Memory Allocation

Anil Kumar Arvapalli

I have a the following string "568" and 568(which is int), how memory is allocated for them internally... can any one please help me regrding this... Thanks in Advance... :)

CPallini

The language provides the sizeof operator [^], please use it. :)

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ThatsAlok

Pardhu2 wrote:

I have a the following string "568" and 568(which is int), how memory is allocated for them internally... can any one please help me regrding this...

if it string,it would 1 byte per char! if it int, it would be 4 byte per variable! Shoot me down, if i am wrong! :-)

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Luc Pattyn

ThatsAlok Shoot me down, if i am wrong!

say where and when.

ThatsAlok if it string,it would 1 byte per char!

1 or 2 bytes per character, also counting the terminating null. :)

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CPallini

C++ string literals (like to one of the OP) have 1 byte per character (wide character string literals must be L prefixed). They include, as you stated, a terminating 0. :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
[My articles]

Lost User

In its simplest (ASCII) form the string "568" will allocate one byte per character and a null byte to signify the end of the string, giving a total of four bytes. If the string uses Unicode encoding then two bytes per character are allocated. If MBCS UTF-8[^] then it may be more than two per character. An integer will be stored as 16, 32, or 64 bits depending on the type of variable: short, int, long, long long etc.

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