how can i find number of days in a given year and month

Rajesh R Subramanian

Number of days in a year is a constant (varies for a leap year). Number of days in any given month is going to be a constant (except for February in a leap year). Which part of this are you having a difficulty with?

It is a crappy thing, but it's life -^ Carlo Pallini

Ahmed Khallaf

thank you for your replay and you solved the problem and i remembered that if we want to know if February in a leap year or not by divided the year by 4 and if the result is an integer number it will be leap year such as 2004/4=501 this is a leap year and 2005/4=501.25 it's not a leap year and i'll to try it by code Many thanks for all

modified on Tuesday, June 2, 2009 3:48 AM

Pete OHanlon · modified on Tuesday, June 2, 2009 3:48 AM

Ooh - not quite. If it's a century, it has to be divisible by 400 to be a leap year, so 2000 is a leap year and 2100 isn't.

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musefan · modified on Tuesday, June 2, 2009 3:48 AM

use modulus (provides the remainder after a division) not divide...

if(year % 4 == 0)
//is leap year
else
//not leap year

Life goes very fast. Tomorrow, today is already yesterday.

Rajesh R Subramanian

Let us hope that his code will not have to run for a century. :)

It is a crappy thing, but it's life -^ Carlo Pallini

musefan

is 2100 really not a leap year? EDIT: It's OK I WIKI it and got an answer ;)

Life goes very fast. Tomorrow, today is already yesterday.

Ahmed Khallaf

Many Thanks and i'm very happy from Your cooperation

Ahmed Khallaf

i dont think

Lost User

int daysInMonth = DateTime.DaysInMonth(2009, 2);
Console.WriteLine(daysInMonth);

Ahmed Khallaf

i don't know if the user will enter 2009 or 2008 or any month i want to take the data from the user

modified on Tuesday, June 2, 2009 4:19 AM

musefan

Ok this is what you should use instead...

if(year % 4 == 0 && year % 100 == 0 ? year % 400 == 0 : true)//hope you get that logic
//is leap year
else
//not leap year

Life goes very fast. Tomorrow, today is already yesterday.

Ahmed Khallaf

you realy have come to the right solution thank you

Guffa · modified on Tuesday, June 2, 2009 4:19 AM

Then you just use variables in the call to the DaysInMonth method instead of the literal values used in the example.

Despite everything, the person most likely to be fooling you next is yourself.

Guffa

Or if you don't want to reinvent the wheel:

if (DateTime.IsLeapYear(year)) {
// is leap year
} else {
// not leap year
}

;)

Despite everything, the person most likely to be fooling you next is yourself.

musefan

I think we all need new wheels :)

Life goes very fast. Tomorrow, today is already yesterday.

Ahmed Khallaf

i finished simple code for this topic and i want you to review it sory for not optimized code but see the idea download the project: http://www.geocities.com/ahmed_117/Month.zip[^]

Guffa

Have a look at this:

private void button1_Click(object sender, EventArgs e) {
button1.Enabled = false;
int year = dateTimePicker1.Value.Year;
int month = dateTimePicker1.Value.Month;
DateTime start = new DateTime(year, month, 1);
dateTimePicker1.Value = start;
int days = DateTime.DaysInMonth(year, month);
for (int i = 0; i < days; i++) {
dataGridView1.Rows.Add();
dataGridView1.Rows[i].Cells[0].Value = start.AddDays(i).DayOfWeek;
dataGridView1.Rows[i].Cells[1].Value = start.AddDays(i).ToShortDateString();
}
}

Despite everything, the person most likely to be fooling you next is yourself.

Ahmed Khallaf

a very Clever man this what i want to reach thank you