Converting calloc to new.

[BubbaGeeNH]

I'm trying to convert some old code that is using 'calloc' to use 'new' but I'm having a little trouble with this: void (**temp_stack)(void); temp_stack=(void (**)())calloc(count+1,sizeof(void *)); I tried using this: void (**temp_stack)(void); temp_stack=new (void*[count+1]); but get the following error: error C2440: '=' : cannot convert from 'void ** ' to 'void (__cdecl ** )(void)' Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast Can anyone help me figure it out? Thanks, George

George

[Chris Losinger]

void (**temp_stack)(void);
temp_stack=(void (**)())calloc(count+1,sizeof(void *));

:confused: that doesn't even compile in VC6.

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[Nemanja Trifunovic]

Chris Losinger wrote:

that doesn't even compile in VC6.

It does in VC2010. What is the error message you got?

utf8-cpp

[Chris Losinger]

error C2563: mismatch in formal parameter list

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[Nemanja Trifunovic]

This should work:

typedef void(* void_pp_fn)(void);
void_pp_fn* temp_stack=new void_pp_fn[count+1];

utf8-cpp