Hi, I need help !!!

[Nisha Agrawal]

for that u have to handle RowDataBound and SelectedIndexChanged Events. Below is the code

protected void gvItems_SelectedIndexChanged(object sender, EventArgs e)
{
Response.Redirect("ToPage.aspx?SelectedItemId=" + gvItems.SelectedDataKey.Value)
}

protected void gvItems_RowDataBound(object sender, GridViewRowEventArgs e)
{
if(e.Row.RowType==DataControlRowType.DataRow)
{
e.Row.Attributes.Add("onclick", ClientScript.GetPostBackEventReference(this.gvItems, "Select$" + e.Row.RowIndex));
}
}

Now at ToPage.aspx u have the Id of the Selected Item so you can display the data related to that item as you want to display.

[Not Active]

Waste of time doing a Response.Redirect from a postback event, just use a Hyperlink column.

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only two letters away from being an asset

[Not Active]

Use a Hyperlink column or a Template column to place the link in the grid

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only two letters away from being an asset

[sashidhar]

<ItemTemplate>
<asp:LinkButton ID ="LinkButtonemp" CausesValidation="false" Text='<%# Eval("EmployeeName") %>' runat="server" CommandArgument='<% #Eval("EmployeeID")%>' CommandName="View" CssClass="gridlnk"/>
</ItemTemplate>

Append the name/ID to the querystring and redirect it to another page say InfoPage.aspx.In info page Request the query String .With the Help of Query String Get the Data in the InfoPage.aspx.

If It Helps Click It as Answer

[S Dhanasekaran]

Hi, do changes in frist column(Viewdetails) <asp:HyperLink ID="hypTitle" NavigateUrl='<%#"secondpage.aspx?pid="+DataBinder.Eval(Container.DataItem,"picid")%>' Text='<%#DataBinder.Eval(Container.DataItem,"picturename") %>' runat="server" ></asp:HyperLink> when click the viewdetails column, i pass Querystring("pid") value of current picture. On second page, get value from querystring("pid"), using to display the picture.

[sashidhar]

Mark Nischalke wrote:

Waste of time

Yes He is right Try to use ItemTemplate as Mark suggests

If It Helps Click It as Answer

[sashidhar]

Good Answer But Try to use pre tags i.e. code block so he can understand easily:cool:

If It Helps Click It as Answer

[Nisha Agrawal]

But the original requirement was to able to click on datarow not any control in the gridview row. thats why i have prvovided that code. please read the requirement carefully.

[Not Active]

Nisha Agrawal wrote:

please read the requirement carefully.

Please look at all of the requirements. The image clearly shows and says the OP want to click on a LINK

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only two letters away from being an asset

[_ASPAle_]

Thank you guys!!!

[Nisha Agrawal]

yes, it's my mistake. I just followed the words that were written in the main post and ignored the one in the image.

[_ASPAle_]

Ok, it works, because when I click the link, it has this value "http://localhost:3849/progetto/visualizza.aspx?IDModello=24," but now to see the data, including other photos in the DataList , how should I proceed?

[sashidhar]

_ASPAle_ wrote:

but now to see the data

Can You please explain in detail.I didnt get Your point. Depending upon the IDModello You can present the data .If You want to access the previous data provide a link. If You want to See all the other photos Provide a next button or image slider.If that is the case use the below links it may help. http://www.asp.net/AJAX/AjaxControlToolkit/Samples/SlideShow/SlideShow.aspx[^] http://aspnet.4guysfromrolla.com/articles/070704-1.aspx[^] http://aspnet.4guysfromrolla.com/London/[^]

If It Helps Click It as Answer

[_ASPAle_]

"IDModello" is a sql int variable. When I click on the gridview (see the image I posted),I want to appear a DataList with only the data that I want to ... not all!