Read coefficients of linear equations into 2d array
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Yes I think I'll try getline() and save each line into a string in a string array, and then parse it like I was advised to do above and save the coefficients in the 2d array while checking for variable in the variable array each time. I think this would be the way to go :) Thanks for replying :)
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Hmm, How about a RegExp? You could scrub data into a tonenized string then convert it to an array. There is an open source mathematics program called 'sage', I would look atthe aproach they are implimenting. Also, you might find other good ideas by searching for OpenML. There are many examples supported by many frameworks.
I'll look into the source of 'sage' then and see if it's of any help. The other things you mentioned I'm afraid I don't understand as I am not a very advanced programmer (yet I hope :) ). Thanks for replying :)
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Oh yeah, forgot to mention another idea. Create a Red / Black tree from the code. Look at examples for expanding lambda expressions.
I don't know about this either, so I'll try working with the hints and ideas from above and if it doesn't work out I'll research this and work on it :) Thanks for your ideas :)
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I don't know about this either, so I'll try working with the hints and ideas from above and if it doesn't work out I'll research this and work on it :) Thanks for your ideas :)
hope your problem is solved. i did some paperwork onit yesterday and got some ideas. do you require any more discussion on that today?
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hope your problem is solved. i did some paperwork onit yesterday and got some ideas. do you require any more discussion on that today?
-------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.
Actually I was very busy yesterday, so I didn't have time to implement the ideas that I got from the discussion here yet but I'll start working on it today and let you know how it works out. Post your ideas anyway they might help me now :) I need all the help I can get :) Thank you for taking the time to think about the problem :)
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Actually I was very busy yesterday, so I didn't have time to implement the ideas that I got from the discussion here yet but I'll start working on it today and let you know how it works out. Post your ideas anyway they might help me now :) I need all the help I can get :) Thank you for taking the time to think about the problem :)
so, kindly confirm these points for me as per my understanding of the problem. 1. the coefficients may be 0 means, one of the variables may be absent in the expression. 2. the sequence of the variables may change. 3. Will a variable be only 1 character or may be more? 4. what will be the maximum n? (size of expression/number of expressions) because, the solution i have sketched are dependant onthese inputs.
-------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.
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Hi, I'm working on a program that reads linear equations from a file such as those:
3x+2y-2.5z=9
-2x+9y+12z=23.4
4.2x-7y+9.6z=45.3The file is supposed to contain n equations with n variables which I would read into a 2d dynamic array of doubles and then I'm supposed to solve the resulting matrix using Gauss's method. I've already implemented Gauss's method but I can't figure out when reading from file how to get only the numbers and the signs for example from the above equations I'm supposed to have the following in the array:
[+3][+2][-2.5]
[-2][+9][+12]
[+4.2][-7][+9.6]I need the numbers after the equal sign to be stored in a separate n sized array as well. If anyone has any ideas I'd really appreciate it :)
Omar Al Qady wrote:
If anyone has any ideas I'd really appreciate it
Here's a half-baked one:
void main( void )
{
char szTemp[16],
*pInput[3] = { "3x+2y-2.5z=9",
"-2x+9y+12z=23.4",
"4.2x-7y+9.6z=45.3" };int x = 0; double d1, d2, d3; for (char \*p = pInput\[0\]; p && \*p != '\\0'; p++) { if (isalpha(\*p)) { szTemp\[x\] = '\\0'; // use atof(szTemp) here x = 0; } else if ('=' == \*p) break; else { szTemp\[x\] = \*p; x++; } }}
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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so, kindly confirm these points for me as per my understanding of the problem. 1. the coefficients may be 0 means, one of the variables may be absent in the expression. 2. the sequence of the variables may change. 3. Will a variable be only 1 character or may be more? 4. what will be the maximum n? (size of expression/number of expressions) because, the solution i have sketched are dependant onthese inputs.
-------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.
1. Yes, that's possible, but a friend gave an idea of initializing the whole 2d array to equal zero, so when a variable isn't found in an equation the value isn't changed and would be correct for further calculations. 2. Yes, the sequence may change from one equation to another. 3. Variables could be one or more character so I'll just save them in an array of strings. 4. No maximum size was stated, but I don't think that matters as long as the arrays are dynamic, or does it?? :doh:
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1. Yes, that's possible, but a friend gave an idea of initializing the whole 2d array to equal zero, so when a variable isn't found in an equation the value isn't changed and would be correct for further calculations. 2. Yes, the sequence may change from one equation to another. 3. Variables could be one or more character so I'll just save them in an array of strings. 4. No maximum size was stated, but I don't think that matters as long as the arrays are dynamic, or does it?? :doh:
yes, my ideas seem to resemble with those you got yourself or my be from our friends here. go ahead, and you will surely achieve it. we will also co operate withyou.
-------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.
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Omar Al Qady wrote:
If anyone has any ideas I'd really appreciate it
Here's a half-baked one:
void main( void )
{
char szTemp[16],
*pInput[3] = { "3x+2y-2.5z=9",
"-2x+9y+12z=23.4",
"4.2x-7y+9.6z=45.3" };int x = 0; double d1, d2, d3; for (char \*p = pInput\[0\]; p && \*p != '\\0'; p++) { if (isalpha(\*p)) { szTemp\[x\] = '\\0'; // use atof(szTemp) here x = 0; } else if ('=' == \*p) break; else { szTemp\[x\] = \*p; x++; } }}
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
Good ideas, I'll try to incorporate them into my solution :) Thanks :)
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yes, my ideas seem to resemble with those you got yourself or my be from our friends here. go ahead, and you will surely achieve it. we will also co operate withyou.
-------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.
Working on it now .... :D