What does mean "struct foo f = {0};"?

ant damage

struct foo
{
int i;
};

foo f = {0}; // <- What does this mean?

Maximilien

what about initialize the struct ?

Watched code never compiles.

rp_suman

ant-damage wrote:

foo f = {0}; // <- What does this mean?

creating an instance of structure foo(in the name of "f") with i's value zero.

-- "Programming is an art that fights back!"

_Superman_

In Visual Studio this will initialize the structure to all zeros similar to ZeroMemory(&f, sizof(struct foo));

«_Superman_»
I love work. It gives me something to do between weekends.

ant damage

And if we have

struct point
{
float x;
float y;
float z;
};

struct face
{
point a;
point b;
point c;
};

face f = {0}; // <- This will initialize to zero the struct, and its elements?

rp_suman

ant-damage wrote:

struct face{ point a; point b; point c;};face f = {0}; // <- This will initialize to zero the struct, and its elements?

Yes, (I guess point is of type similar to CPoint containing x & y), above code will initialize x & y values of a, b & c to zeroes.

-- "Programming is an art that fights back!"

ant damage

That is exactly what I wanted to know. Thanks.

rp_suman

You are welcome!! BTW: You can have constructors for initializing structures.

-- "Programming is an art that fights back!"

Eugen Podsypalnikov

... the code of ... = {0}; may be much faster (than the code of ZeroMemory(..)) :)

virtual void BeHappy() = 0;