Char To String & Then Array.

[Mike Certini]

I am currently taking data from a database that is in the form of char data and attempting to convert to a string and then saving in a char array. It appears that these strings have to be saved in a two dimension array. The first array or inner array containing each element of the date in the form of chars. The outer array then contains each record or occurance of the date. Can someone help me in copying the string data into the array? Listed below is what I have so far.

char Date1[10] = {};
vFieldDate = rec->Fields->GetItem("Date")->Value;

for(int r = 0; r < 1; r++)
{
for(int c = 0; c < 10; c++)
{
strcpy (Date1,vFieldDate);
strcpy (Date[r][c],Date1[10]);
printf ("%s",Date[r][c]);
}
}

[Cool_Dev]

Mike Certini wrote:

strcpy (Date[r][c],Date1[10]);

strcpy (Date[r][c],Date1); is correct. Hope you have declared char Date[MAX][10] (where MAX will be greater than or equal to l) , or dynamically allocated memory for it.

[Mike Certini]

Through research the following was derived from an MSDN website:

#define ARR 65500 //Total Records
#define TARGSIZE 11 //Field Length

char Date[ARR][TARGSIZE] = {};

orig = rec->Fields->GetItem("Time")->Value; //ADO Data

// Convert to a char*
const size_t newsize = 100;
char nstring[newsize];
strcpy_s(nstring, (char *)orig); //Typecast & Copy Data Elements
strncpy(Date[cyc],nstring,TARGSIZE - 1);//Copy String To Array
printf("%s",nstring);
printf("\n");

Original MSDN website: http://msdn.microsoft.com/en-us/library/ms235631(v=vs.80).aspx[^]

[Lost User]

Why not:

strncpy(Date[cyc], (char *)orig, TARGSIZE - 1);
// or even (what type is orig?)
strncpy(Date[cyc], (char *)rec->Fields->GetItem("Time")->Value, TARGSIZE - 1);

I must get a clever new signature for 2011.