String operation

[Lost User]

Are they delimited by spaces? Are there always the same number of elements in your string? If so, you could split[^] it on the space.

I are Troll :suss:

[SRKSHOME]

This line of string is not delimited by spaces.Yes,this particular line always contains same number of elements. Is there any efficient method other than split?

[Rajesh Anuhya]

Try This

string str = "8 (26/04/2010 05:58.03) Execute(WQADataRequest, WQA\_LOAD\_TYPE.Deep) 931.3392ms (1.7/11.4 KB)";

MessageBox.Show(
(((str.Substring(str.IndexOf(")") + 1)).
Substring((str.Substring(str.IndexOf(")") + 1)).IndexOf(")") + 1)).
Substring(0, ((str.Substring(str.IndexOf(")") + 1)).
Substring((str.Substring(str.IndexOf(")") + 1)).IndexOf(")") + 1)).IndexOf("(")))
);

Rajesh B --> A Poor Workman Blames His Tools <--

[SRKSHOME]

Thanks...This works efficiently.

[Lost User]

SRKSHOME wrote:

This line of string is not delimited by spaces.

You already mentioned that, just checking since there were spaces in the example-string.

SRKSHOME wrote:

Yes,this particular line always contains same number of elements.

Split on some other character? Like the "("?

SRKSHOME wrote:

Yes,this particular line always contains same number of elements.

But the elements do not always have the same length?

SRKSHOME wrote:

Is there any efficient method other than split?

Yup, using regular expressions[^].

I are Troll :suss:

[Md Marufuzzaman]

Gr8... very smart. :)

Thanks Md. Marufuzzaman

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I will not say I have failed 1000 times; I will say that I have discovered 1000 ways that can cause failure – Thomas Edison.

[Luc Pattyn]

I can't disagree more, that is horrible code. It is unreadable, it has 7 calls to IndexOf where you only need 3, and 7 to SubString where you also need just 3.

string a=str.Substring(str.IndexOf(")") + 1);   // skip everything before first ")"
string b=a.Substring(a.IndexOf(")") + 1);       // skip everything before second ")"
string c=b.Substring(0, b.IndexOf("("));        // drop everything after next "("

The Regex alternatives are pretty simple too, here is one; the result excludes the surrounding spaces:

string d=Regex.Match(str, @"\\) (\[0-9\\.\]\*ms) \\(").Groups\[1\].Value;

:)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]

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We all depend on the beast below.

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[PIEBALDconsult]

Use a Regular Expression, check out Expresso[^] or my own RegexTester[^].

[PIEBALDconsult]

+5 for sarcasm.

[hossein narimani rad 0]

if the string is always fix size you can simply try the Substring method of the String class.

[Ravi Bhavnani]

You may want to consider using my StringParser[^] class.

string mSec = string.Empty;
StringParser sp = new StringParser (s);
if (sp.skipToEndOf (") ") && sp.skipToEndOf (") ")) {
sp.extractTo ("(", out mSec);
}

/ravi

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