Select word in richtextbox control

[realJSOP]

If all three words are "word", how do you know you selected the desired word?

.45 ACP - because shooting twice is just silly
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"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass..." - Dale Earnhardt, 1997
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"The staggering layers of obscenity in your statement make it a work of art on so many levels." - J. Jystad, 2001

[salamonty86]

each one has id. i.e if i said id=1 then select the first word only, if i said id=2 then select the second word only and so on.

[TheDudeJuan]

Split the string by " " (space) and select the second value

Dollartegn 8D

[OriginalGriff]

He's going to spell the one in the middle wrong. :laugh:

All those who believe in psycho kinesis, raise my hand. My :badger:'s gonna unleash hell on your ass. :badger:tastic!

[salamonty86]

The issue is how i will select the second "word" ONLY, when i say id=2, OR select the third "word" ONLY, when i say id=3, if i have in my richtextbox string like this "word word word word word word word word word word word"

[Dan Mos]

DudeJuan already answered your question something like:

string[] words = richTextBox1.Text.Split(" ");
//get the second word
string secondWord = words[1];

It works for your example. But there are more separators than just space. There's also ".",";","," and many other words separators.

[salamonty86]

I understood this but what i want exactly is the selection operation in the richtextbox. How i will find and select the second "word" only without select the first occurence of it :-D

[Dan Mos]

well you need to find the location of the second " " in the text as well as the loacation of the third " " and then use the

richTextBox1.Select(StartPosition, Endposition);

Here are the steps: -find the start position of the nth word -find end postion of the nth word and select it. How you do that it's up to you. If it's just spaces that separates your words, then it's quite simple. id=3 => third word

for(int i=0;i<(id-1);i++)
{
startPos+=words[i].Length;
}
//now add to the position for the spaces between the numbers
if(id>2) startPos+=(id-2);

for the endPosition:

endPos = startPos+(words[id-1].Length);

Hope it helps

[salamonty86]

YES IT HELPED :rose: :rose: :rose: THANK YOUUUU VERY VERY MUCH MOS DAN

[Dan Mos]

you're welcome

[Mycroft Holmes]

salamonty86 wrote:

YES IT HELPED

So give a vote on the answer! Then we can all see at a glance that there is a response that was useful

Never underestimate the power of human stupidity RAH

[salamonty86]

Ok :) Sorry for being late :laugh: