Copy File From One Location To Another + Urgent + Sourabh Das

Dot Net Jantu

Hi All, After A long time.. Hope u all are good.. I am having btnUpload and btnTransfer. On btnUpload I open a openFileDialogue select any type of file and at transfer i want to transfer it to another location suppose D:\TransferTest\. But its giving this error Could not find a part of the path 'D:\TransferTest\'. The code is as below :

Dim filename As String
Dim ofd As OpenFileDialog

Private Sub btnUpload\_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnUpload.Click
    ofd = New OpenFileDialog()
    ofd.Filter = "All Files|\*.\*"
    ofd.ShowDialog()
    If ofd.ShowDialog() = Windows.Forms.DialogResult.OK Then
        filename = ofd.FileName()
        txtFile.Text = filename
    End If
End Sub

Private Sub btnTransfer\_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnTransfer.Click
    File.Copy(filename, "D:\\TransferTest\\")
End Sub

Help with a code tip... its a urgent.. Regards, Sourabh

Thanks and Regards,

kriskomar

Try using the new filesystem namespace: FileSystem.FileCopy(filename, "D:\TransferTest\")

Luc Pattyn

Hi, in Windows you can only create/move/copy files to existing folders, so if either D:\ or D:\TransferTest\ does not exist, you would get such error. You should use Directory.CreateDirectory() to create a folder (no need to test for existence first!). :)

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Private Sub btnTransfer_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnTransfer.Click if not io.directory.exists("D:\TransferTest\") then io.directory.createdirectory("D:\Tran.....") enf if File.Copy(filename, "D:\TransferTest\") End Sub

Luc Pattyn

so far for "no need to test for existence"... :)

Luc Pattyn [Forum Guidelines] [My Articles]

- before you ask a question here, search CodeProject, then Google - the quality and detail of your question reflects on the effectiveness of the help you are likely to get - use the code block button (PRE tags) to preserve formatting when showing multi-line code snippets