Some problen in converting char * to LPCWSTR

anuhoho

Hi I am facing some problem in the following code .Actually I am not able to print the full data present in my LPCWSTR .Here is the code

....
SYSTEMTIME current_time;.

GetLocalTime(¤t_time);

char *str =new char[2000];

sprintf(str, "%4d/%2d/%2d %2d:%2d:%2d:%2d\n", current_time.wYear,current_time.wMonth,current_time.wDay,current_time.wHour,current_time.wMinute,current_time.wSecond,current_time.wMilliseconds);

int i;

wchar_t *pwc = (wchar_t *)malloc( sizeof( wchar_t ));

i = mbstowcs( pwc, str, sizeof(str) );

WriteToLogFile(pwc);

delete [] str;

In the log file I just want to print the year date and time but only the year gets printed. Here is the log file

void WriteToLogFile(LPCWSTR strData)
{
try
{
ofstream myfile;
myfile.open("\\MyData\\Log.txt",ios::app);

    int iSize = WideCharToMultiByte(CP\_ACP,0,strData, -1, NULL, 0, NULL, NULL );

    char\* lpNarrow = new char\[iSize\];

        lpNarrow\[0\] = 0;

    iSize= WideCharToMultiByte(CP\_ACP, 0,strData, -1, lpNarrow, iSize, NULL, NULL );

	

    myfile<

Any help on this..

Thanks in advance

Covean

anuhoho wrote:

wchar_t *pwc = (wchar_t *)malloc( sizeof( wchar_t ));

Maybe you should allocate more than 2 bytes for your string. ;P

Greetings Covean

Covean

In addition to my first post this

anuhoho wrote:

i = mbstowcs( pwc, str, sizeof(str) );

copies only 4(32bit)/8(64bit) chars to your 2 wchar_t long string, because the call sizeof(str) returns the length of an char* and not the length of the string.

Greetings Covean

anuhoho

SO what you suggest seeing the above code,.what should i give

anuhoho

what you suggest then

Covean

Something like this:

int nStrLen = strlen(str);
wchar_t *pwc = (wchar_t *)malloc( sizeof( wchar_t) * (nStrLen + 1));
i = mbstowcs( pwc, str, nStrLen );

Hope this work, couldn't test it.

Greetings Covean

anuhoho

thnx it worked