HextoCString conversion

[ShilpiP]

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[Lost User]

It depends what you mean by convert. Do you want the hex value to appear as hex in the string (e.g. 0x3739 --> "0x3739") or do you want to display it as characters (e.g. 0x3739 --> "79")?

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[S p k 521]

ys.. i need to convert hex to its corresponding ascii value...

[Satheesh1546]

Hi, Please try this.. char str[] = "01-15-43-43-34-37-37-41"; char delims[]="-"; CString strAscii = _T(""); CString strModelN0 = _T(""); char *result= NULL; result = strtok(str,delims); while(result != NULL) { result = strtok(NULL, delims); if(NULL != result) { strAscii.Format(_T("%c"),hexToAscii(result)); strModelN0 += strAscii; } } char hexToAscii(char *Num) { char hex[10]= "0x"; strcat(hex,Num); return strtol(hex, NULL, 16); } Regards, Spidy

[S p k 521]

Thanks laj its working....

[Nuri Ismail]

You can do this easily using std::ostringstream[^]. Here is a small example for you:

#include <iostream>
#include <string>
#include <iomanip>
#include <sstream>

int main()
{
// Test numbers - num1 declared as HEX, num2 as DEC
const unsigned int num1 = 0x1234, num2 = 1234;

// We will use std::ostringstream for the conversion
std::ostringstream oss;

// First num to Hex
    // "0x" is optional if you don't need it you can use "oss << std::hex << num1;"
oss << "0x" << std::hex << num1; 
std::string strFirstNumHex = oss.str();
    // Clear the content of the string buffer for later use
oss.str(std::string());

// Second num to Hex
    // "0x" is optional if you don't need it you can use "oss << std::hex << num2;"
oss << "0x" << std::hex << num2;
std::string strSecondNumHex = oss.str();
    // Clear the content of the string buffer for later use
oss.str(std::string());

// First num to Dec
oss << std::dec << num1;
std::string strFirstNumDec = oss.str();
    // Clear the content of the string buffer for later use
oss.str(std::string());

// Second num to Dec
oss << std::dec << num2;
std::string strSecondNumDec = oss.str();

// This line prints: Numbers in HEX: 0x1234, 0x4d2       Numbers in DEC: 4660, 1234
std::cout << "Numbers in HEX: " << strFirstNumHex << ", " << strSecondNumHex << "\\t"
          << "Numbers in DEC: " << strFirstNumDec << ", " << strSecondNumDec;

std::cin.get();
return 0;

}

As you can see from the above example strFirstNumHex and strSecondNumHex contain hex string representations of the test integers (strFirstNumHex = 0x1234 and strSecondNumHex = 0x4d2). strFirstNumDec and strSecondNumDec contain decimal string representations of the test integers. If you don't need the "0x" prefix for your Hex strings you can remove this prefix from specified lines in above example. I hope this helps. :) NOTE: For clearing the content of the stream buffer I usually use: oss.str("");, but it messes the formatting of the code block and I changed it to oss.str(s

[Cool_Dev]

in addition to his above example, if your hex is in some int type variable, you may try this also,

int k = 0x3739;
CString out;
while(k > 0) {
out += (char)k % 0x100;
k /= 0x100;
}
strrev(out.GetBuffer(0));
cout <<(LPCTSTR)out <

[Lost User]

You missed the first number.

I must get a clever new signature for 2011.

[S p k 521]

thank you very much experts...

[David Crow]

S p k 521 wrote:

...convert hex to its corresponding ascii value...

This makes no sense? Are you wanting to convert from base-16 to base-10?

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