How to use a function return value as array size

[Joschwenk666]

Hi, I try to initialize an array with a function return, but i get error C2057: expected constant expression. Is there an easy solution for the following problem?

const int iRecordCountBefore = p_rs->GetRecordCount();
int iRsPositionsUpdated[iRecordCountBefore] = {-1};

Thanks you!

[norish]

You cannot write such array code in C or C++ program syntax. You should change like below;

const int iRecordCountBefore = p_rs->GetRecordCount();
// if you use C++ syntax
int* iRsPositionsUpdated = new int[iRecordCountBefore];
// otherwise C syntax
int* iRsPositionsUpdated = (int*)malloc(sizeof(int)*iRecordCountBefore);
// if you want to initialize with -1 below dose
memset(iRsPositionsUpdated, -1, sizeof(int)*iRecordCountBefore);

[Joschwenk666]

Thank you for the working and fast answer!

[Cedric Moonen]

Don't forget to delete (if you used new) or free (if you used malloc) the memory when you don't need it anymore, otherwise it might lead to memory leaks.

Cédric Moonen Software developer
Charting control [v2.0] OpenGL game tutorial in C++

[Stuart Dootson]

Can I suggest using a std::vector rather than an array, if only so you don't need to bother remember freeing memory? This will create a vector initialised with iRecordCountBefore integers, all set to -1.

const int iRecordCountBefore = p_rs->GetRecordCount();
std::vector<int> iRsPositionsUpdated(iRecordCountBefore, -1);

Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p