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  4. how to access base class member function

how to access base class member function

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  • S Offline
    S Offline
    santhosh padamatinti
    wrote on last edited by
    #1

    Hi to all Please look at the following code:

    class base
    {
    public:
    void show_base()
    {
    cout<<"executing base"<

      In the above my problem is "I want to access a base class member function.i.e when i called show\_derived(), it needs first calls show\_base() and then show\_derived() remaining code should execute. Is it possible to call like this. Or please show me any other possibilities 
    

    Thanks in advance......................

    To invent something, you need a mountain of junk in your mind.
    ---------------------Thomas alva edison

    CPalliniC A 2 Replies Last reply
    0
    • S santhosh padamatinti

      Hi to all Please look at the following code:

      class base
      {
      public:
      void show_base()
      {
      cout<<"executing base"<

        In the above my problem is "I want to access a base class member function.i.e when i called show\_derived(), it needs first calls show\_base() and then show\_derived() remaining code should execute. Is it possible to call like this. Or please show me any other possibilities 
      

      Thanks in advance......................

      To invent something, you need a mountain of junk in your mind.
      ---------------------Thomas alva edison

      CPalliniC Offline
      CPalliniC Offline
      CPallini
      wrote on last edited by
      #2

      sampath-padamatinti wrote:

      cout<<"code is added at derived class":

      Excluding a minor syntax error in the above line (colon instead of semicolon at the end of the statement), your code,as it stands, produces exactly the output you require. :)

      If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
      This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
      [My articles]

      In testa che avete, signor di Ceprano?

      1 Reply Last reply
      0
      • S santhosh padamatinti

        Hi to all Please look at the following code:

        class base
        {
        public:
        void show_base()
        {
        cout<<"executing base"<

          In the above my problem is "I want to access a base class member function.i.e when i called show\_derived(), it needs first calls show\_base() and then show\_derived() remaining code should execute. Is it possible to call like this. Or please show me any other possibilities 
        

        Thanks in advance......................

        To invent something, you need a mountain of junk in your mind.
        ---------------------Thomas alva edison

        A Offline
        A Offline
        Abhi Lahare
        wrote on last edited by
        #3

        Hello, The code is giving required output. What is your question? Is that something which you need different an output?

        S 1 Reply Last reply
        0
        • A Abhi Lahare

          Hello, The code is giving required output. What is your question? Is that something which you need different an output?

          S Offline
          S Offline
          santhosh padamatinti
          wrote on last edited by
          #4

          Thanks for reply, sorry, I am not check my code properly. It s giving me correct answer.

          To invent something, you need a mountain of junk in your mind. ---------------------Thomas alva edison

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