C parsing question

[Software2007]

I know how to do this in C++, but a bit rusty on C,

char line[1024]="d(Text1)b(ID1)n(node1)d(Text2)b(ID2)n(node2)d(Text3)b(ID3)n(node3)...
I would like to parse the line above into item0 = d(Text1)b(ID1)n(node1), item2 - d(Text2)b(ID2)n(node2)... and so forth

char *py;
char *px = line;
while ((py=strstr(px,"d(")) != NULL) {
// if ((px=strstr(py,")")) == NULL)
// printf("error1");
px++;
}

return 0;

Thanks

[PIEBALDconsult]

Because you posted this in the C# forum I assume you mean you want a solution in C#, so I recommend using a Regular Expression. Something like this might be a good start: d\([^)]*\)b\([^)]*\)n\([^)]*\) If not, there is a Regular Expressions forum.

[Software2007]

Sorry, I meant to post it on the C/C++ forum, will post it there. Thanks

[Not Active]

There is only a pound of difference between C and C # :-D

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No comment

[David Skelly]

That's quite a sharp comment, although if you were British you might have made a hash of it.