Skip to content
  • Categories
  • Recent
  • Tags
  • Popular
  • World
  • Users
  • Groups
Skins
  • Light
  • Cerulean
  • Cosmo
  • Flatly
  • Journal
  • Litera
  • Lumen
  • Lux
  • Materia
  • Minty
  • Morph
  • Pulse
  • Sandstone
  • Simplex
  • Sketchy
  • Spacelab
  • United
  • Yeti
  • Zephyr
  • Dark
  • Cyborg
  • Darkly
  • Quartz
  • Slate
  • Solar
  • Superhero
  • Vapor

  • Default (No Skin)
  • No Skin
Collapse
Code Project
  1. Home
  2. General Programming
  3. Visual Basic
  4. access databse into datagridview

access databse into datagridview

Scheduled Pinned Locked Moved Visual Basic
helpdatabase
20 Posts 5 Posters 2 Views 1 Watching
  • Oldest to Newest
  • Newest to Oldest
  • Most Votes
Reply
  • Reply as topic
Log in to reply
This topic has been deleted. Only users with topic management privileges can see it.
  • R rajulama

    thanks. what can be an alternative to fileInfo?

    C Offline
    C Offline
    Christian Graus
    wrote on last edited by
    #8

    you have the path already, use System.IO.Path.GetDirectoryName and Path.GetFileName to get the pieces of the file path that you seem to need.

    Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

    R 1 Reply Last reply
    0
    • C Christian Graus

      you have the path already, use System.IO.Path.GetDirectoryName and Path.GetFileName to get the pieces of the file path that you seem to need.

      Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

      R Offline
      R Offline
      rajulama
      wrote on last edited by
      #9

      sorry I didn't get it. Could you please give me an example?

      C 1 Reply Last reply
      0
      • R rajulama

        sorry I didn't get it. Could you please give me an example?

        C Offline
        C Offline
        Christian Graus
        wrote on last edited by
        #10

        In the System.IO namespace: Path.GetDirectory("c:\documents\word.doc") will return c:\documents Path.GetFileName("c:\documents\word.doc") will return word.doc. The Path class is full of methods for manipulating and examining file paths

        Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

        R 1 Reply Last reply
        0
        • C Christian Graus

          In the System.IO namespace: Path.GetDirectory("c:\documents\word.doc") will return c:\documents Path.GetFileName("c:\documents\word.doc") will return word.doc. The Path class is full of methods for manipulating and examining file paths

          Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

          R Offline
          R Offline
          rajulama
          wrote on last edited by
          #11

          but my file location is not fixed. I want users to select the access database file and display a table from it into datagridview.

          C 1 Reply Last reply
          0
          • R rajulama

            but my file location is not fixed. I want users to select the access database file and display a table from it into datagridview.

            C Offline
            C Offline
            Christian Graus
            wrote on last edited by
            #12

            *sigh* Dim fi As New FileInfo(OpenFileDialog1.FileName) Dim sConnectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=;Data Source=" & fi.DirectoryName Dim objConn As New OleDbConnection(sConnectionString) Dim objDataSet As DataSet = New DataSet() objConn.Open() Dim objCmdSelect As New OleDbCommand("select * from [Joint Restraint Assignments]" & fi.Name, objConn) So, you take the filename from the openfiledialog and use the FileInfo object to extract the directory name and the filename. Instead, you can use the methods I gave you, to get those values from the filename property of the file dialog, directly. I am at a loss how you think what I have been saying takes away from your using a dynamic filename. If the filename was fixed, you'd type in the values in your code, not use methods to work them out, surely ?

            Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

            R 2 Replies Last reply
            0
            • C Christian Graus

              *sigh* Dim fi As New FileInfo(OpenFileDialog1.FileName) Dim sConnectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=;Data Source=" & fi.DirectoryName Dim objConn As New OleDbConnection(sConnectionString) Dim objDataSet As DataSet = New DataSet() objConn.Open() Dim objCmdSelect As New OleDbCommand("select * from [Joint Restraint Assignments]" & fi.Name, objConn) So, you take the filename from the openfiledialog and use the FileInfo object to extract the directory name and the filename. Instead, you can use the methods I gave you, to get those values from the filename property of the file dialog, directly. I am at a loss how you think what I have been saying takes away from your using a dynamic filename. If the filename was fixed, you'd type in the values in your code, not use methods to work them out, surely ?

              Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

              R Offline
              R Offline
              rajulama
              wrote on last edited by
              #13

              that means my no need to establish a connection. Do you mean to do something like: Dim fi As New FileInfo(OpenFileDialog1.FileName) path.GetFileName(&fi.name) Dim objCmdSelect As New OleDbCommand("select * from [Joint Restraint Assignments]" .....) ??? or, path.getfilename(openfiledialog1.filename) Dim objCmdSelect As New OleDbCommand("select * from [Joint Restraint Assignments]" .....)

              1 Reply Last reply
              0
              • C Christian Graus

                *sigh* Dim fi As New FileInfo(OpenFileDialog1.FileName) Dim sConnectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=;Data Source=" & fi.DirectoryName Dim objConn As New OleDbConnection(sConnectionString) Dim objDataSet As DataSet = New DataSet() objConn.Open() Dim objCmdSelect As New OleDbCommand("select * from [Joint Restraint Assignments]" & fi.Name, objConn) So, you take the filename from the openfiledialog and use the FileInfo object to extract the directory name and the filename. Instead, you can use the methods I gave you, to get those values from the filename property of the file dialog, directly. I am at a loss how you think what I have been saying takes away from your using a dynamic filename. If the filename was fixed, you'd type in the values in your code, not use methods to work them out, surely ?

                Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

                R Offline
                R Offline
                rajulama
                wrote on last edited by
                #14

                i think i got it. But I am confused about the data source to be use in oledbconnection:

                Path.GetFileName(OpenFileDialog1.FileName)
                Dim con As OleDbConnection = New OleDbConnection("Provider=Microsoft.jet.oledb.4.0;data source=???")

                C 1 Reply Last reply
                0
                • R rajulama

                  i think i got it. But I am confused about the data source to be use in oledbconnection:

                  Path.GetFileName(OpenFileDialog1.FileName)
                  Dim con As OleDbConnection = New OleDbConnection("Provider=Microsoft.jet.oledb.4.0;data source=???")

                  C Offline
                  C Offline
                  Christian Graus
                  wrote on last edited by
                  #15

                  Dim path as String =Path.GetFileName(OpenFileDialog1.FileName) will give you the path in a variable. Just calling GetFileName without storing the result, does nothing.

                  Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

                  R 3 Replies Last reply
                  0
                  • C Christian Graus

                    Dim path as String =Path.GetFileName(OpenFileDialog1.FileName) will give you the path in a variable. Just calling GetFileName without storing the result, does nothing.

                    Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

                    R Offline
                    R Offline
                    rajulama
                    wrote on last edited by
                    #16

                    thanks i got it. so what should be the data source in:

                    Dim path1 As String = Path.GetFileName(OpenFileDialog1.FileName)
                    Dim con As OleDbConnection = New OleDbConnection("Provider=Microsoft.jet.oledb.4.0;data source=???")

                    1 Reply Last reply
                    0
                    • C Christian Graus

                      Dim path as String =Path.GetFileName(OpenFileDialog1.FileName) will give you the path in a variable. Just calling GetFileName without storing the result, does nothing.

                      Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

                      R Offline
                      R Offline
                      rajulama
                      wrote on last edited by
                      #17

                      Dim con As OleDbConnection = New OleDbConnection("Provider=Microsoft.jet.oledb.4.0;data source=" & path1 & "")

                      above code works. Thank you very very much

                      1 Reply Last reply
                      0
                      • C Christian Graus

                        Dim path as String =Path.GetFileName(OpenFileDialog1.FileName) will give you the path in a variable. Just calling GetFileName without storing the result, does nothing.

                        Christian Graus Driven to the arms of OSX by Vista. "I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

                        R Offline
                        R Offline
                        rajulama
                        wrote on last edited by
                        #18

                        :)

                        1 Reply Last reply
                        0
                        • R rajulama

                          Hello everyone, I just wonder what's wrong with my code. Actually I want to use openfiledialog to locate an access database file and then display it in datagridview. I used following connection string:

                          Dim sConnectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=;Data Source=" & fi.DirectoryName

                          and following to call the table

                          Dim objCmdSelect As New OleDbCommand("select * from table1" & fi.Name, objConn)

                          But I get the famous error: "the microsoft jet database engine cannot open the file. it is already opened exclusively by another user or you need permission to view its data." But neither by database is open nor its password protected. Please help me resolving this problem

                          L Offline
                          L Offline
                          Luc Pattyn
                          wrote on last edited by
                          #19

                          rajulama wrote:

                          Dim sConnectionString As String = "..." & fi.DirectoryName

                          Trying to open a directory as a database? :)

                          Luc Pattyn [Forum Guidelines] [My Articles]


                          Avoiding unwanted divs (as in "articles needing approval") with the help of this FireFox add-in


                          1 Reply Last reply
                          0
                          • R rajulama

                            Hello everyone, I just wonder what's wrong with my code. Actually I want to use openfiledialog to locate an access database file and then display it in datagridview. I used following connection string:

                            Dim sConnectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=;Data Source=" & fi.DirectoryName

                            and following to call the table

                            Dim objCmdSelect As New OleDbCommand("select * from table1" & fi.Name, objConn)

                            But I get the famous error: "the microsoft jet database engine cannot open the file. it is already opened exclusively by another user or you need permission to view its data." But neither by database is open nor its password protected. Please help me resolving this problem

                            D Offline
                            D Offline
                            Dave Kreskowiak
                            wrote on last edited by
                            #20

                            rajulama wrote:

                            Dim sConnectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=;Data Source=" & fi.DirectoryName

                            The names used in your code, you're trying to open a directory as a database. You have to give it the path to the .MDB file, not just it's parent directory.

                            rajulama wrote:

                            Dim objCmdSelect As New OleDbCommand("select * from table1" & fi.Name, objConn)

                            On top of that, your SQL query to get the data in table1 (if it even exists in that database) is wrong. You appending the filename to the end of the SQL SELECT statement, which won't work. The filename goes in the Data Source if your connection string, not the SELECT statement.

                            A guide to posting questions on CodeProject[^]
                            Dave Kreskowiak Microsoft MVP Visual Developer - Visual Basic
                                 2006, 2007, 2008

                            1 Reply Last reply
                            0
                            Reply
                            • Reply as topic
                            Log in to reply
                            • Oldest to Newest
                            • Newest to Oldest
                            • Most Votes


                            • Login

                            • Don't have an account? Register

                            • Login or register to search.
                            • First post
                              Last post
                            0
                            • Categories
                            • Recent
                            • Tags
                            • Popular
                            • World
                            • Users
                            • Groups