Question about classes in C++

[akirilov]

Hi guys, I have 2 classes:

class A{
virtual void Paint() {...}
}

class B: public A{
virtual void Paint() {...}
}

Is it possible and what I have to do, so in B.Paint to invoke A.Paint and then some other code

[Cedric Moonen]

akirilov wrote:

so in B.Paint to invoke A.Paint and then some other code

Yes:

void B::Paint()
{
A::Paint();
// Other stuff here...
}

Cédric Moonen Software developer
Charting control [v1.5] OpenGL game tutorial in C++

[Stuart Dootson]

akirilov wrote:

in B.Paint to invoke A.Paint and then some other code

Implement B::Paint like this:

void B::Paint()
{
A::Paint();
// Do some B specific stuff.
}

Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p

[Code o mat]

class A{
virtual void Paint() {...}
}

class B: public A{
virtual void Paint()
{
A::Paint();
...
}
}

You can also use __super (if available) like:

class B: public A{
virtual void Paint()
{
__super::Paint();
...
}
}

> The problem with computers is that they do what you tell them to do and not what you want them to do. < > Life: great graphics, but the gameplay sux. <

[akirilov]

Thank you guys, the answer of all of you was very helpful. I tried with A.Paint(), but it didn't work. I'm going to use __super, thus It will not depend of the base class name. THANK YOU, again!!!

[CPallini]

akirilov wrote:

I tried with A.Paint(), but it didn't work.

Possibly because they suggested A::Paint() instead. :rolleyes:

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
[My articles]

[akirilov]

:laugh: Well I tried A.Paint() before I posted here ;) so, A::Paint() is working fine.

[Rajesh R Subramanian]

Along with other answers, see the __super[^] keyword. You could call a parent class function by __super::FuncName() [EDIT] OK, I just read you already are going to settle on this keyword. [/EDIT]

It is a crappy thing, but it's life -^ Carlo Pallini

[Stuart Dootson]

akirilov wrote:

I'm going to use __super, thus It will not depend of the base class name.

But it does tie you to Microsoft's compiler...

Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p