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  4. SELECT ... GROUP BY Error

SELECT ... GROUP BY Error

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  • M MikeDhaan

    I have as table like TheDate Type Value I need to retreive the last value for each type. I try a SQL command like SELECT MAX(TheDate), Type, Value from MyTable GROUP BY Type But I receive an error : Erreur SQL : ORA-00979: not a GROUP BY expression 00979. 00000 - "not a GROUP BY expression" Do you have any idea ?

    S Offline
    S Offline
    Simon_Whale
    wrote on last edited by
    #2

    I would try

    SELECT MAX(TheDate), Type, Value
    FROM MyTable
    GROUP BY Type, Value

    Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

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    • S Simon_Whale

      I would try

      SELECT MAX(TheDate), Type, Value
      FROM MyTable
      GROUP BY Type, Value

      Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

      M Offline
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      MikeDhaan
      wrote on last edited by
      #3

      Thanks for the idea, but it's not enought because the values are diffrent. I receive in this case : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/15 , T2 , 10 ... And I only need the last value for T1, T2, ... ! Mike

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      • M MikeDhaan

        Thanks for the idea, but it's not enought because the values are diffrent. I receive in this case : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/15 , T2 , 10 ... And I only need the last value for T1, T2, ... ! Mike

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        Jorgen Andersson
        wrote on last edited by
        #4

        Then you need to remove the Value column from the query.

        SELECT MAX(TheDate), Type
        FROM MyTable
        GROUP BY TYPE

        But then you don't get the value. So join the result from this query with the original table.

        WITH maxdate AS (
        SELECT MAX(TheDate) TheDate, Type
        FROM MyTable
        GROUP BY Type
        )
        SELECT t.TheDate, t.Type, t.Value
        FROM MyTable t join maxdate d
        ON t.TheDate = d.TheDate
        AND t.Type = d.Type

        Light moves faster than sound. That is why some people appear bright, until you hear them speak. List of common misconceptions

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        • M MikeDhaan

          I have as table like TheDate Type Value I need to retreive the last value for each type. I try a SQL command like SELECT MAX(TheDate), Type, Value from MyTable GROUP BY Type But I receive an error : Erreur SQL : ORA-00979: not a GROUP BY expression 00979. 00000 - "not a GROUP BY expression" Do you have any idea ?

          C Offline
          C Offline
          Chris Meech
          wrote on last edited by
          #5

          You first need to find the MAX(TheDate) and then use that to find the Value(s). :)

          select Value
          ,Type
          from TABLE
          where TheDate in ( select MAX(TheDate)
          from Table
          group by Type
          )
          ;

          That's off the top of my head, but should be close. :)

          Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

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          • C Chris Meech

            You first need to find the MAX(TheDate) and then use that to find the Value(s). :)

            select Value
            ,Type
            from TABLE
            where TheDate in ( select MAX(TheDate)
            from Table
            group by Type
            )
            ;

            That's off the top of my head, but should be close. :)

            Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

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            M Offline
            MikeDhaan
            wrote on last edited by
            #6

            OK, but you select the max date and not the max date per type I have several types and I shearch the last value for each type and not the max date per type

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            0
            • M MikeDhaan

              OK, but you select the max date and not the max date per type I have several types and I shearch the last value for each type and not the max date per type

              C Offline
              C Offline
              Chris Meech
              wrote on last edited by
              #7

              MikeDhaan wrote:

              and not the max date per type

              The inner select has a group by type which should produce a list of MAX(dates). :)

              Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

              M 1 Reply Last reply
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              • C Chris Meech

                MikeDhaan wrote:

                and not the max date per type

                The inner select has a group by type which should produce a list of MAX(dates). :)

                Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

                M Offline
                M Offline
                MikeDhaan
                wrote on last edited by
                #8

                Correct but the result with the extract below is not correct. MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/10/10 , T3 , 15 ... The result is : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 :confused: 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/08/15 , T2 , 10 ... Because select MAX(TheDate) from Table group by Type return 2011/09/25 (for T1) 2011/08/11 (for T2) 2011/10/10 (for T3)

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                • M MikeDhaan

                  Thanks for the idea, but it's not enought because the values are diffrent. I receive in this case : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/15 , T2 , 10 ... And I only need the last value for T1, T2, ... ! Mike

                  B Offline
                  B Offline
                  Blue_Boy
                  wrote on last edited by
                  #9

                  Try this query

                  select distinct
                  (select top 1 t2.thedate from MyTable as t2 where t2.[type]=t1.[type] order by t2.thedate desc) as thedate
                  , t1.[type]
                  ,(select top 1 t2.value from MyTable as t2 where t2.[type]=t1.[type] order by t2.thedate desc) as [Value]
                  from MyTable as t1
                  order by t1.[type]


                  I Love T-SQL "VB.NET is developed with C#.NET" If my post helps you kindly save my time by voting my post.

                  1 Reply Last reply
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                  • M MikeDhaan

                    Correct but the result with the extract below is not correct. MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/10/10 , T3 , 15 ... The result is : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 :confused: 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/08/15 , T2 , 10 ... Because select MAX(TheDate) from Table group by Type return 2011/09/25 (for T1) 2011/08/11 (for T2) 2011/10/10 (for T3)

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                    Mycroft Holmes
                    wrote on last edited by
                    #10

                    Do a little research on Row_Number, Partition and Ranking. Using these you can set up an inner query that ranks the records by date partitioned over type. The outer query would then join by date and type where the rank = 1.

                    Never underestimate the power of human stupidity RAH

                    1 Reply Last reply
                    0
                    • J Jorgen Andersson

                      Then you need to remove the Value column from the query.

                      SELECT MAX(TheDate), Type
                      FROM MyTable
                      GROUP BY TYPE

                      But then you don't get the value. So join the result from this query with the original table.

                      WITH maxdate AS (
                      SELECT MAX(TheDate) TheDate, Type
                      FROM MyTable
                      GROUP BY Type
                      )
                      SELECT t.TheDate, t.Type, t.Value
                      FROM MyTable t join maxdate d
                      ON t.TheDate = d.TheDate
                      AND t.Type = d.Type

                      Light moves faster than sound. That is why some people appear bright, until you hear them speak. List of common misconceptions

                      M Offline
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                      MikeDhaan
                      wrote on last edited by
                      #11

                      :thumbsup: Super, It's working ;) Thanks

                      J 2 Replies Last reply
                      0
                      • M MikeDhaan

                        Correct but the result with the extract below is not correct. MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/10/10 , T3 , 15 ... The result is : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 :confused: 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/08/15 , T2 , 10 ... Because select MAX(TheDate) from Table group by Type return 2011/09/25 (for T1) 2011/08/11 (for T2) 2011/10/10 (for T3)

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                        C Offline
                        Chris Meech
                        wrote on last edited by
                        #12

                        Since there are multiple values the same in TheDate column it can not be used as a key and that is why you are getting those results. Another, more complicated way, is to use the date and type as a key. Try this

                        select date
                        ,type
                        ,value
                        from table t
                        , ( select max(date) max_date
                        ,type type
                        from Table
                        group by type
                        ) tg
                        where t.date = tg.max_date
                        and t.type = tg.type
                        order by type
                        ;

                        Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

                        M M 2 Replies Last reply
                        0
                        • C Chris Meech

                          Since there are multiple values the same in TheDate column it can not be used as a key and that is why you are getting those results. Another, more complicated way, is to use the date and type as a key. Try this

                          select date
                          ,type
                          ,value
                          from table t
                          , ( select max(date) max_date
                          ,type type
                          from Table
                          group by type
                          ) tg
                          where t.date = tg.max_date
                          and t.type = tg.type
                          order by type
                          ;

                          Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

                          M Offline
                          M Offline
                          MikeDhaan
                          wrote on last edited by
                          #13

                          :thumbsup: Super, It's now in order ! ;) Thanks

                          1 Reply Last reply
                          0
                          • C Chris Meech

                            Since there are multiple values the same in TheDate column it can not be used as a key and that is why you are getting those results. Another, more complicated way, is to use the date and type as a key. Try this

                            select date
                            ,type
                            ,value
                            from table t
                            , ( select max(date) max_date
                            ,type type
                            from Table
                            group by type
                            ) tg
                            where t.date = tg.max_date
                            and t.type = tg.type
                            order by type
                            ;

                            Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

                            M Offline
                            M Offline
                            Mycroft Holmes
                            wrote on last edited by
                            #14

                            I'm always reluctant to push the partition/rank solution as someone always seems to come up with a simpler answer.

                            Never underestimate the power of human stupidity RAH

                            J 1 Reply Last reply
                            0
                            • M MikeDhaan

                              :thumbsup: Super, It's working ;) Thanks

                              J Offline
                              J Offline
                              Jorgen Andersson
                              wrote on last edited by
                              #15

                              If you get performance issues on this query you will need a composite index on (Type,TheDate)

                              Light moves faster than sound. That is why some people appear bright, until you hear them speak. List of common misconceptions

                              1 Reply Last reply
                              0
                              • M Mycroft Holmes

                                I'm always reluctant to push the partition/rank solution as someone always seems to come up with a simpler answer.

                                Never underestimate the power of human stupidity RAH

                                J Offline
                                J Offline
                                Jorgen Andersson
                                wrote on last edited by
                                #16

                                A partition/rank solution wouldn't need the join and therefore probably performs better. The simplest answer isn't always the best.

                                Light moves faster than sound. That is why some people appear bright, until you hear them speak. List of common misconceptions

                                1 Reply Last reply
                                0
                                • M MikeDhaan

                                  :thumbsup: Super, It's working ;) Thanks

                                  J Offline
                                  J Offline
                                  Jorgen Andersson
                                  wrote on last edited by
                                  #17

                                  Heres a query using Rank as suggested by Mycroft

                                  SELECT TheDate, TYPE, Value
                                  FROM (
                                  SELECT TheDate, Type, Value, Rank( ) OVER (PARTITION BY Type ORDER BY TheDate DESC NULLS LAST) RN
                                  FROM MyTable
                                  )
                                  WHERE RN = 1

                                  Just a bit curious whether performance is better.

                                  Light moves faster than sound. That is why some people appear bright, until you hear them speak. List of common misconceptions

                                  1 Reply Last reply
                                  0
                                  • M MikeDhaan

                                    I have as table like TheDate Type Value I need to retreive the last value for each type. I try a SQL command like SELECT MAX(TheDate), Type, Value from MyTable GROUP BY Type But I receive an error : Erreur SQL : ORA-00979: not a GROUP BY expression 00979. 00000 - "not a GROUP BY expression" Do you have any idea ?

                                    P Offline
                                    P Offline
                                    purnananda behera
                                    wrote on last edited by
                                    #18

                                    SELECT MAX(TheDate), Type, Value FROM MyTable GROUP BY Type, Value

                                    1 Reply Last reply
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