Skip to content
  • Categories
  • Recent
  • Tags
  • Popular
  • World
  • Users
  • Groups
Skins
  • Light
  • Cerulean
  • Cosmo
  • Flatly
  • Journal
  • Litera
  • Lumen
  • Lux
  • Materia
  • Minty
  • Morph
  • Pulse
  • Sandstone
  • Simplex
  • Sketchy
  • Spacelab
  • United
  • Yeti
  • Zephyr
  • Dark
  • Cyborg
  • Darkly
  • Quartz
  • Slate
  • Solar
  • Superhero
  • Vapor

  • Default (No Skin)
  • No Skin
Collapse
Code Project
  1. Home
  2. General Programming
  3. C#
  4. what the code of this

what the code of this

Scheduled Pinned Locked Moved C#
data-structurestutorial
22 Posts 8 Posters 0 Views 1 Watching
  • Oldest to Newest
  • Newest to Oldest
  • Most Votes
Reply
  • Reply as topic
Log in to reply
This topic has been deleted. Only users with topic management privileges can see it.
  • N Nabawoka

    An array is defined to be a Jeffian array if it contains at least one prime number and the minimum prime number in the array is equal to the count of all the prime numbers in the array. Recall that a prime number is an integer greater than 1 whose only factors are 1 and itself. For example, the array {3, 6, 7, 10, 5} is a Jeffian array because: 1. it contains at least one prime number 2. its minimum prime number is 3 and that is the count of the number of primes (3, 7, 5) in the array

    modified on Wednesday, January 26, 2011 5:20 PM

    A Offline
    A Offline
    AspDotNetDev
    wrote on last edited by
    #8

    This is quite simple really:

    1. Take the inverse cosine of the dot product of the array and its transverse.
    2. Once you have this result, compare it to the sum of the edges of the numbers arranged into the indentity matrix multiplied by the primes of the original array arranged diagonally into a matrix.
    3. Once you perform that comparison, realize that it does you no good and that you should really focus on the assignment at hand rather than asking strangers on a forum to complete it for you. That's dishonest and stupid.

    [WikiLeaks Cablegate Cables]

    P 1 Reply Last reply
    0
    • A AspDotNetDev

      This is quite simple really:

      1. Take the inverse cosine of the dot product of the array and its transverse.
      2. Once you have this result, compare it to the sum of the edges of the numbers arranged into the indentity matrix multiplied by the primes of the original array arranged diagonally into a matrix.
      3. Once you perform that comparison, realize that it does you no good and that you should really focus on the assignment at hand rather than asking strangers on a forum to complete it for you. That's dishonest and stupid.

      [WikiLeaks Cablegate Cables]

      P Offline
      P Offline
      Pete OHanlon
      wrote on last edited by
      #9

      Oh for goodness sake. I didn't expect anybody to actually post the solution here. BTW, it's the log of the inverse cosine otherwise you end up with a nullity array.

      I'm not a stalker, I just know things. Oh by the way, you're out of milk.

      Forgive your enemies - it messes with their heads

      My blog | My articles | MoXAML PowerToys | Onyx

      A T 2 Replies Last reply
      0
      • N Nabawoka

        An array is defined to be a Jeffian array if it contains at least one prime number and the minimum prime number in the array is equal to the count of all the prime numbers in the array. Recall that a prime number is an integer greater than 1 whose only factors are 1 and itself. For example, the array {3, 6, 7, 10, 5} is a Jeffian array because: 1. it contains at least one prime number 2. its minimum prime number is 3 and that is the count of the number of primes (3, 7, 5) in the array

        modified on Wednesday, January 26, 2011 5:20 PM

        N Offline
        N Offline
        Nabawoka
        wrote on last edited by
        #10

        cheat cheat cheat what i want help from you and you can't help me to depend on my self and i thanxs you i ended the exam and not passed if one can help me in any time not now i will thank him very much

        T P F 3 Replies Last reply
        0
        • N Nabawoka

          not cheating but i ended the exam i can't answer three question :( now i want to know the code ... and wait the answer tomorro or after tomorrow not now :) calculating in programing difficult

          A Offline
          A Offline
          AspDotNetDev
          wrote on last edited by
          #11

          Mohamed Nabawy wrote:

          not cheating but i ended the exam

          Suuuuure. Is that why you deleted the message you just had posted that said you had 30 minutes to go on your exam? If you have all this free time now, you would do yourself some good by solving this yourself. Perhaps you should go to your teacher if you are unable to provide a solution. I'm sure he/she would be happy to help you so that you don't fail again in the future.

          [WikiLeaks Cablegate Cables]

          N 1 Reply Last reply
          0
          • A AspDotNetDev

            Mohamed Nabawy wrote:

            not cheating but i ended the exam

            Suuuuure. Is that why you deleted the message you just had posted that said you had 30 minutes to go on your exam? If you have all this free time now, you would do yourself some good by solving this yourself. Perhaps you should go to your teacher if you are unable to provide a solution. I'm sure he/she would be happy to help you so that you don't fail again in the future.

            [WikiLeaks Cablegate Cables]

            N Offline
            N Offline
            Nabawoka
            wrote on last edited by
            #12

            thaaanks but the exam ended .. and i will do my best in other exams :D

            T 1 Reply Last reply
            0
            • N Nabawoka

              cheat cheat cheat what i want help from you and you can't help me to depend on my self and i thanxs you i ended the exam and not passed if one can help me in any time not now i will thank him very much

              T Offline
              T Offline
              TheGreatAndPowerfulOz
              wrote on last edited by
              #13

              do you really think we're that stupid? oh, wait, you're a cheater... so yeah, you do think we're that stupid.

              "If your actions inspire others to dream more, learn more, do more and become more, you are a leader." - John Quincy Adams

              N 1 Reply Last reply
              0
              • P Pete OHanlon

                Oh for goodness sake. I didn't expect anybody to actually post the solution here. BTW, it's the log of the inverse cosine otherwise you end up with a nullity array.

                I'm not a stalker, I just know things. Oh by the way, you're out of milk.

                Forgive your enemies - it messes with their heads

                My blog | My articles | MoXAML PowerToys | Onyx

                A Offline
                A Offline
                AspDotNetDev
                wrote on last edited by
                #14

                Ah, but you see the nullity array is cancelled out during the substitution phase. It's also important to keep the nullity array to preserve the equation's covariance, otherwise you end up with an unprovable postulate.

                [WikiLeaks Cablegate Cables]

                P P 2 Replies Last reply
                0
                • T TheGreatAndPowerfulOz

                  do you really think we're that stupid? oh, wait, you're a cheater... so yeah, you do think we're that stupid.

                  "If your actions inspire others to dream more, learn more, do more and become more, you are a leader." - John Quincy Adams

                  N Offline
                  N Offline
                  Nabawoka
                  wrote on last edited by
                  #15

                  i don`t know what i can say to you but Thank you think

                  1 Reply Last reply
                  0
                  • N Nabawoka

                    cheat cheat cheat what i want help from you and you can't help me to depend on my self and i thanxs you i ended the exam and not passed if one can help me in any time not now i will thank him very much

                    P Offline
                    P Offline
                    Pete OHanlon
                    wrote on last edited by
                    #16

                    Look. It's easy. You have an array. Iterate over the array and check to see if each item is a prime. If it's a prime, increment your prime count and check to see if it's lower than any other primes you've found. At the end of the function, compare the count of primes with the lowest prime value. There are various optimisations that you can apply, but this is the basic functionality. If you want to have a career that doesn't involve flipping burgers then you need to apply critical thinking to problems. The question gave you all the information that you needed, but you chose to waste your time here rather than breaking the problem down into small steps.

                    I'm not a stalker, I just know things. Oh by the way, you're out of milk.

                    Forgive your enemies - it messes with their heads

                    My blog | My articles | MoXAML PowerToys | Onyx

                    1 Reply Last reply
                    0
                    • A AspDotNetDev

                      Ah, but you see the nullity array is cancelled out during the substitution phase. It's also important to keep the nullity array to preserve the equation's covariance, otherwise you end up with an unprovable postulate.

                      [WikiLeaks Cablegate Cables]

                      P Offline
                      P Offline
                      Pete OHanlon
                      wrote on last edited by
                      #17

                      Ah. I see you are applying Huffman's theory of indeterminate coexistence. An interesting theory, but as I only program in L space, completely useless in the 11th dimension. Still, it should suffice in a four dimension Euclidean universe.

                      I'm not a stalker, I just know things. Oh by the way, you're out of milk.

                      Forgive your enemies - it messes with their heads

                      My blog | My articles | MoXAML PowerToys | Onyx

                      1 Reply Last reply
                      0
                      • N Nabawoka

                        thaaanks but the exam ended .. and i will do my best in other exams :D

                        T Offline
                        T Offline
                        TheGreatAndPowerfulOz
                        wrote on last edited by
                        #18

                        just remember: cheaters never prosper, unless you work for WallStreet

                        "If your actions inspire others to dream more, learn more, do more and become more, you are a leader." - John Quincy Adams

                        1 Reply Last reply
                        0
                        • A AspDotNetDev

                          Ah, but you see the nullity array is cancelled out during the substitution phase. It's also important to keep the nullity array to preserve the equation's covariance, otherwise you end up with an unprovable postulate.

                          [WikiLeaks Cablegate Cables]

                          P Offline
                          P Offline
                          PIEBALDconsult
                          wrote on last edited by
                          #19

                          I find that Capo Ferro cancels Agrippa.

                          1 Reply Last reply
                          0
                          • N Nabawoka

                            cheat cheat cheat what i want help from you and you can't help me to depend on my self and i thanxs you i ended the exam and not passed if one can help me in any time not now i will thank him very much

                            F Offline
                            F Offline
                            fjdiewornncalwe
                            wrote on last edited by
                            #20

                            For me, I'm glad you did not pass. As a mentor, I would not want to waste my time interviewing, never mind hiring, someone who wants to cheat on an exam, because these are the same people who will cheat in the workplace and life in general. Sorry if this sounds mean, but you got what you earned.

                            I wasn't, now I am, then I won't be anymore.

                            1 Reply Last reply
                            0
                            • P Pete OHanlon

                              Oh for goodness sake. I didn't expect anybody to actually post the solution here. BTW, it's the log of the inverse cosine otherwise you end up with a nullity array.

                              I'm not a stalker, I just know things. Oh by the way, you're out of milk.

                              Forgive your enemies - it messes with their heads

                              My blog | My articles | MoXAML PowerToys | Onyx

                              T Offline
                              T Offline
                              Thomas Krojer
                              wrote on last edited by
                              #21

                              and don´t forget to XOR the 13th and 17th element of the array

                              I cannot remember: What did I before google?

                              P 1 Reply Last reply
                              0
                              • T Thomas Krojer

                                and don´t forget to XOR the 13th and 17th element of the array

                                I cannot remember: What did I before google?

                                P Offline
                                P Offline
                                Pete OHanlon
                                wrote on last edited by
                                #22

                                Oh. I think we all took that as read.

                                I'm not a stalker, I just know things. Oh by the way, you're out of milk.

                                Forgive your enemies - it messes with their heads

                                My blog | My articles | MoXAML PowerToys | Onyx

                                1 Reply Last reply
                                0
                                Reply
                                • Reply as topic
                                Log in to reply
                                • Oldest to Newest
                                • Newest to Oldest
                                • Most Votes


                                • Login

                                • Don't have an account? Register

                                • Login or register to search.
                                • First post
                                  Last post
                                0
                                • Categories
                                • Recent
                                • Tags
                                • Popular
                                • World
                                • Users
                                • Groups