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Logic

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  • G gumi_r msn com

    Really? And I always thought that '&&' was simply a short-circuited '&'. I must go RTFM. :sigh:

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    0bx
    wrote on last edited by
    #29

    Ha, that's what they taught me as well. It's utter nonsense off course since both '&' and '|' would be completely useless if that was the only difference. It's just that it's a good habit to always use '&&' and '||' unless you need '&' or '|' specifically, even in cases where the result is the same.

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    • L Lost User

      As I have stated in my reply to Fabio, & and && are for different purpose. & is a bitwise operator and && is a logical operator, they may produce same output in certain situations, but it does not mean that you can use them interchangeably. In C#, logical operators always short-circuit. See this link for an example: http://blog.dmbcllc.com/2009/03/16/vs-and-vs-whats-the-difference/[^]

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      gumi_r msn com
      wrote on last edited by
      #30

      The && operator should be used instead of the & operator for clarity's sake because its the standard way of doing things. Also the && operator gives you some type safety that the & operator does not when dealing with LOGICAL ANDS: (4 && 5) will not compile but (4 & 5) will. If you are intending to perform a LOGICAL AND operation you could end up performing a LOGICAL BITWISE AND operation instead by mistake. But in any case, the reason you are giving: "(...)In C#, logical operators always short-circuit(...) is so wrong I dont even know where to begin. The operator & is an overloadable operator. Integral and boolean types have their own predefined & binary operators: &(int, int) computes the logical bitwise AND of its operands while &(bool, bool) computes the logical AND of its operands; that is, the result is true if and only if both its operands are true. This is all straight from the C# specifications:http://msdn.microsoft.com/en-us/library/sbf85k1c.aspx[^] So bool & bool is NOT A BITWISE OPERATION at all. Its a normal LOGICAL AND OPERATION where both terms are always evaluated contrary to bool && bool where the second term is evaluated if and only if the first term is true.

      modified on Thursday, May 19, 2011 5:55 AM

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      • K Keith Barrow

        http://www.codeproject.com/feature/HallOfSHame.aspx?msg=3895520#xx3895520xx[^]

        Sort of a cross between Lawrence of Arabia and Dilbert.[^]
        -Or-
        A Dead ringer for Kate Winslett[^]

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        Lost User
        wrote on last edited by
        #31

        forget it Keith, it's not gonna make any difference, I'm afraid you've just opened a can of worms.

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        • F Fabio V Silva

          Again, what makes you think I don't know the difference between & and &&?! I never said they do the same thing and I do know that && is the most commonly used. That, however, does not make it wrong to use & between two boolean and it does not invalidate the fact that in that case it makes no difference. And if someone says it does then they should RTFM!

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          Nagy Vilmos
          wrote on last edited by
          #32

          Fabio V Silva wrote:

          in that case it makes no difference

          Wrong. Take notes if you like:

          A && B

          In this scenario A is evaluated and if it is true then B is evaluated and that is the result, otherwise the result is false and B never gets evaluated.

          A & B

          Both A and B are evaluated and the values are then combined using a Bitwise And operation, the output of which is cast to a Boolean for the result. At any level, these are two very diferent operations.

          Fabio V Silva wrote:

          And if someone says it does then they should RTFM!

          Manual read and understood, I still says it does.


          Panic, Chaos, Destruction. My work here is done. or "Drink. Get drunk. Fall over." - P O'H OK, I will win to day or my name isn't Ethel Crudacre! - DD Ethel Crudacre Have a bit more patience with newbies. Of course some of them act dumb -- they're often *students*, for heaven's sake. -- (Terry Pratchett, alt.fan.pratchett)

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          • L Lost User

            Your case is an exception, don't treat it like a rule.

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            musefan
            wrote on last edited by
            #33

            So are you admitting you were wrong?

            I may or may not be responsible for my own actions

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            • N Nagy Vilmos

              Fabio V Silva wrote:

              in that case it makes no difference

              Wrong. Take notes if you like:

              A && B

              In this scenario A is evaluated and if it is true then B is evaluated and that is the result, otherwise the result is false and B never gets evaluated.

              A & B

              Both A and B are evaluated and the values are then combined using a Bitwise And operation, the output of which is cast to a Boolean for the result. At any level, these are two very diferent operations.

              Fabio V Silva wrote:

              And if someone says it does then they should RTFM!

              Manual read and understood, I still says it does.


              Panic, Chaos, Destruction. My work here is done. or "Drink. Get drunk. Fall over." - P O'H OK, I will win to day or my name isn't Ethel Crudacre! - DD Ethel Crudacre Have a bit more patience with newbies. Of course some of them act dumb -- they're often *students*, for heaven's sake. -- (Terry Pratchett, alt.fan.pratchett)

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              gumi_r msn com
              wrote on last edited by
              #34

              Jesus, why do people pretend to know the absolute truth about things without even bothering to do some minimal research. What you are stating is completely wrong. The & operator is an OVERLOADABLE operator. As such, it has predefined behaviours for integral types and boolean types. (int & int) IS NOT THE SAME AS bool & bool. The first performs a logical bitwise AND operation while the latter performs a LOGICAL AND operation. There is no bitwise operation at all if the operator is dealing with two booleans. It is exactly the same as bool && bool except that both terms are evaluated no matter what the first expression evaluates to. If you are not convinced then please read the following MSDN C# reference link: http://msdn.microsoft.com/en-us/library/sbf85k1c.aspx[^] or better yet: http://msdn.microsoft.com/en-us/library/2a723cdk.aspx[^]

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              • G gumi_r msn com

                Jesus, why do people pretend to know the absolute truth about things without even bothering to do some minimal research. What you are stating is completely wrong. The & operator is an OVERLOADABLE operator. As such, it has predefined behaviours for integral types and boolean types. (int & int) IS NOT THE SAME AS bool & bool. The first performs a logical bitwise AND operation while the latter performs a LOGICAL AND operation. There is no bitwise operation at all if the operator is dealing with two booleans. It is exactly the same as bool && bool except that both terms are evaluated no matter what the first expression evaluates to. If you are not convinced then please read the following MSDN C# reference link: http://msdn.microsoft.com/en-us/library/sbf85k1c.aspx[^] or better yet: http://msdn.microsoft.com/en-us/library/2a723cdk.aspx[^]

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                _Erik_
                wrote on last edited by
                #35

                Come on, guys. Stop this mess, ok? I don't pretend to know the absolute truth about this but, man, you are wrong or, at least, you might be confusing beginners. The fact that, as you say, "both terms are evaluated no matter what the first expression evaluates to" with the & operator is the key, and it is not a trivial difference. See this example:

                string s = null;
                bool b1 = s != null && s.Length == 0;
                bool b2 = s != null & s.Length == 0;

                You see the operands here are boolean expressions. However, while b1 would be assigned false without any problem, a runtime NullReferenceException would be thrown when trying to assing the value to b2. This is a really important difference. Both operands are not the same and can never be considered as if they were the same. Under some circumstances they can return the same result, yes, but that does not mean that they are exactly the same or that you can use any of them when you use boolean expressions. Can we, please, go on with our lifes now?

                OriginalGriffO 1 Reply Last reply
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                • G gumi_r msn com

                  Jesus, why do people pretend to know the absolute truth about things without even bothering to do some minimal research. What you are stating is completely wrong. The & operator is an OVERLOADABLE operator. As such, it has predefined behaviours for integral types and boolean types. (int & int) IS NOT THE SAME AS bool & bool. The first performs a logical bitwise AND operation while the latter performs a LOGICAL AND operation. There is no bitwise operation at all if the operator is dealing with two booleans. It is exactly the same as bool && bool except that both terms are evaluated no matter what the first expression evaluates to. If you are not convinced then please read the following MSDN C# reference link: http://msdn.microsoft.com/en-us/library/sbf85k1c.aspx[^] or better yet: http://msdn.microsoft.com/en-us/library/2a723cdk.aspx[^]

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                  Nathan D Cook
                  wrote on last edited by
                  #36

                  I'm just a novice programmer and didn't even realize (or I forgot?) that & was a legal command. I've always just used &&. I'm so confused by the last 30 some posts, I'm going to keep it simple and make sure I never use &.

                  OriginalGriffO 1 Reply Last reply
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                  • N Nathan D Cook

                    I'm just a novice programmer and didn't even realize (or I forgot?) that & was a legal command. I've always just used &&. I'm so confused by the last 30 some posts, I'm going to keep it simple and make sure I never use &.

                    OriginalGriffO Offline
                    OriginalGriffO Offline
                    OriginalGriff
                    wrote on last edited by
                    #37

                    Wise decision!

                    Real men don't use instructions. They are only the manufacturers opinion on how to put the thing together. Manfred R. Bihy: "Looks as if OP is learning resistant."

                    "I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
                    "Common sense is so rare these days, it should be classified as a super power" - Random T-shirt

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                    • _ _Erik_

                      Come on, guys. Stop this mess, ok? I don't pretend to know the absolute truth about this but, man, you are wrong or, at least, you might be confusing beginners. The fact that, as you say, "both terms are evaluated no matter what the first expression evaluates to" with the & operator is the key, and it is not a trivial difference. See this example:

                      string s = null;
                      bool b1 = s != null && s.Length == 0;
                      bool b2 = s != null & s.Length == 0;

                      You see the operands here are boolean expressions. However, while b1 would be assigned false without any problem, a runtime NullReferenceException would be thrown when trying to assing the value to b2. This is a really important difference. Both operands are not the same and can never be considered as if they were the same. Under some circumstances they can return the same result, yes, but that does not mean that they are exactly the same or that you can use any of them when you use boolean expressions. Can we, please, go on with our lifes now?

                      OriginalGriffO Offline
                      OriginalGriffO Offline
                      OriginalGriff
                      wrote on last edited by
                      #38

                      Gets my five - nicely argued.

                      Real men don't use instructions. They are only the manufacturers opinion on how to put the thing together. Manfred R. Bihy: "Looks as if OP is learning resistant."

                      "I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
                      "Common sense is so rare these days, it should be classified as a super power" - Random T-shirt

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                      • OriginalGriffO OriginalGriff

                        Wise decision!

                        Real men don't use instructions. They are only the manufacturers opinion on how to put the thing together. Manfred R. Bihy: "Looks as if OP is learning resistant."

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                        Manfred Rudolf Bihy
                        wrote on last edited by
                        #39

                        Agreed! That is of course only if he meant to say: "I'll never use & with boolean operands." :-D

                        OriginalGriffO B 2 Replies Last reply
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                        • A AspDotNetDev

                          This should really mess with your noggin:

                          bool isTrue = true || true && false; // True
                          bool isFalse = true | true && false; // False.

                          Also, given your example, I'd prefer the double ampersand for 2 reasons: 1) for short-circuiting and 2) for standards' sake.

                          [Managing Your JavaScript Library in ASP.NET]

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                          Quirkafleeg
                          wrote on last edited by
                          #40

                          Ahem! The real Hall of Shame is the lack of brackets - pure laziness without realizing a simple misstyping mistiping mistyping can change the behaviour of code. ...most people are not a programming god who knows all precedence rules!

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                          • M Manfred Rudolf Bihy

                            Agreed! That is of course only if he meant to say: "I'll never use & with boolean operands." :-D

                            OriginalGriffO Offline
                            OriginalGriffO Offline
                            OriginalGriff
                            wrote on last edited by
                            #41

                            That's how I read it. :-D

                            Real men don't use instructions. They are only the manufacturers opinion on how to put the thing together. Manfred R. Bihy: "Looks as if OP is learning resistant."

                            "I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
                            "Common sense is so rare these days, it should be classified as a super power" - Random T-shirt

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                            • M Manfred Rudolf Bihy

                              Agreed! That is of course only if he meant to say: "I'll never use & with boolean operands." :-D

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                              BobJanova
                              wrote on last edited by
                              #42

                              Indeed. & and | on ints (or uints) is very useful.

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                              • G gumi_r msn com

                                Jesus, why do people pretend to know the absolute truth about things without even bothering to do some minimal research. What you are stating is completely wrong. The & operator is an OVERLOADABLE operator. As such, it has predefined behaviours for integral types and boolean types. (int & int) IS NOT THE SAME AS bool & bool. The first performs a logical bitwise AND operation while the latter performs a LOGICAL AND operation. There is no bitwise operation at all if the operator is dealing with two booleans. It is exactly the same as bool && bool except that both terms are evaluated no matter what the first expression evaluates to. If you are not convinced then please read the following MSDN C# reference link: http://msdn.microsoft.com/en-us/library/sbf85k1c.aspx[^] or better yet: http://msdn.microsoft.com/en-us/library/2a723cdk.aspx[^]

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                                Nagy Vilmos
                                wrote on last edited by
                                #43

                                Well f. me sideways and call me Dr Dream. You come and tell me that I don't know what I'm saying and immediately say what I said. Bitwise means EVERYTHING is evaluated and then anded ored noted xored and stuck through the mincer. Binary menas once the result is known it stops. I appologise if using technical terms confussed you but that's it.


                                Panic, Chaos, Destruction. My work here is done. or "Drink. Get drunk. Fall over." - P O'H OK, I will win to day or my name isn't Ethel Crudacre! - DD Ethel Crudacre Have a bit more patience with newbies. Of course some of them act dumb -- they're often *students*, for heaven's sake. -- (Terry Pratchett, alt.fan.pratchett)

                                1 Reply Last reply
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                                • F Fabio V Silva

                                  Again, what makes you think I don't know the difference between & and &&?! I never said they do the same thing and I do know that && is the most commonly used. That, however, does not make it wrong to use & between two boolean and it does not invalidate the fact that in that case it makes no difference. And if someone says it does then they should RTFM!

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                                  sucram
                                  wrote on last edited by
                                  #44

                                  Shut the f... up.

                                  Ego non sum semper iustus tamen Ego sum nunquam nefas!

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                                  • F Fabio V Silva

                                    I just got an answer[^] downvoted in Q&A because I used & instead of && in this line:

                                    if(UsernameTextBox.Text == "Manager" & PasswordTextBox.Text == "Maintenance")

                                    I'm still waiting for a response to my "Why?"

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                                    Timothy Byrd
                                    wrote on last edited by
                                    #45

                                    So if I have this straight, in your example:

                                    if(UsernameTextBox.Text == "Manager" & PasswordTextBox.Text == "Maintenance")

                                    because both arguments are boolean, the '&' is effectively acting just like a '&&' except for being trivially less efficient because it is always doing both of the string compares. I know in this case you were merely quoting previous post using '&', but even if the non-short-circuit behaviour would be useful sometime, I'd avoid it because it just looks wrong to me. We're in a mixed C++/C# environment here, and I have to be on the lookout for misused '&'s in the code as it is. Allowing for false positives is not in the cards here. That said, I think you got a raw deal.

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                                    • F Fabio V Silva

                                      I just got an answer[^] downvoted in Q&A because I used & instead of && in this line:

                                      if(UsernameTextBox.Text == "Manager" & PasswordTextBox.Text == "Maintenance")

                                      I'm still waiting for a response to my "Why?"

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                                      Rob Grainger
                                      wrote on last edited by
                                      #46

                                      And quite rightly so. While for booleans, & can work as a logical operator, in all other cases it is bitwise. For consistency, use a single operatopr to represent logical operators throughout, the C# designers (C really) chose && for this purpose. It may work, but its obfuscated, and should be rejected or corrected by any reasonable code review, regardless of any appeals you make to technical documentation.

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                                      • R Rob Grainger

                                        And quite rightly so. While for booleans, & can work as a logical operator, in all other cases it is bitwise. For consistency, use a single operatopr to represent logical operators throughout, the C# designers (C really) chose && for this purpose. It may work, but its obfuscated, and should be rejected or corrected by any reasonable code review, regardless of any appeals you make to technical documentation.

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                                        Timothy Byrd
                                        wrote on last edited by
                                        #47

                                        Rob, I think the problem is that you are assuming human beings are rational/reasonable. Where I am currently, I have to fill out a form and get authorization to fix a simple memory leak. The code base is several million lines of C++, suffering from 20 years of technical debt. Since I already have a reputation for being "too critical about code quality" which causes my input to get knocked down a level or two, I have to bite my tongue a lot. It's a grand learning experience, but I'll be glad when I figure out what the lesson is!

                                        F 1 Reply Last reply
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                                        • T Timothy Byrd

                                          Rob, I think the problem is that you are assuming human beings are rational/reasonable. Where I am currently, I have to fill out a form and get authorization to fix a simple memory leak. The code base is several million lines of C++, suffering from 20 years of technical debt. Since I already have a reputation for being "too critical about code quality" which causes my input to get knocked down a level or two, I have to bite my tongue a lot. It's a grand learning experience, but I'll be glad when I figure out what the lesson is!

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                                          Firo Atrum Ventus
                                          wrote on last edited by
                                          #48

                                          The lesson : Never start a fight in the Hall of Shame :laugh:

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