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  4. C++ program to print the path without the file name!

C++ program to print the path without the file name!

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  • C chandu004

    traverse the char array from end (in reverse way) till you see a / and then replace '\0' there. did this not work for you? i found, you asked the same question on 8th july see the answers here http://www.codeproject.com/Messages/3110995/String-Parsing-in-Cplusplus-Simple-Question.aspx[^]

    -------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.

    K Offline
    K Offline
    ksaw123
    wrote on last edited by
    #5

    it didn't work I need to print the path without the baseile name

    C 1 Reply Last reply
    0
    • J Jijo Raj

      You can use PathRemoveFileSpec()[^] to strip out the filename. Regards, Jijo.

      _____________________________________________________ http://weseetips.com[^] Visual C++ tips and tricks. Updated daily.

      K Offline
      K Offline
      ksaw123
      wrote on last edited by
      #6

      it is C/C++ program not vasuil C++

      D 1 Reply Last reply
      0
      • C CPallini

        And what is the question? :)

        If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
        This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
        [My articles]

        K Offline
        K Offline
        ksaw123
        wrote on last edited by
        #7

        How can I print the path without the base filename

        C 1 Reply Last reply
        0
        • K ksaw123

          it is C/C++ program not vasuil C++

          D Offline
          D Offline
          David Crow
          wrote on last edited by
          #8

          Use PathRemoveFileSpec() or _splitpath().

          "Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown

          "Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons

          K 1 Reply Last reply
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          • D David Crow

            Use PathRemoveFileSpec() or _splitpath().

            "Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown

            "Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons

            K Offline
            K Offline
            ksaw123
            wrote on last edited by
            #9

            Which .h file those functions is in?

            D 1 Reply Last reply
            0
            • K ksaw123

              Which .h file those functions is in?

              D Offline
              D Offline
              David Crow
              wrote on last edited by
              #10

              See here.

              "Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown

              "Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons

              K 1 Reply Last reply
              0
              • D David Crow

                See here.

                "Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown

                "Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons

                K Offline
                K Offline
                ksaw123
                wrote on last edited by
                #11

                my boss I don't want to use Microsoft C++ , I am using the lagacy C/C++ actually , my code is working but i wanna print the path without the file name as your suggested function. Thanks

                D 1 Reply Last reply
                0
                • K ksaw123

                  How can I print the path without the base filename

                  C Offline
                  C Offline
                  CPallini
                  wrote on last edited by
                  #12

                  The code you posted does it. :)

                  If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                  This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
                  [My articles]

                  K 1 Reply Last reply
                  0
                  • C CPallini

                    The code you posted does it. :)

                    If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                    This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
                    [My articles]

                    K Offline
                    K Offline
                    ksaw123
                    wrote on last edited by
                    #13

                    the code i posted prints the base file name not the path I want to print the path without file name

                    C C 2 Replies Last reply
                    0
                    • K ksaw123

                      my boss I don't want to use Microsoft C++ , I am using the lagacy C/C++ actually , my code is working but i wanna print the path without the file name as your suggested function. Thanks

                      D Offline
                      D Offline
                      David Crow
                      wrote on last edited by
                      #14

                      You might want to consider strrchr() to find the last backslash. Put a '\0' character there.

                      "Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown

                      "Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons

                      1 Reply Last reply
                      0
                      • K ksaw123

                        it didn't work I need to print the path without the baseile name

                        C Offline
                        C Offline
                        chandu004
                        wrote on last edited by
                        #15

                        this logic worked for me perfectly.

                        const char \* path = "/work1/data/xxxx/yyy/file\_name.txt";
                        char path1\[256\];
                        strcpy(path1,path);//copying the char array
                        cout << path <<"\\n";//this prints the whole filename with path.
                        int l=strlen(path);//finding the length of the path
                        for(int i=l;i>0;i--)//reverse traversing the array
                        {
                        	if(path1\[i\]=='/')//if '/' is found, then replacing it with '\\0'.
                        	{
                        		path1\[i\]='\\0';
                        		break;
                        	}
                        }
                        cout << path1<<"\\n";//this prints only the path.
                        

                        the output is as you desired.

                        -------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.

                        K L 2 Replies Last reply
                        0
                        • K ksaw123

                          the code i posted prints the base file name not the path I want to print the path without file name

                          C Offline
                          C Offline
                          chandu004
                          wrote on last edited by
                          #16

                          see here http://www.codeproject.com/Messages/3118524/Re-Cplusplus-program-to-print-the-path-without-the-file-name.aspx[^] and also try with the David crow's recent post that would be easier than mine.

                          -------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.

                          1 Reply Last reply
                          0
                          • C chandu004

                            this logic worked for me perfectly.

                            const char \* path = "/work1/data/xxxx/yyy/file\_name.txt";
                            char path1\[256\];
                            strcpy(path1,path);//copying the char array
                            cout << path <<"\\n";//this prints the whole filename with path.
                            int l=strlen(path);//finding the length of the path
                            for(int i=l;i>0;i--)//reverse traversing the array
                            {
                            	if(path1\[i\]=='/')//if '/' is found, then replacing it with '\\0'.
                            	{
                            		path1\[i\]='\\0';
                            		break;
                            	}
                            }
                            cout << path1<<"\\n";//this prints only the path.
                            

                            the output is as you desired.

                            -------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.

                            K Offline
                            K Offline
                            ksaw123
                            wrote on last edited by
                            #17

                            sorry, it didn't work why? look at the way you are using strcpy() function

                            C 1 Reply Last reply
                            0
                            • K ksaw123

                              sorry, it didn't work why? look at the way you are using strcpy() function

                              C Offline
                              C Offline
                              chandu004
                              wrote on last edited by
                              #18

                              ksaw123 wrote:

                              look at the way you are using strcpy() function

                              whats the problem?

                              -------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.

                              1 Reply Last reply
                              0
                              • K ksaw123

                                the code i posted prints the base file name not the path I want to print the path without file name

                                C Offline
                                C Offline
                                CPallini
                                wrote on last edited by
                                #19

                                you're right:

                                const char * path ="/work1/data/xxxx/yyy/file_name.txt";
                                char * basename;
                                char * filename;

                                basename = _strdup(path);
                                if ( !basename){/*handle error*/}

                                filename = basename+strlen(basename);

                                while (filename != basename && *(filename) != '/')
                                filename--;

                                if ( filename != basename)
                                {
                                *(filename+1)='\0';
                                }
                                else
                                *basename='\0';

                                printf("%s\n", basename);
                                free(basename); /* REMEMBER TO FREE */

                                :)

                                If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                                This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
                                [My articles]

                                1 Reply Last reply
                                0
                                • C chandu004

                                  this logic worked for me perfectly.

                                  const char \* path = "/work1/data/xxxx/yyy/file\_name.txt";
                                  char path1\[256\];
                                  strcpy(path1,path);//copying the char array
                                  cout << path <<"\\n";//this prints the whole filename with path.
                                  int l=strlen(path);//finding the length of the path
                                  for(int i=l;i>0;i--)//reverse traversing the array
                                  {
                                  	if(path1\[i\]=='/')//if '/' is found, then replacing it with '\\0'.
                                  	{
                                  		path1\[i\]='\\0';
                                  		break;
                                  	}
                                  }
                                  cout << path1<<"\\n";//this prints only the path.
                                  

                                  the output is as you desired.

                                  -------------------------------------------- Suggestion to the members: Please prefix your main thread subject with [SOLVED] if it is solved. thanks. chandu.

                                  L Offline
                                  L Offline
                                  Lost User
                                  wrote on last edited by
                                  #20

                                  You don't need to parse. Use SHString apis.

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