how to open a form when click on custom property item in propertygridview.
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i am adding one custom property to textbox.when i click on this item i need to show one form (like popup window).and this form having one textbox and one button..after entering the text in textbox and click on ok button.i need to display the text in this custom property item.. please any one help me.
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i am adding one custom property to textbox.when i click on this item i need to show one form (like popup window).and this form having one textbox and one button..after entering the text in textbox and click on ok button.i need to display the text in this custom property item.. please any one help me.
How do you add the custom property to textbox? Do you mean inherite from textbox control? If so, just register the click event of OK button from the custom control. Then you write the code to update the property.
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