call strcpy???????????

[Lost User]

hi there, following problem: char g_szOutputFile[_MAX_PATH]; CString pathname; now i want to copy pathname into g_szOutputFile and i call strcpy(g_szOutputFile,pathname); but this doesn't look like it is working, are there any other functions i can call to convert a CString into a char? thank's in advance, patrick:confused:

[XKent]

Strange, it's alwayse working perfectly (and doing so now!) But try to use LPTSTR GetBuffer( int nMinBufLength ); char *c; CString S; c = S.Getbuffer(10)

[David Fleming]

I'm pretty new to C++, but it seems to me that you can just cast the CString. I believe you need an LPTCSTR type for the strcpy function, so I think you can do a simple cast from CString to the LPTCSTR type: ...(LPTCSTR)pathname... You may need to cast it again such as: ...(LPTSTR)(LPTCSTR)pathname... David.

[Lost User]

You can try it as such: char szFileName[MAX_LENGTH]; CString pathname = "c:\temp"; strcpy(szFileName, (const char*)pathname);:suss: :cool: :cool:

[Lost User]

thank's a lot guys, you helped me a lot:) :) :) patrick

[Lost User]

I Think strncpy should be used for "safer" strcpy #define STRCPY(d,s) strncpy( (d), (s), sizeof( (s) ) - 1 );\ (d)[ sizeof((d)) - 1 ] = NULL;\ STRCPY( g_szOutputFile, pathname );

[realJSOP]

you can use one of these: strcpy(g_szOutputFile, (const char*)pathname); strcpy(g_szOutputFile, (LPCTSTR)pathname); strcpy(g_szOutputFile, (LPSTR)pathname); strcpy(g_szOutputFile, pathname.GetBuffer(pathname..GetLength())); pathname.ReleaseBuffer();