Type declaration ?

[daveyerwin]

Heres what I do now

Type a = b.GetType();
if (a.Name == "Blog")
{
Console.WriteLine("blog = {0}", ((Blog)b).text);
error = "ok";
return 0;
}
if (a.Name == "String")
{
Console.WriteLine("blog = {0}", (String)b);
error = "ok";
return 0;
}
Console.WriteLine("blog = TypeError");
error = "unKnownType";
return 1;

I want to set the type similar to this ((GetType())b).text How can I do this ?

[0x3c0]

If b implements the interface IBlog, then you can cast b to an IBlog and provided Text is part of the interface declaration and is implemented in b's class, you can get the text. Something like:

interface IBlog
{
public string text { get; }
}

public class Blog : IBlog
{
public string text
{
get { return "name"; }
}
}

public int testThisExample()
{
object b = new Blog();

if(b is IBlog)
    Console.WriteLine("blog = {0}", (b as IBlog).text);
return 0;

}

Between the idea And the reality Between the motion And the act Falls the Shadow

[Leonscape]

You could override the ToString() function in the Blog class.

class Program
{
static void Main( string[] args )
{
object obj = "Test from string";
Console.WriteLine("The result of to string is:" + obj.ToString());
obj = new Test();
Console.WriteLine("The result of to string is:" + obj.ToString());
Console.ReadKey();
}
}

public class Test
{
public override string ToString()
{
return "Test from class";
}
}

Using the wrong tool for the job is half the fun.

[Luc Pattyn]

Hi, 1. you could concentrate on the ToString() method which exists for all objects; you should override for most types since for most classes ToString() by default returns a type string. 2. you should NOT check types by getting the type's name, then string.compare. C# has the is keyword which returns true when the type matches (directly or through inheritance). :)

Luc Pattyn [Forum Guidelines] [My Articles]

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