Repositioning the cursor

skhan17

Hello, I am looking for ways to reposition the cursor when I am clicked on the first menu item from a form menu. It should create a jumping effect so the user doesn't have to scroll through the other menus which don't have a child menu. for example.... one file menu has 4 items. Namely 1, 2, 3, 4 now only item 2 has child menu items. namely 2.1, 2.2, 2.3. I want the cursor to be on 2.1 when the user brings the mouse on 2. Please let me know how to do that. I am trying the following:

private void toolStripMenuItem2_MouseHover(object sender, EventArgs e)
{
toolStripMenuItem2.ShowDropDown();
Point LocalMousePosition_1 = this.PointToClient(Cursor.Position);
System.Windows.Forms.Cursor.Position = new Point(500, 500); //This just repositions the cursor to 500,500 position but not in the net child menu. This is where I am stuck.

        //Point LocalMousePosition\_2 = toolStripMenuItem2\_1.PointToClient(Cursor.Position);
        MessageBox.Show(LocalMousePosition\_1+"Happy New Year to DOTNETSPIDER.COM guys");        
    }

PIEBALDconsult

That sounds user-hostile -- I wouldn't use your application if it did that.

skhan17

It doesn't matter if it's hostile or not, I need it now for some reason... let's just say all the supervisors in the MSc. program are crazy...... if you know a solution please help me ...otherwise please mind your own business....

Paw Jershauge

Easy now skhan17, no need to get all personal and stuff... hi just posted his opinion... But here try this: System.Windows.Forms.Cursor.Position = [MenuItem2.1].PointToClient(); One thing here to remember is, that you CANNOT call this before the [MenuItem2.1] has been shown. ;) Hope it works

With great code, comes great complexity, so keep it simple stupid...:-\ :-\

skhan17

well it doesn't let me add that... i have tried that... it says : Error 1 'System.Windows.Forms.ToolStripMenuItem' does not contain a definition for 'PointToClient' and no extension method 'PointToClient' accepting a first argument of type 'System.Windows.Forms.ToolStripMenuItem' could be found (are you missing a using directive or an assembly reference?) I am sure that the child menu item has been shown before that.... please help.... Thanks for replying......

Paw Jershauge

Ohhh my god, what was i thinking, ofcause you cannot do that... sorry m8. Let me get back to you in a moment...

With great code, comes great complexity, so keep it simple stupid...:-\ :-\

Paw Jershauge

Well i couldnt really find anything for you mate, sorry. But try look for HitTest methods or perhaps you shall loop through all MenuItems to do some calculation of somesort... Sorry i couldnt be of more help... :doh: :doh: :doh:

With great code, comes great complexity, so keep it simple stupid...:-\ :-\

PIEBALDconsult

skhan17 wrote:

all the supervisors in the MSc. program are crazy

I can imagine. I have no idea, but will Focus have any effect?

skhan17

I don't know how to use focus.....can you please let me know how to use mouse focus... then I can use it..maybe

Alan N

Hi, Handle the DropDownOpening or DropDownOpened event that occurs when your child menu appears. The Location property will get the screen coordinates of the top left corner of the menu. Apply an offset to put the cursor into the centre of the first menu item.

private void MenuItem_DropDownOpening(object sender, EventArgs e) {
ToolStripMenuItem menu = (ToolStripMenuItem)sender;

Point p = menu.DropDown.Location; // screen coords
Rectangle r = menu.DropDown.Items[0].Bounds;
p.Offset(r.Width / 2, r.Height / 2);
Cursor.Position = p;
}

Alan.

skhan17

THANK YOU SO MUCH..... although I have figured out a manual way.... but this works like a charm....

Som Shekhar

PIEBALDconsult wrote:

That sounds user-hostile

Agree completely... Tell me something, how will you go to menu no 3? when you are moving your mouse down to item 1, and then to item 2, and boom... your mouse has gone to item 2.1 :D HORRIBLE

skhan17

I agree with you too...it's horrible.... and since we both agree on this issue, there is a little chance that you'll also agree that some people always see the glass as half empty...... I chose not to be one of them. Finally thank you Alan N for helping me out.

Som Shekhar

Dude!! I am not seeing the glass as half empty buddy... There is a fine line between optimism and hallucination. I am always there standing next to you on optimism and I would always prefer to see the glass as half full... I only reasoned my doubt that how would you go to Menu Item number 3 in your example. Think about it. It is practically just not possible. By implementing this (so called) feature you are inviting a fault in your menu functionality. Now, the optimism part: May be your requirement is that you do not want your user to reach Item 3 and 4. Then, this could be one of the innovative ways. However, in that case, I would have simply preferred disabling the items.

skhan17 wrote:

Finally thank you Alan N for helping me out.

Welcome... I do think i have helped you... Provided you understand the problem here.

Som Shekhar

In any case, I am sure you don't believe me. So here is a code made for you. Run it and you will see it.

public class Form2 : Form
{
private System.ComponentModel.IContainer components = null;

    protected override void Dispose(bool disposing)
    {
        if (disposing && (components != null))
        {
            components.Dispose();
        }
        base.Dispose(disposing);
    }

    private void InitializeComponent()
    {
        this.menuStrip1 = new System.Windows.Forms.MenuStrip();
        this.item1ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
        this.item1ToolStripMenuItem1 = new System.Windows.Forms.ToolStripMenuItem();
        this.item2ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
        this.item3ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
        this.item4ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
        this.subItem1ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
        this.subItem2ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
        this.menuStrip1.SuspendLayout();
        this.SuspendLayout();
        this.menuStrip1.Items.AddRange(new System.Windows.Forms.ToolStripItem\[\] {
        this.item1ToolStripMenuItem});
        this.menuStrip1.Location = new System.Drawing.Point(0, 0);
        this.menuStrip1.Name = "menuStrip1";
        this.menuStrip1.Size = new System.Drawing.Size(491, 24);
        this.menuStrip1.TabIndex = 0;
        this.menuStrip1.Text = "menuStrip1";
        this.item1ToolStripMenuItem.DropDownItems.AddRange(new System.Windows.Forms.ToolStripItem\[\] {
        this.item1ToolStripMenuItem1,
        this.item2ToolStripMenuItem,
        this.item3ToolStripMenuItem,
        this.item4ToolStripMenuItem});
        this.item1ToolStripMenuItem.Name = "item1ToolStripMenuItem";
        this.item1ToolStripMenuItem.Size = new System.Drawing.Size(77, 20);
        this.item1ToolStripMenuItem.Text = "MainMenu";
        this.item1ToolStripMenuItem.MouseMove += new System.Windows.Forms.MouseEventHandler(this.item1ToolStripMenuItem\_MouseMove);
        this.item1ToolStripMenuItem1.Name = "item1ToolStripMenuItem1";
        this.item1ToolStripMenuItem1.Size = new System.Drawing.Size(152, 22);
        this.item1ToolStripMenuItem1.Text = "I