output format

[wong1907]

hello if "i","j" are double i=1.2345678 j=2.345678 cout<

[Joel Holdsworth]

printf("%.2f\n", i*j);

- I believe that should do the trick!**

With time we live, with money we spend! Joel Holdsworth.

**

[wong1907]

If I prefer use cout rather than printf how can I do??? THX!!!:-D:-D

[Dominik Reichl]

char szTemp[256];
sprintf(szTemp, "%.2f\n", i*j);
cout << szTemp;

:-D -Dominik

[Michael Dunn]

You need to use an iomanip function. Unfortunately the VC 6 STL "documentation" is unhelpful, but something like:

cout << setprecision(2) << i*j;

should work. The horrible docs and the complexity of using iomanips is why printf() is favored for this type of output. ;) --Mike-- If it doesn't move and it should: WD-40. If it moves and it shouldn't: duct tape. 1ClickPicGrabber - Grab & organize pictures from your favorite web pages, with 1 click! My really out-of-date homepage Sonork-100.19012 Acid_Helm

[markkuk]

#include <iostream>
#include <iomanip>

int main(int argc, char* argv[]) {
double i = 1.2345678;
double j = 2.345678;
std::cout << std::fixed << std::setprecision(2)
<< i * j << std::endl;
}

[Nick Parker]

Michael Dunn wrote: You need to use an iomanip function. Unfortunately the VC 6 STL "documentation" is unhelpful I didn't know that the iomanip header file was part of the STL.

---

Nick Parker

You see the Standards change. - Fellow co-worker