPORTS #define COMMONLIB_API __declspec(dllexport) #else #define COMMONLIB_API __declspec(dllimport) #endif #endif namespace MyAppLibrary { class MessageReporter { public: //ctor COMMONLIB_API MessageReporter(); //Add new reporting function COMMONLIB_API static void AddReportFunction(ReportFnPtr func); //Set MessageReporter Level on or off COMMONLIB_API static void SetReporterLevel(Level lev, bool on); //Set all levels to on COMMONLIB_API static void AllLevelsOn() {repLevels=~0;} //Set all levels to off COMMONLIB_API static void AllLevelsOff() {repLevels=0;} }; }; Is it possible you haven't exported necessary constructors?

                  G Offline
                  G Offline
                  George_George
                  wrote on last edited by
                  #21

                  But if you only expose class not expose methods, the methods could not be found when linking the client of the DLL (link error, unresolved symbols related to the methods). Could you have a try? I have tried. regards, George

                  S 1 Reply Last reply
                  0
                  • G George_George

                    But if you only expose class not expose methods, the methods could not be found when linking the client of the DLL (link error, unresolved symbols related to the methods). Could you have a try? I have tried. regards, George

                    S Offline
                    S Offline
                    Stuart Dootson
                    wrote on last edited by
                    #22

                    DLL interface defined in a.h

                    a.h

                    #if !defined(__A_H__) #define __A_H__ #if!defined(A_API) #ifdef A_EXPORTS #define A_API __declspec(dllexport) #else #define A_API __declspec(dllimport) #endif #endif class A_API A { public: A(); A(int a); void DoSomething(int b); int Result() const; private: int a_; }; #endif // !defined(__A_H__) DLL implemented in a.cpp and built with cl -EHsc -LD a.cpp

                    a.cpp

                    #include <windows.h> #define A_EXPORTS #include "a.h" BOOL APIENTRY DllMain( HANDLE hModule, DWORD ul_reason_for_call, LPVOID lpReserved ) { return TRUE; } A::A() : a_(0) {} A::A(int a) : a_(a) {} void A::DoSomething(int b) { a_ += b; } int A::Result() const { return a_; }
                    DLL used in b.cpp, built with cl -EHsc b.cpp a.lib:

                    b.cpp

                    #include <iostream> #include "a.h" int main(int argc, char** argv) { A a(argc); a.DoSomething(3); std::cout << a.Result() << std::endl; } Builds fine, runs OK and even produces the right result...which is nice.

                    modified on Saturday, December 20, 2008 6:19 AM

                    G 1 Reply Last reply
                    0
                    • S Stuart Dootson

                      DLL interface defined in a.h

                      a.h

                      #if !defined(__A_H__) #define __A_H__ #if!defined(A_API) #ifdef A_EXPORTS #define A_API __declspec(dllexport) #else #define A_API __declspec(dllimport) #endif #endif class A_API A { public: A(); A(int a); void DoSomething(int b); int Result() const; private: int a_; }; #endif // !defined(__A_H__) DLL implemented in a.cpp and built with cl -EHsc -LD a.cpp

                      a.cpp

                      #include <windows.h> #define A_EXPORTS #include "a.h" BOOL APIENTRY DllMain( HANDLE hModule, DWORD ul_reason_for_call, LPVOID lpReserved ) { return TRUE; } A::A() : a_(0) {} A::A(int a) : a_(a) {} void A::DoSomething(int b) { a_ += b; } int A::Result() const { return a_; }
                      DLL used in b.cpp, built with cl -EHsc b.cpp a.lib:

                      b.cpp

                      #include <iostream> #include "a.h" int main(int argc, char** argv) { A a(argc); a.DoSomething(3); std::cout << a.Result() << std::endl; } Builds fine, runs OK and even produces the right result...which is nice.

                      modified on Saturday, December 20, 2008 6:19 AM

                      G Offline
                      G Offline
                      George_George
                      wrote on last edited by
                      #23

                      Cool, Stuart! regards, George

                      1 Reply Last reply
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